Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A cup of tea placed in the room eventually acquires a room temperature by losing heat. The process may be considered close to (1) cyclic process (2) reversible process (3) isothermal process (4) zeroth law

Short Answer

Expert verified
Zeroth Law

Step by step solution

01

Identify the Nature of the Process

We are given a scenario where a cup of tea loses heat to eventually match the room temperature. Understanding the nature of the process is critical here.
02

Evaluate the Cyclic Process

A cyclic process is one where the system returns to its initial state after completing a cycle. In this case, the cup of tea does not return to its initial state after losing heat, so this cannot be classified as a cyclic process.
03

Evaluate the Reversible Process

A reversible process means the system can return to its initial state with no entropy change in the overall system. Losing heat to the room irreversibly increases the entropy, hence this is not a reversible process.
04

Evaluate the Isothermal Process

An isothermal process involves the system remaining at the same temperature. Since the cup of tea starts at a higher temperature and gradually cools to room temperature, it is not an isothermal process.
05

Evaluate the Zeroth Law

The Zeroth Law of Thermodynamics states that when two systems are each in thermal equilibrium with a third system, they are in thermal equilibrium with each other. The cup of tea reaching thermal equilibrium with the room temperature is an illustration of this law in action.
06

Conclusion

Given the options and the reasoning, the cup of tea cooling down to room temperature can best be associated with the Zeroth Law of Thermodynamics.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

cyclic process
A cyclic process is a series of thermodynamic steps that return a system to its original state. Think of an engine, where the working fluid undergoes various transformations, but ultimately, it returns to its initial conditions. In these processes, which often involve changes in pressure, volume, and temperature, the key feature is repeatability. Systems undergo sequential states but come back to the starting point, allowing the cycle to repeat.

However, in the case of the cooling tea, the system (tea) isn't returning to its original hot state after reaching room temperature. Instead, the tea progressively loses heat and settles at room temperature, making it a non-cyclic process.
reversible process
A reversible process is one in which the system and its surroundings can be restored to their initial states with no net change in entropy. These processes are idealized and occur infinitely slowly to ensure equilibrium at every stage.

Consider a piston with gas inside, slowly compressing and decompressing without generating extra heat or causing irreversible changes.

When a cup of tea cools to room temperature, it loses heat irreversibly, usually accompanied by entropy increase in the surroundings. For an everyday scenario, especially with heat transfer to the environment, the process tends to be irreversible, explaining why cooling tea isn't reversible.
isothermal process
An isothermal process maintains a constant temperature throughout the system's transformation. This kind of process often happens when the system is in perfect thermal contact with an external reservoir, exchanging heat precisely to keep the temperature steady.

For example, when a gas expands or contracts while maintaining a steady temperature by absorbing or releasing heat to the surroundings, it undergoes an isothermal transformation. On the contrary, when tea loses heat and cools to match room temperature, the temperature of the tea decreases steadily. Thus, it is not isothermal.
zeroth law of thermodynamics
The Zeroth Law of Thermodynamics establishes the basis for measuring temperature. It states that if two systems are each in thermal equilibrium with a third system, they are also in thermal equilibrium with each other.

In simpler terms, if object A is in thermal equilibrium with object B, and object B is in thermal equilibrium with object C, then object A and object C are in thermal equilibrium. In the context of our exercise, the cup of tea reaches thermal equilibrium with the room's air. This gradual heat transfer until both have the same temperature illustrates the Zeroth Law in action.

By this process, we understand why the cup of tea achieving room temperature is associated with the Zeroth Law of Thermodynamics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One mole of an ideal gas is \(25^{\circ} \mathrm{C}\) is subjected to expand reversibly 10 times of its initial volume. The change in cntropy of expansion is (1) \(19.15 \mathrm{Jk}^{-1} \mathrm{~mol}^{-1}\) (2) \(16.15 \mathrm{Jk}^{-1} \mathrm{~mol}^{-1}\) (3) \(22.15 \mathrm{Jk}^{-1} \mathrm{~mol}^{-1}\) (4) \(11.25 \mathrm{Jk}^{-1} \mathrm{~mol}^{-1}\)

\(\Delta / I\) for the transition of carbon in the diamond form to carbon in the graphite form is \(-453.5 \mathrm{cal}\). This suggests that (1) Graphite is chemically different from diamond. (2) Graphite is as stable as diamond. (3) Graphite is more stable than diamond. (4) Diamond is more stable than graphite.

The wrong statement among the following is (1) The heat change for the reaction \(\mathrm{II}_{2} \mathrm{O}(1) \rightarrow\) \(\mathrm{II}_{2} \mathrm{O}(\mathrm{g})\) is known as heat of vapourisation. (2) The heat change in the reaction \(\mathrm{C}(\mathrm{s})+2 \mathrm{~S}(\mathrm{~s}) \rightarrow\) \(\mathrm{CS}_{2}\) (1) is called heat of formation of \(\mathrm{CS}_{2}\). (3) The standard heat cnthalpy of diamond is zero. (4) The enthalpy change \(\mathrm{C}_{(\mathrm{s})} \rightarrow \mathrm{C}_{(\mathrm{g})}\) is known as cnthalpy of sublimation.

Hess's law of heat summation is an application of (1) Entropy (2) Kirchoff's law (3) First law of thermodynamics (4) Sccond law of thermodynamics

The law of conscrvation of energy states that (1) the internal energy of a system is constant (2) the heat content of the system is constant (3) cnergy is neither created nor destroyed (4) there is an equivalence between energy and mass

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free