Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The alkali not suitable for volumctric dctermination of IICl using phenolphthalcin as an indicator (1) \(\mathrm{NaOH}\) (2) \(\mathrm{Ba}(\mathrm{OH})_{2}\) (3) \(\mathrm{KOH}\) (4) \(\mathrm{NH}_{4} \mathrm{OH}\)

Short Answer

Expert verified
NH₄OH

Step by step solution

01

Understand the Question

Identify that the goal is to determine which alkali is not suitable for a volumetric determination of HCl using phenolphthalein as an indicator.
02

Know the Alkalis

Consider the alkalis given: NaOH, Ba(OH)₂, KOH, and NH₄OH. Understand their properties in acidic and basic titration reactions.
03

Indicator Properties

Phenolphthalein changes color in a pH range of approximately 8.2 to 10. It is colorless in acidic solutions and turns pink in basic solutions.
04

Suitability of Each Alkali

Evaluate the suitability of each alkali: 1. NaOH (Strong base, suitable)2. Ba(OH)₂ (Strong base, suitable) 3. KOH (Strong base, suitable) 4. NH₄OH (Weak base, not suitable for phenolphthalein titrations as it doesn't produce a clear endpoint in this pH range)
05

Conclusion

Determine that NH₄OH (ammonium hydroxide) is not suitable for the volumetric determination of HCl using phenolphthalein.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alkali Suitability
In a volumetric determination of hydrochloric acid (HCl) using phenolphthalein as an indicator, it is crucial to choose a suitable alkali. Alkalis are substances that accept protons or donate pairs of electrons. For titration purposes, the nature of the alkali—whether it is a strong or weak base—affects the detection of the endpoint.
Common strong bases include:
  • Sodium hydroxide (NaOH)
  • Barium hydroxide (Ba(OH)₂)
  • Potassium hydroxide (KOH)
Ammonium hydroxide (NH₄OH) is an example of a weak base. The suitability of each alkali for titrating HCl needs to be checked, as it affects the accuracy of the results.
Strong bases fully dissociate in water, providing clear and unambiguous color change with phenolphthalein between pH 8.2 and 10. However, weak bases do not dissociate completely, producing less distinct endpoints. Thus, NH₄OH is not suitable for this titration.
Phenolphthalein Indicator
Phenolphthalein is a common indicator used in acid-base titrations. It is known for its distinct color change, which makes it easy to detect the endpoint of the titration.
Phenolphthalein is colorless in acidic solutions. As the pH of the solution increases and enters the range of 8.2 to 10, phenolphthalein turns pink. This color change indicates that the solution is basic.
When titrating HCl (a strong acid), the chosen alkali needs to provide a clear and sharp color change with phenolphthalein. Strong bases like NaOH, Ba(OH)₂, and KOH ensure that the transition from colorless to pink is noticeable and precise. In contrast, weak bases like NH₄OH do not shift the pH sufficiently to produce a clear indicator response, making them less suitable for this purpose.
Titration Endpoint
The titration endpoint is a crucial moment in a titration, indicating the point at which the reactants have been mixed in the exact stoichiometric proportions. For a titration involving HCl and an alkali using phenolphthalein, the endpoint is usually marked by a permanent color change of the indicator.
To achieve an accurate titration endpoint with phenolphthalein:
  • A strong base should be used to ensure a sharp endpoint.
  • The endpoint is identified when the solution changes from colorless to a faint pink, just as it reaches the pH range of 8.2 to 10.
  • A slow and careful addition of the titrant (the alkali) helps in identifying the precise moment when the endpoint is reached.
Using a weak base like NH₄OH can cause difficulties in precisely identifying the endpoint, as the color change may be weak or non-existent due to insufficient pH change. This makes NH₄OH unsuitable for accurate volumetric determination of HCl using phenolphthalein.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Hydrochloric acid is a stronger acid than acetic acid because (1) It can neutralize large quantity of alkali. (2) It can corrode anything it comes in contact. (3) It ionizes completely into ions in an aqueous solution. (4) It ionizes partially into ions in aqueous solution.

An aqucous solution of hydrogen sulphide shows the cquilibrium \(\mathrm{II}_{2} \mathrm{~S} \rightleftharpoons \mathrm{II}^{-} \mathrm{I} \mathrm{IIS}^{-}\) If dilute hydrochloric acid is added to an aqucous solution of hydrogen sulphide without any change in temperature, then (1) the equilibrium constant will change (2) the concentration of HS will increase (3) the concentration of nondissociated hydrogen sulphide will decrease (4) the concentration of HS will decrease

The hydrogen ion concentration in a solution of weak acid of dissociation constant \(K_{a}\) and concentration \(C\) is nearly equal to (1) \(\sqrt{\frac{K_{\mathrm{u}}}{C}}\) (2) \(\frac{C}{K_{\mathrm{a}}}\) (3) \(K_{\mathrm{a}} \cdot C\) (4) \(\sqrt{K_{\mathrm{a}} \cdot \mathrm{C}}\)

The ionization constant of a base is \(\frac{1}{10} .\) The base is described as (1) Normal base (2) Strong basc (3) Weak base (4) None of these

In a vessel containing \(\mathrm{SO}_{3}, \mathrm{SO}_{2}\) and \(\mathrm{O}_{2}\) at equilibrium some helium gas is introduced so that the total pressure increases while temperature and volume remains constant. According to Le Chatelier's principle, the dissociation of \(\mathrm{SO}_{3}\) (1) increases (2) decreases (3) remains unaltered (4) changes unpredictably

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free