Chapter 5: Problem 60
The temperature of 20 litres of nitrogen was increased from \(100 \mathrm{~K}\) to \(300 \mathrm{~K}\) at constant pressure. Change in volume will be (1) 80 litres (2) 60 litres (3) 40 litres (4) 20 litres
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Charles's Law
The formula for Charles's Law is: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]
Here,
- \(V_1\) represents the initial volume of the gas,
- \(T_1\) represents the initial temperature,
- \(V_2\) represents the final volume of the gas, and
- \(T_2\) represents the final temperature.
Temperature-Volume Relationship
For instance, if you have 20 liters of nitrogen gas at a temperature of 100 K and you heat it up to 300 K, the volume will increase. The steps to calculate the new volume are:
1. Identify the initial volume (\(V_1\)) and temperatures (\(T_1\) and \(T_2\)).
2. Use the Charles's Law formula to solve for the final volume (\(V_2\)).
Using the formula: \(V_2 = V_1 \times (T_2/T_1)\),
Substituting the known values: \(V_2 = 20 \times (300/100) = 60 \text{ liters} \).
This means that the gas expands to 60 liters when the temperature is increased from 100 K to 300 K.
Ideal Gas Law
- \(P\) represents the pressure,
- \(V\) represents the volume,
- \(n\) represents the number of moles of the gas,
- \(R\) is the gas constant, and
- \(T\) represents the temperature in Kelvin.
While Charles's Law focuses specifically on the temperature-volume relationship at constant pressure, the ideal gas law is broader. It also takes into account changes in pressure and the amount of gas. Understanding the ideal gas law helps in predicting how a gas will respond to various changes in temperature, volume, or pressure.
In the example problem, only Charles's Law is directly applicable because pressure remains constant while temperature and volume change.