Chapter 3: Problem 43
Which of the series of elements listed below would have nearly same atomic radii (1) \(\mathrm{F}, \mathrm{Cl}, \mathrm{Br}, \mathrm{I}\) (2) \(\mathrm{Na}, \mathrm{K}, \mathrm{Rb}, \mathrm{Cs}\) (3) \(\mathrm{Li}, \mathrm{Be}, \mathrm{B}, \mathrm{C}\) (4) \(\mathrm{Fe}, \mathrm{Co}, \mathrm{Ni}, \mathrm{Cu}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Periodic Table Trends
- Atomic radius increases as we move down a group (or column) in the periodic table because each element down a group has an additional electron shell, increasing the size.
- Atomic radius decreases as we move from left to right across a period (or row). This is due to the increasing positive charge in the nucleus, which pulls electrons closer, decreasing the size.
Transition Metals
- The additional electrons go into the inner d-subshell, rather than the outer valence shell. This results in a weaker impact on the overall size of the atom.
- The effective nuclear charge is somewhat balanced by the electron shielding from these inner d-electrons, making the change in atomic radius less pronounced than in s- or p-block elements.
Electron Shielding
- As the number of inner electron shells increases in an atom, the outermost electrons experience less nuclear attraction. This increases the atomic radius.
- In transition metals, the d-electrons provide significant shielding, which stabilizes the size of the atom even when nuclear charge increases across the period.