Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In a certain Bohr orbit the total energy is \(-4.9 \mathrm{eV}\), for this orbit, the kinetic energy and potential energy are respectively (1) \(9.8 \mathrm{eV},-4.9 \mathrm{eV}\) (2) \(4.9 \mathrm{eV},-9.8 \mathrm{eV}\) (3) \(4.9 \mathrm{eV}_{3}-4.9 \mathrm{eV}\) (4) \(9.8 \mathrm{eV},-9.8 \mathrm{eV}\)

Short Answer

Expert verified
Option (2): 4.9 eV, -9.8 eV

Step by step solution

01

Recall the Relationship of Total Energy

In a Bohr orbit, the total energy (E) is related to the kinetic energy (K) and potential energy (U) by the equation: \[ E = K + U \]
02

Property of Kinetic Energy in Bohr Orbit

The kinetic energy (K) in a Bohr orbit is equal to the negative of the total energy: \[ K = -E \]Given that the total energy (E) is -4.9 eV, we have \[ K = -(-4.9) = 4.9 \text{ eV} \]
03

Property of Potential Energy in Bohr Orbit

The potential energy (U) in a Bohr orbit is twice the total energy: \[ U = 2E \]Given that the total energy (E) is -4.9 eV, we have \[ U = 2(-4.9) = -9.8 \text{ eV} \]
04

State the Results for Kinetic and Potential Energy

So the kinetic energy is 4.9 eV, and the potential energy is -9.8 eV. Option (2) correctly matches these values.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Total Energy in Bohr Orbit
In atomic physics, the Bohr model plays a crucial role in understanding the energy levels of electrons in an atom. The total energy (E) of an electron in a Bohr orbit is the sum of its kinetic energy (K) and potential energy (U). This relationship is given by the equation:











E = K + U

For example, if the total energy is given to be -4.9 eV, this means that the energy level of the electron in that particular Bohr orbit is -4.9 eV. Total energy combines both the kinetic energy and potential energy of the electron. An important aspect to note is that the total energy in a Bohr orbit is always negative, indicating that the electron is bound to the nucleus.




Kinetic Energy in Bohr Orbit
The kinetic energy (K) of an electron in a Bohr orbit comes from its motion around the nucleus. A unique property of the Bohr model is that the kinetic energy is equal to the negative of the total energy. This can be expressed with the formula:





E

K = -E

This means if the total energy (E) is -4.9 eV, the kinetic energy will be:




K =-(-4.9) = 4.9 eV

In this case, the electron has a kinetic energy of 4.9 eV, indicating how much energy it has due to its motion around the nucleus. This relationship underscores how tightly bound the electron is within the atom.


Potential Energy in Bohr Orbit
The potential energy (U) of an electron in a Bohr orbit is related to the electrostatic force between the negatively charged electron and the positively charged nucleus. The Bohr model reveals that the potential energy is twice the total energy:

















U = 2E

When the total energy (E) is -4.9 eV, the potential energy (U) can be calculated as follows:


U = 2(-4.9) = -9.8 eV

Thus, the electron in this Bohr orbit has a potential energy of -9.8 eV. The negative sign signifies that this energy is needed to overcome the electrostatic attraction and remove the electron from the atom.


One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The wave number of first line in the Balmer series of hydrogen is \(15200 \mathrm{~cm}^{\text {? }}\). The wave number of the first line in the Balmer series of \(\mathrm{Be}^{3+}\) is (1) \(2.43 \times 10^{5} \mathrm{~cm}^{-1}\) (2) \(3.43 \times 10^{5} \mathrm{~cm}^{-1}\) (3) \(4.43 \times 10^{5} \mathrm{~cm}^{-1}\) (4) \(5.43 \times 10^{5} \mathrm{~cm}^{-1}\)

Consider the spectral lines resulting from the transition \(n=2\) to \(n=1\), in the atoms and ions given below, the shortest wavelength is produced by (1) IIydrogen atom (2) Deuterium atom (3) Singly ionised lithium (4) Doubly ionised lithium

An electron in the lithium atom is in the thi?d energy level. Then, which of the following is falsc? (1) The electron is in the excited state. (2) The atom can emit light. (3) The atom will decay due to radioactivity. (4) This implies no change in its nucleus.

Which best describes the emission spectra of atomic hydrogen? (1) A series of only four lines. (2) A discrete series of lines of equal intensity and equally spaced with respect to wavelength. (3) Several discrete series of lines with both intensity and spacing between decreasing as the wave number increases within each series. (4) A continuous emission of radiation of all frequencies.

Which of the following concerning Bohr's model is not true? (1) It predicts that probability of an electron near nucleus is more. (2) Angular momentum of electron in \(n\) th orbit is given by \(n \mathrm{~h} / 2 \pi\). (3) The radius of an orbit is proportional to \(\frac{n^{2}}{Z}\). (4) When an electron jump from \(N\) to \(K\) shell, energy is released.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free