Chapter 4: Problem 182
\(\mathrm{H}_{2} \mathrm{O}\) has net dipole moment while \(\mathrm{BeF}_{2}\) has zero dipole moment because (1) \(\mathrm{H}_{2} \mathrm{O}\) molecule is linear while \(\mathrm{Be} \mathrm{F}_{2}\) is bent (2) \(\mathrm{BeF}_{2}\) molecule is linear while \(\mathrm{H}_{2} \mathrm{O}\) is bent (3) Fluorine is more electronegative than oxygen (4) Be is more electronegative than oxygen
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Geometry
For instance, \(\text{H}_2\text{O}\) (water) has a bent or V-shaped structure. This happens because the oxygen atom has two lone pairs of electrons. These lone pairs repel each other and push the hydrogen atoms closer together, creating a bent shape.
On the other hand, \(\text{BeF}_2\) (beryllium fluoride) has a linear structure. Beryllium, the central atom, forms two bonds with fluorine atoms and doesn't have any lone pairs. This linear geometry leads to the two \(\text{Be-F}\) bonds being opposite each other, which affects the overall dipole moment of the molecule.
Electronegativity
In \(\text{H}_2\text{O}\), oxygen is more electronegative than hydrogen. This causes the shared electrons in the \(\text{O-H}\) bonds to be drawn more towards oxygen, creating partial negative and positive charges. These differences lead to an uneven distribution of electron density, contributing to the net dipole moment of water.
For \(\text{BeF}_2\), fluorine is more electronegative than beryllium. In a linear \(\text{BeF}_2\) molecule, these electronegativity differences cause dipole moments in opposite directions. However, the symmetrical linear structure ensures that the individual dipole moments cancel each other out, resulting in no net dipole moment.
Dipole Moment
The magnitude of a dipole moment depends on two factors: the difference in electronegativity between the atoms and the distance between them.
In \(\text{H}_2\text{O}\), the bent geometry causes the individual bond dipoles to add up, creating a net dipole moment. This is why water can dissolve many substances and exhibits unique chemical behaviors.
Conversely, in \(\text{BeF}_2\), the linear geometry ensures that the individual bond dipoles cancel each other out. Despite the high electronegativity difference between beryllium and fluorine, the cancelation of dipoles results in a dipole moment of zero, making \(\text{BeF}_2\) nonpolar.