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Why only \(\Lambda \mathrm{s}^{3+}\) gets precipitated as \(\Lambda \mathrm{s}_{2} \mathrm{~S}_{3}\) not \(\mathrm{Zn}^{2-}\) as \(\mathrm{ZnS}\) when \(\mathrm{II}_{2} \mathrm{~S}\) is passed through an acidic solution containing \(\Lambda s^{3-}\) and \(Z n^{2-}\) ? (1) Solubility product of \(\mathrm{As}_{2} \mathrm{~S}_{3}\) is less than that of \(\mathrm{ZnS}\) (2) Enough As s' are present in the acidic medium (3) Zinc salt does not ionize in the acidic medium (4) Solubility product changes in the presence of an acid

Short Answer

Expert verified
The solubility product of \(\text{As}_2\text{S}_3\) is less than that of \(\text{ZnS}\).

Step by step solution

01

Understand the Problem

Identify why only \(\text{As}^{3+}\) precipitates as \(\text{As}_2\text{S}_3\) and not \(\text{Zn}^{2+}\) as \(\text{ZnS}\) in the given conditions.
02

Solubility Product (Ksp) Concept

Recall that a compound precipitates when the product of the ion concentrations exceeds the solubility product (Ksp) of the compound.
03

Compare Solubility Products

Recognize that \(\text{As}_2\text{S}_3\) has a lower solubility product than \(\text{ZnS}\). This means \(\text{As}_2\text{S}_3\) is less soluble in water than \(\text{ZnS}\). The lower the Ksp, the more likely the compound will precipitate first.
04

Acidic Medium Influence

Note the medium of the solution is acidic. In acidic conditions, the solubility product of compounds can change, but the significant factor here is the difference in Ksp values.
05

Conclude the Right Answer

Based on the above points, the primary reason for \(\text{As}_2\text{S}_3\) precipitating over \(\text{ZnS}\) in acidic conditions is that \(\text{As}_2\text{S}_3\) has a much lower solubility product than \(\text{ZnS}\). Therefore, the correct choice is option (1).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Precipitation Reactions
Precipitation reactions occur when the concentration of ions in a solution exceeds the solubility product, or Ksp, of an insoluble compound. As a result, a solid precipitate forms from the solution. Understanding these reactions is essential in predicting which compounds will form solids under various conditions. For example, if we mix two aqueous solutions containing different ions, a precipitate will form if the product of the ion concentrations exceeds the Ksp value for that particular compound.
Solubility Product Constant (Ksp)
The Solubility Product Constant, commonly known as Ksp, is a crucial concept when studying solubility and precipitation. It provides a measure of the maximum concentration of a salt that can dissolve in water before it precipitates. The lower the Ksp value, the less soluble the compound is in aqueous solutions.
For instance, in our exercise, \(As_2S_3\) has a Ksp value significantly lower than that of \(ZnS\). This means \(As_2S_3\) is much less soluble and will precipitate first when both \(As^{3+}\) and \(Zn^{2+}\) ions are present in the solution.
Acidic Medium Influence
Acidic conditions can affect the solubility of compounds significantly. In an acidic medium, the solubility products of certain salts can either increase or decrease based on the nature of the ions involved. For \(As_2S_3\), the presence of excess protons (\text{H}^+) helps keep the sulfide ions (\text{S}^{2-}) in solution, reducing the formation of \(ZnS\). As such, only \(As_2S_3\) precipitates out.
However, the solubility of \(ZnS\) remains relatively unaffected, and it does not precipitate because its Ksp is relatively higher and the available \(S^{2-}\) ions are insufficient to exceed this threshold under the acidic conditions.

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Most popular questions from this chapter

Hydrochloric acid is a stronger acid than acetic acid because (1) It can neutralize large quantity of alkali. (2) It can corrode anything it comes in contact. (3) It ionizes completely into ions in an aqueous solution. (4) It ionizes partially into ions in aqueous solution.

Which of the following statements is wrong? (1) for an acid buffer solution the \(\mathrm{pH}\) can be increased by inereasing the concentration of salt (2) for a basic buffer solution the pH can increased by decreasing the concentration of base(3) buffer capacity of a buffer solution is maximum when the ratio of salt/acid or base is 1 (4) the number of moles of acid or base required by one litre of buffer solution to alter its \(\mathrm{pH}\) by one unit is called buffer efficiency

The correct statement is (1) \(\mathrm{NII}_{4} \mathrm{Cl}\) gives an alkalinc solution in water (2) \(\mathrm{CII}_{3}\) COONa gives an acidic solution in water (3) \(\mathrm{CII}_{3} \mathrm{COOII}\) is a weak acid (4) \(\mathrm{NII}_{4} \mathrm{OII}\) is a strong base

The \(\mid \mathrm{OH}\) I in \(100 \mathrm{~mL}\) of \(0.015 \mathrm{M} \mathrm{HCl}(\mathrm{aq})\) is (1) \(5 \times 10^{-12} \mathrm{M}\) (2) \(3 \times 10^{-10} \mathrm{M}\) (3) \(6.7 \times 10^{-13} \mathrm{M}\) (4) \(2.0 \times 10^{-9} \mathrm{M}\)

When equal volumes of the following solutions are mixed, precipitation of \(\mathrm{AgCl}\left(K_{\mathrm{pp}}=1.8 \times 10^{10}\right)\) will occur only with (1) \(10^{-4} \mathrm{M}\left(\mathrm{Ag}^{-}\right)\) and \(10^{-4} \mathrm{M}\left(\mathrm{Cl}^{-}\right)\) (2) \(10^{-5} \mathrm{M}\left(\Lambda \mathrm{g}^{-}\right)\) and \(10^{-5} \mathrm{M}\left(\mathrm{Cl}^{-}\right)\) (3) \(10^{-6} \mathrm{M}\left(\Lambda \mathrm{g}^{-}\right)\) and \(10^{-6} \mathrm{M}\left(\mathrm{Cl}^{-}\right)\) (4) \(10^{-10} \mathrm{M}\left(\Lambda \mathrm{g}^{-}\right)\) and \(10^{-10} \mathrm{M}\left(\mathrm{Cl}^{-}\right)\)

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