Chapter 19: Problem 47
The false statement among the following is (1) heating \(1,1,2,2\) -tetrabromoalkane is heated with zinc powder in alcohol gives alkyne (2) 1-alkynes liberate hydrogen with sodium in liquid ammonia (3) Acetylene when treated with \(\mathrm{Cl}_{2}\) in \(\mathrm{CCl}_{4}\) forms lewisite (4) Terminal dihalides on heating with zinc or sodium forms cycloalkanes
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dehalogenation Reaction
Some key points include:
- The reaction usually requires a heated environment.
- Zinc powder is often the reducing agent used.
- The end product, in this case, is an alkyne.
Alkane and Alkyne Reactions
Alkanes are saturated hydrocarbons, meaning all carbon atoms are connected by single bonds. They undergo reactions like combustion and substitution. Alkynes, on the other hand, are unsaturated hydrocarbons with one or more carbon-carbon triple bonds. This makes them more reactive than alkanes. When 1-alkynes react with sodium in liquid ammonia, they liberate hydrogen gas.
Here's a simplified breakdown of the reaction:
- The triple bond of the alkyne makes it nucleophilic.
- Sodium donates electrons, reducing the alkyne.
- Hydrogen gas is liberated as a by-product.
Nucleophilic Addition
Key points to remember:
- Nucleophiles are electron-rich and seek positive centers.
- Electrophiles are electron-deficient and seek electrons.
- The result is the formation of new chemical bonds and products.
Cycloalkane Formation
Here's how it works:
- Terminal dihalides undergo intramolecular reactions.
- The halogens are removed by the reducing agent (zinc or sodium).
- The resulting structure forms a ring, creating a cycloalkane.