Chapter 20: Problem 12
Benzene is a resonance hybrid mainly of two Kekule structures. Hence (1) Half the molecules correspond to one structure and half to the structure (2) At low temperatures benzene can be separated into two structures (3) Two structures make equal contribution to resonance hybrid (4) An individual benzene molecule changes back and forth between two structures
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Kekule structures
These are known as the Kekulé structures of benzene. Despite the elegance of Kekulé's idea, the problem arises when considering the actual behavior of benzene. Experimentally, benzene does not exhibit the distinct characteristics of alternating single and double bonds.
Instead, all carbon-carbon bonds in benzene are equivalent, suggesting something other than the simple Kekulé structures.
The Kekulé structures are useful representations but do not capture the true nature of benzene’s bonding.
In essence:
- Kekulé structures are theoretical constructs.
- They helped advance our understanding of aromatic compounds.
- The actual molecule doesn't correspond to either structure exclusively.
Resonance Hybrid
For benzene, the hybrid is composed of the two Kekulé structures. This means the actual bonding in benzene is an average of the two Kekulé forms.
Since each Kekulé structure equally contributes to the hybrid, benzene’s structure is a superposition of these two forms.
Here's what you need to understand about the resonance hybrid:
- It represents the true, stable structure.
- The real bonding situation in the molecule is an average or blend of the possible structures.
- This model explains why benzene’s carbon-carbon bonds are of equal length.
Thus, the resonance hybrid offers a more accurate picture, explaining the stability and uniform bond lengths found in benzene.
Electron Delocalization
In the case of benzene, the six pi (π) electrons from the double bonds are shared equally among all six carbon atoms in the ring. This delocalization results in the stabilization of the molecule.
To visualize this:
- Imagine the electrons spreading out evenly over the entire carbon ring, rather than being localized between individual carbon atoms.
- This leads to the uniformity in bond lengths.
This stability helps explain why benzene doesn’t undergo addition reactions typical of alkenes but instead participates in substitution reactions, preserving the aromatic system.