Chapter 3: Problem 44
Which one of the following indicates the correct order of atomic size?
(1) \(\mathrm{Be}>\mathrm{F}>\mathrm{C}>\mathrm{Ne}\)
(2) \(\mathrm{Be}
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Atomic Size Trend
As we move from left to right across a period, the atomic size decreases. This occurs because each additional proton in the nucleus exerts a stronger positive charge. This 'nuclear charge' pulls the electrons closer, making the atom smaller. Thus, in a single period, elements on the left side (like Beryllium) will have a larger atomic size compared to elements on the right side (like Neon).
Understanding this trend helps predict how atoms behave in chemical reactions and bonds.
Periodic Table
Here's a closer look at where our specific elements lie:
- Beryllium (Be) is in Group 2, Period 2.
- Carbon (C) is in Group 14, Period 2.
- Fluorine (F) is in Group 17, Period 2.
- Neon (Ne) is in Group 18, Period 2.
Nuclear Charge
In Period 2 of the periodic table: Beryllium (with 4 protons) has a smaller nuclear charge compared to Neon (with 10 protons). This difference in nuclear charge affects the atomic size significantly, resulting in Be having a larger atomic size than Ne.
When comparing elements within the same period, like Be, C, F, and Ne, the atomic size order can be deduced by understanding their increasing nuclear charge. Therefore, the atomic size decreases as you move from Be to Ne: Be > C > F > Ne.