Chapter 5: Problem 65
It is desired to increase the volume of 800 cc of a gas by \(20 \%\) keeping the pressure constant. To what temperature the gas be heated, if the initial temperature is \(22^{\circ} \mathrm{C}\) ? (1) \(360^{\circ} \mathrm{C}\) (2) \(87 \mathrm{~K}\) (3) \(454 \mathrm{~K}\) (4) \(81^{\circ} \mathrm{C}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Charles's Law
In our problem, we used Charles's Law to determine the new temperature required to increase the gas volume by 20%. When applying Charles's Law, be sure to always use the absolute temperature (measured in Kelvin) for calculations.
Gas Volume Expansion
Consider our example: the volume of gas increases from 800 cc to 960 cc when heated. Here’s how we calculated it:
- We started with an initial volume, \(V1 = 800 \text{cc}\).
- We wanted to increase this by 20%, so we computed the final volume \ V2 = V1 + \frac{20}{100} \times V1 = 960 cc.
Understanding how gases expand with temperature changes is crucial in various fields, from weather prediction to engineering applications.
Temperature Conversion
To convert Celsius to Kelvin, simply add 273.15 to the Celsius temperature:
- \(T \text{(K)} = T \text{(°C)} + 273.15\).
In our exercise, we converted the initial temperature from 22°C to Kelvin:
- \(T1 = 22^{\text{°C}} = 22 + 273 = 295 \text{K}\).
After finding the final temperature in Kelvin, we converted it back to Celsius:
- \(T2 = 354 \text{K} - 273 = 81^{\text{°C}}\).
Understanding and accurately converting temperatures is key to solving problems involving gas laws efficiently.