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Which one of the following indicates the correct order of atomic size? (1) \(\mathrm{Be}>\mathrm{F}>\mathrm{C}>\mathrm{Ne}\) (2) \(\mathrm{Be}\mathrm{C}>\mathrm{F}<\mathrm{Ne}\) (4) \(F

Short Answer

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Option 3: Be > C > F < Ne

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01

- Understand Atomic Size

Atomic size refers to the distance from the nucleus to the outermost electrons of an atom. Generally, atomic size decreases from left to right across a period due to increasing nuclear charge, which pulls electrons closer to the nucleus.
02

- Assess Elements' Positions in the Periodic Table

Locate the elements mentioned in the options: - Beryllium (Be) is in Group 2, Period 2.- Fluorine (F) is in Group 17, Period 2.- Carbon (C) is in Group 14, Period 2.- Neon (Ne) is in Group 18, Period 2.
03

- Determine the Trend in Period 2

In Period 2, as we move from left (Be) to right (Ne), atomic size decreases. Therefore, the correct decreasing order of atomic size within these elements should start with Be (largest) and end with Ne (smallest).
04

- Compare with Given Options

Compare this trend with the options provided:1) Be > F > C > Ne2) Be < C < F < Ne3) Be > C > F < Ne4) F < Ne < Be < CThe correct order Be > C > F > Ne matches with option 3.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Size Trend
The concept of atomic size, also known as atomic radius, is essential for understanding how different elements compare to each other. Atomic size refers to the distance between the nucleus of an atom and its outermost electron. This size can vary due to several factors, chief among them being the element's position on the periodic table.
As we move from left to right across a period, the atomic size decreases. This occurs because each additional proton in the nucleus exerts a stronger positive charge. This 'nuclear charge' pulls the electrons closer, making the atom smaller. Thus, in a single period, elements on the left side (like Beryllium) will have a larger atomic size compared to elements on the right side (like Neon).
Understanding this trend helps predict how atoms behave in chemical reactions and bonds.
Periodic Table
The periodic table is an organized way to display all known elements. It arranges elements by increasing atomic number and groups them based on similar chemical properties. The table is crucial for predicting atomic size and understanding atomic trends.
Here's a closer look at where our specific elements lie:
  • Beryllium (Be) is in Group 2, Period 2.
  • Carbon (C) is in Group 14, Period 2.
  • Fluorine (F) is in Group 17, Period 2.
  • Neon (Ne) is in Group 18, Period 2.
It's clear from these positions that all these elements fall within the same period (Period 2), meaning they have the same number of electron shells. However, their atomic size varies based on their nuclear charge, which increases as we move across the period from left to right.
Nuclear Charge
Nuclear charge is the total charge of all the protons in the nucleus of an atom. This charge directly impacts the atomic size. In essence, a higher nuclear charge means a stronger pull on the electrons, reducing the atomic radius.
In Period 2 of the periodic table: Beryllium (with 4 protons) has a smaller nuclear charge compared to Neon (with 10 protons). This difference in nuclear charge affects the atomic size significantly, resulting in Be having a larger atomic size than Ne.
When comparing elements within the same period, like Be, C, F, and Ne, the atomic size order can be deduced by understanding their increasing nuclear charge. Therefore, the atomic size decreases as you move from Be to Ne: Be > C > F > Ne.

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Most popular questions from this chapter

The first ionisation energy of sodium is \(500 \mathrm{KJ} \mathrm{mol} !\) This denotes the energy (1) Given out when 1 mole of sodium atoms dissolve in water to form sodium ions (2) Required to remove one electrons to infinity from one atom of sodium (3) Required to raise the electrons in one mole of gascous sodium atoms to a higher energy level (4) Required to change one mole of gascous sodium atoms into gascous ions \(\left(\mathrm{Na}^{\prime}\right)\)

The statement that is not correct for the periodic classification of elements is (1) The properties of elements are the periodic functions of their outer electronic configurations. (2) Non-metallic elements arc lesser in number than metallic elements. (3) For transition elements the d-subshells are filled with electrons monotonically with increase in atomic number. (4) In the periodic table metallic elements appear in the right-hand columns.

Which of the following statement is wrong? (1) Transition elements lie between III and IV groups in the periodic table. (2) Transition elements are those which contain incomplete d-orbital. (3) The 14 elements placed in the 3rd group and 6 th period of the periodic table are known as rare earths. (4) The clement californium belongs to actinide series.

The valency shell of an clement \(\Lambda\) contains 3 electrons while the valence shell of another clement \(B\) contains 6 electrons. If \(\Lambda\) combines with \(\mathrm{B}\), the probable formula of the compound formed will be (1) \(\Lambda \mathrm{B}_{2}\) (2) \(\Lambda_{2} B\) (3) \(\mathrm{A}_{2} \mathrm{~B}_{3}\) (4) \(\Lambda_{3} B_{2}\)

Which of the series of elements listed below would have nearly same atomic radii (1) \(\mathrm{F}, \mathrm{Cl}, \mathrm{Br}, \mathrm{I}\) (2) \(\mathrm{Na}, \mathrm{K}, \mathrm{Rb}, \mathrm{Cs}\) (3) \(\mathrm{Li}, \mathrm{Be}, \mathrm{B}, \mathrm{C}\) (4) \(\mathrm{Fe}, \mathrm{Co}, \mathrm{Ni}, \mathrm{Cu}\)

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