Chapter 5: Problem 57
One litre of a gas collected at NTP will occupy ..... litre at 2 atm pressure and \(27^{\circ} \mathrm{C}\) (1) \(\frac{300}{2 \times 273}\) litre (2) \(\frac{2 \times 300}{273}\) litre (3) \(\frac{273}{2 \times 300}\) litre (4) \(\frac{2 \times 273}{300}\) litre
Short Answer
Expert verified
Option 1: \( \frac{300}{2 \times 273} \) litre
Step by step solution
01
Recall Ideal Gas Law
The ideal gas law is given by\[PV = nRT\]. This will help to understand the relations between pressure, volume, and temperature.
02
Understand NTP conditions
At NTP (Normal Temperature and Pressure), the conditions are: Pressure \(P_1 = 1\) atm, Temperature \(T_1 = 273\) K, and Volume \(V_1 = 1\) litre.
03
Note the given conditions
The gas is now at a pressure \(P_2 = 2\) atm and temperature \(T_2 = 27^{\text{o}} \text{C} = 300\text{K}\). We need to find the new volume \(V_2\)
04
Apply combined gas law
Use the combined gas law which relates initial and final states of a gas:\[\frac{P_1}{T_1} \frac{V_1}{n} = \frac{P_2}{T_2} \frac{V_2}{n} \]. Since the amount of gas \(n\) remains constant, the formula simplifies to \(\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}\).
05
Insert known values
Insert the known values into the simplified equation:\[\frac{1 \times 1}{273} = \frac{2 \times V_2}{300}\].
06
Solve for the new volume
Solve for \(V_2\) to find the new volume:\[V_2 = \frac{300}{2 \times 273} = \frac{300}{546} \text{ litres}\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
The Ideal Gas Law is crucial for understanding how gases behave under different conditions. It's represented by the equation \(PV = nRT\), where:
- **P** is the pressure of the gas.
- **V** is the volume.
- **n** is the number of moles of gas.
- **R** is the gas constant.
- **T** is the temperature in Kelvin.
Combined Gas Law
The Combined Gas Law merges Boyle's Law, Charles's Law, and Gay-Lussac's Law to relate the pressure, volume, and temperature of a gas. It's expressed as \(\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}\). This formula is useful in solving the given problem because it allows us to compare two different sets of pressure, volume, and temperature conditions. Here's how to use it:
- Start by identifying your initial and final conditions (\(P_1, V_1, T_1\) and \(P_2, V_2, T_2\)).
- Plug these values into the equation and solve for the unknown variable, which in our case is the final volume \(V_2\).
Normal Temperature and Pressure (NTP)
Normal Temperature and Pressure, or NTP, is a standard set of conditions used in various scientific calculations. At NTP, the conditions are defined as:
- Pressure, \(P_1 = 1 \text{ atm}\).
- Temperature, \(T_1 = 273 \text{ K}\).
- Often, the volume of one mole of an ideal gas is considered to be 22.4 liters.
Volume and Pressure Relationship
The relationship between volume and pressure in gases is described by Boyle's Law. This law states that the volume of a gas is inversely proportional to its pressure when temperature is constant, written as \(P_1 V_1 = P_2 V_2\). This means:
- If the pressure increases, the volume will decrease, provided the temperature remains the same.
- Similarly, if the pressure decreases, the volume will increase.