Chapter 3: Problem 83
The electronegativity of the following elements increases in the order (1) \(\mathrm{C}, \mathrm{N}, \mathrm{S} i, \mathrm{P}\) (2) \(\mathrm{N}, \mathrm{Si}, \mathrm{C}, \mathrm{P}\) (3) \(\mathrm{Si}, \mathrm{P}, \mathrm{C}, \mathrm{N}\) (4) \(\mathrm{P}, \mathrm{Si}, \mathrm{N}, \mathrm{C}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Periodic Trends
For example:
- Fluorine, the most electronegative element, is located on the upper right corner of the periodic table.
- Lithium, which has a comparatively low electronegativity, is found on the bottom left.
Covalent Bonds
If the difference in electronegativity between the two atoms is significant, the bond becomes polar covalent, meaning electrons are not shared equally. For instance:
- In a water molecule (H₂O), oxygen is more electronegative than hydrogen, creating a polar bond where electrons spend more time closer to the oxygen.
Chemical Properties
Here are key points:
- Electronegativity can predict the type of bonding (ionic, covalent) that will occur between elements.
- It also helps in determining molecular polarity and reactivity.
Periodic Table
Here are some critical aspects:
- Elements in the same group (vertical columns) have similar chemical properties, including trends in electronegativity.
- Periods (horizontal rows) show a progressive change in properties, including increasing electronegativity from left to right.