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Which relation represent the correct relationship of the radius of an atom, its cation and its anion? (1) atom = cation \(=\) anion (2) atom \(>\) cation \(>\) anion (3) atom \(>\) cation \(<\) anion (4) atom \(<\) cation \(>\) anion

Short Answer

Expert verified
Option (3): atom > cation < anion.

Step by step solution

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01

Understand Atomic and Ionic Radii

An atom's radius is the distance from its nucleus to the outermost electron shell. Cations are positively charged ions formed by the loss of electrons, leading to a decrease in the radius. Anions are negatively charged ions formed by the gain of electrons, which increases the radius.
02

Relate Atomic Radius to Cation Radius

Since a cation is formed by losing one or more electrons, the electron cloud shrinks, reducing the atomic radius. Consequently, the radius of a cation is smaller than that of the neutral atom.
03

Relate Atomic Radius to Anion Radius

An anion is formed by gaining one or more electrons, causing the electron cloud to expand due to increased electron-electron repulsion. Thus, the radius of an anion is larger than that of the neutral atom.
04

Compare Radii of Atom, Cation, and Anion

Based on the steps above, we find the relationship: Atom radius is larger than cation radius, which in turn is smaller than anion radius. This implies: atom > cation < anion, matching option (3).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Radius
The atomic radius is a fundamental concept in chemistry that measures the size of an atom. It is the distance from the nucleus to the outermost electron shell. The larger the atomic radius, the bigger the atom.
Atoms in the same group of the periodic table show an increase in atomic radius down the group. This happens because each successive element has an additional electron shell. This increased distance results in a larger atomic radius.
On the other hand, atoms within a period show a decrease in atomic radius from left to right. As you move across a period, the number of protons in the nucleus increases. This higher positive charge pulls the electron cloud closer to the nucleus, decreasing the atomic radius.
  • Summary:
    - Distance from the nucleus to the outermost shell.
    - Increases down a group.
    - Decreases across a period.
Cation Radius
A cation is an ion with a positive charge, formed when an atom loses one or more electrons. This loss of electrons results in a smaller radius compared to the neutral atom. The decrease in radius happens because the removal of electrons reduces electron-electron repulsion in the electron cloud.
Also, the remaining electrons are pulled closer to the nucleus due to the unbalanced positive charge, shrinking the electron cloud even more.
For example, when a neutral sodium atom (Na) loses one electron to form a cation (Na+), the atomic radius becomes smaller.
  • Summary:
    - Formed by losing electrons.
    - Smaller radius compared to the neutral atom.
    - Reduced electron cloud due to less electron-electron repulsion.
Anion Radius
An anion is an ion with a negative charge, formed when an atom gains one or more electrons. This gain of electrons results in a larger radius compared to the neutral atom. The increase in radius happens because the additional electrons increase electron-electron repulsion in the electron cloud.
The increased repulsion forces the electron cloud to expand, making the anion larger than its neutral counterpart.
For instance, when a neutral chlorine atom (Cl) gains one electron to become an anion (Cl-), the atomic radius increases.
  • Summary:
    - Formed by gaining electrons.
    - Larger radius compared to the neutral atom.
    - Expanded electron cloud due to increased electron-electron repulsion.

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Most popular questions from this chapter

The wrong statement among the following is (1) The element with outer electronic configuration \(n s^{2} n p^{5}\) is more electronegative. (2) The units of electronegativity are eV. (3) The element with higher electronegativity value may act as an oxidising agent. (4) The atom of an electronegative element becomes an ion by gaining electrons.

The element with electronic configuration \(1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6}\) \(3 \mathrm{~s}^{2}\) is (1) metalloid (2) metal (3) noblc gas (4) non-mctal

Cerium \((Z=58)\) is a member of (1) s-block elements (2) p-block elements (3) d-block elements (4) f-block elements

Which of the following statement is false? (1) The group in which all the elements do not have same number of valence electrons is zero. (2) Elements of II period elements are collectively called as bridge elements. (3) The cause of periodicity of properties is reoccurrence of similar outer electronic configuration. (4) The most reactive gaseous element in the second period is oxygen.

Which of the following statement is wrong? (1) In the sixth period the orbitals being filled arc \(6 \mathrm{~s}\), \(4 \mathrm{f}, 5 \mathrm{~d}\), and \(6 \mathrm{p}\). (2) All the elements in a group in the periodic table have the same number of electrons in the outer most shell of their atoms. (3) Periodicity in the properties of elements when elements are arranged in increasing order of their atomic weights is that elements with similar nature repeat after certain fixed interval. (4) The last member in each period of the periodic table is an inert gas.

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