Chapter 4: Problem 49
The geometrical arrangement and shape of \(\mathrm{I}_{3}\) are respectively (1) trigonal bipyramidal geometry, linear shape (2) hexagonal geometry, T-shape (3) triangular planar geometry, pyramidal shape (4) tetrahedral geometry, pyramidal shape
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
triiodide ion
valence electrons
- Iodine has 7 valence electrons per atom.
- Three iodine atoms yield \(7 \times 3 = 21\) valence electrons.
- Adding one extra electron for the negative charge gives a total of 22 valence electrons.
Lewis structure
- Arrange three iodine atoms in a linear formation.
- Connect the central iodine atom to the two outer iodine atoms with single bonds.
- Distribute the remaining electrons to satisfy the octet rule.
VSEPR theory
- The central iodine in \(\mathrm{I}_{3}^{-}\) has 5 electron pairs: 2 bonding pairs and 3 lone pairs.
- The electron pairs arrange themselves in a trigonal bipyramidal geometry to minimize repulsion.
- The 3 lone pairs occupy the equatorial positions.
- The 2 bonding pairs take the axial positions.