Chapter 3: Problem 72
The false statement among the following is (1) Electron affinity of noble gases is almost zero. (2) The halogen with highest electron affinity is fluorine. (3) Electron affinity values are obtained indirectly by Born-Haber Cycle. (4) lonisation potential of Na would be numerically the same as electron affinity of \(\mathrm{Na}^{+}\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
noble gases electron affinity
Because of their full outer shell, the energy required to add an electron is very high, which means it is energetically unfavorable. Hence, their electron affinity values are almost zero. This stability is why noble gases are often found in their elemental form in nature.
halogen electron affinity
Among the halogens, chlorine actually has the highest electron affinity, not fluorine. This might sound surprising because fluorine is the most electronegative element. However, the small size of fluorine leads to significant electron-electron repulsion when it gains an extra electron. This repulsion reduces the energy released compared to chlorine, which has a larger size and less repulsion.
Born-Haber Cycle
By using Hess’s law, the cycle relates the lattice energy of an ionic crystal to the enthalpy changes involved, such as ionization energies, electron affinities, and sublimation energies. Therefore, electron affinity values can indeed be obtained indirectly through the Born-Haber Cycle.
ionisation potential
Interestingly, the electron affinity of Na+ (the energy change when an electron is added to Na+) is numerically equal to the ionization potential of the neutral Na atom. This is because both processes involve moving an electron between the same two states, just in opposite directions.