Chapter 5: Problem 2
A closed flask contains water in all its three states: solid, liquid and vapour at \(0^{\circ} \mathrm{C} .\) In this situation the average kinetic energy of the water molecule will be (1) The greater in the vapour state (2) The same in the three states (3) The greatest in the solid state (4) Greater in the liquid than in the vapour state
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Phases of Water
In the solid phase (ice), water molecules are held in a rigid structure with minimal movement. This gives ice its solid shape and structure.
In the liquid phase, water molecules are more loosely packed. They can slide past one another, allowing water to flow and take the shape of its container.
In the gas phase (vapor), water molecules are much farther apart and move freely, filling the entire volume of their container. Understanding these phases is crucial when discussing kinetic energy and temperature’s impact on water.
Average Kinetic Energy
\[ \text{KE}_{avg} = \frac{3}{2} k_B T \]
where \(k_B\) is the Boltzmann constant, and \(T\) is the temperature in Kelvin. Thus, if the temperature is the same, molecules in different phases have the same average kinetic energy. This is why, in the exercise, the water molecules in solid, liquid, and vapor phases at 0°C have the same average kinetic energy, despite being in different phases.
Temperature Dependence
The relationship between temperature and kinetic energy is foundational in understanding physical changes and thermodynamic processes in substances like water.