Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

An electron that has the quantum number \(n=3\) and \(m=2\) must (1) have spin value \(+1 / 2\) (2) have \(l=1\) (3) have \(l=0,1\) or 2 (4) have \(l=2\)

Short Answer

Expert verified
The electron must have l=2.

Step by step solution

Achieve better grades quicker with Premium

  • Unlimited AI interaction
  • Study offline
  • Say goodbye to ads
  • Export flashcards

Over 22 million students worldwide already upgrade their learning with Vaia!

01

Understand the Quantum Numbers

Quantum numbers n, l, m, and s describe the properties of electrons in atoms. For the given exercise, quantum numbers n (principal quantum number) and m (magnetic quantum number) are provided. The goal is to determine the possible value of l (angular momentum quantum number).
02

Identify the Range of l

For a given n, the quantum number l can take integer values from 0 to n-1. Since n=3, l can be 0, 1, or 2.
03

Verify the Value for m

The magnetic quantum number m can take on integer values from -l to +l. Given that m=2, we need to check which of the possible l values (0, 1, or 2) allow for m=2.
04

Determine the Correct l

If l=0 or l=1, the possible values for m will be constrained to the ranges -0 to 0 and -1 to 1 respectively, which do not include m=2. Only if l=2 does m=2 fall within the range -2 to 2.
05

Conclusion

Since l must be 2 in order for the given m value of 2 to be valid, the correct answer is (4) have l=2.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Quantum Number
The principal quantum number, represented by the symbol n, is a fundamental concept in quantum mechanics. It describes the energy level and size of the electron's orbit around the nucleus.

For example, if an electron has a principal quantum number of n=3, it means that the electron is in the third energy level. As n increases, the energy and the average distance of the electron from the nucleus also increase.

Understanding the principal quantum number helps us predict the general behavior of an electron, such as its potential energy and how it interacts with other electrons.
Angular Momentum Quantum Number
The angular momentum quantum number, denoted as l, defines the shape of the orbital in which an electron resides. It can take any integer value from 0 to n-1, where n is the principal quantum number.

For instance, if n=3, then l can be 0, 1, or 2. Each value of l corresponds to a different orbital shape:
  • l=0: s-orbital (spherical)
  • l=1: p-orbital (dumbbell-shaped)
  • l=2: d-orbital (cloverleaf-shaped)
These shapes determine how electrons distribute around the nucleus and how they bond with other atoms.
Magnetic Quantum Number
The magnetic quantum number, symbolized as m, specifies the orientation of the orbital in space. It can take any integer value between -l and +l, including zero.

For example, if l=2, then m can be -2, -1, 0, +1, or +2. This variety of values means that each type of orbital can align in different ways in three-dimensional space.

Understanding the magnetic quantum number is crucial because it determines the exact orbital an electron occupies. This helps us predict the magnetic properties of atoms and molecules.
Electron Properties
Electrons have several properties, described by quantum numbers n, l, m, and another quantum number called the spin quantum number (s). The spin quantum number can be either +1/2 or -1/2, indicating the two possible spin states of an electron.

In the given exercise, we have an electron with n=3 and m=2. To find the possible value of l, we use the rule that l can be any integer from 0 to n-1. Therefore, l can be 0, 1, or 2.

However, for m=2 to be valid, l must be at least 2, because m=2 is not possible if l is 0 or 1. This leads us to conclude that l must be equal to 2.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free