Chapter 20: Problem 62
Which of following reacts slower than benzene in electrophilic substitution? (1) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}\) (2) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}\) (3) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\) (4) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Donating Groups (EDGs)
Electron Withdrawing Groups (EWGs)
Benzene Derivatives Reaction Rates
- Compounds like \(\text{C}_{6} \text{H}_{5} \text{CH}_{3}\) (with a methyl group) react faster than benzene due to the electron-donating nature of the methyl group.
- Compounds like \(\text{C}_{6} \text{H}_{5} \text{NO}_{2}\) (with a nitro group) react slower than benzene because the nitro group is a strong EWG.
- Hydroxyl and amino groups, as seen in \(\text{C}_{6} \text{H}_{5} \text{OH}\) and \(\text{C}_{6} \text{H}_{5} \text{NH}_{2}\) respectively, also increase the reactivity due to their electron-donating effects.