Chapter 19: Problem 44
Which of the following statements is correct? (1) alkynes are more reactive than alkenes towards halogen addition (2) alkynes are less reactive than alkenes towards halogen addition (3) both alkynes and alkenes are cqually reactive towards halogen addition (4) primary vinylic cation \((\mathrm{RCII}=\mathrm{CII})\) is more rcactive than sccondary vinylic cation \(\left(\mathrm{RC}=\mathrm{CII}_{2}\right)\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
alkenes
In halogen addition reactions, halogens like chlorine (Cl2) or bromine (Br2) add across the double bond, resulting in the formation of vicinal dihalides (where two halogen atoms attach to adjacent carbons).
The general structure of an alkene reacting with a halogen can be represented as:
\[ \text{R-CH=CH-R'} + \text{X}_2 \rightarrow \text{R-CHX-CHX-R'} \ \text{(where X is the halogen)} \ \ \text{For instance:} \ \text{CH\textsubscript{2}=CH\textsubscript{2}} + \text{Br}_2 \rightarrow \text{CH\textsubscript{2}Br-CH\textsubscript{2}Br} \ \ \text{(Ethene plus bromine forms 1,2-dibromoethane)} \ \ \ \]
This high reactivity is due to the π-bond in the double bond, which is easier to break during the reaction, allowing halogen atoms to form bonds with the carbon atoms.
alkynes
When involved in a halogen addition reaction, halogens like chlorine or bromine add across the triple bond to form tetrahalides in two successive steps - first forming a dihalide, followed by a further addition of halogens to form the tetrahalide.
The general reaction can be depicted as:
\[ \text{R-C≡C-R'} + \text{X}_2 \rightarrow \text{R-CX=CX-R'} + \text{X}_2 \rightarrow \text{R-CX\textsubscript{2}-CX\textsubscript{2}-R'} \ \text{(where X is the halogen)} \ \ \text{For example:} \ \text{CH≡CH} + \text{Br}_2 \rightarrow \text{CHBr=CHBr} + \text{Br}_2 \rightarrow \text{CHBr\textsubscript{2}-CHBr\textsubscript{2}} \ \ \text{(Ethyne reacts with bromine to form 1,1,2,2-tetrabromoethane)} \ \ \]
Here, the reactivity is constrained by the higher energy required to break the two π-bonds in the triple bond.
halogen addition reactions
These reactions are characterized as follows:
- The π-bond electrons in the double or triple bond interact with the halogen molecule.
- This interaction leads to the formation of a cyclic halonium ion intermediate in alkenes.
- The halonium ion is then attacked by a halide ion, resulting in the final addition product.
\[\text{CH}\textsubscript{2}=\text{CH}\textsubscript{2} + \text{Br}\textsubscript{2} \rightarrow \text{Br}-\text{CH}\textsubscript{2}-\text{CH}\textsubscript{2}-\text{Br}\]
In this reaction, the bromine molecule adds across the double bond to yield 1,2-dibromoethane.
When dealing with alkynes, the initial product is a di-substituted alkene which further reacts with another molecule of halogen to form a tetra-substituted alkane. This process underlines one of the deviations in reactivity behaviour between alkenes and alkynes.
reactivity comparison
Alkenes have one π-bond in the double bond, making it relatively easier to break. Alkynes, however, have two π-bonds within the triple bond, requiring more energy to break and thereby reducing their reactivity.
This reactivity trend is crucial in many chemical reactions and synthesis processes.
- Alkenes easily undergo halogen addition, forming vicinal dihalides.
- Alkynes require more energy to break the triple bond and form the corresponding tetrahalides through successive steps.
\[ \text{Alkenes} > \text{Alkynes} \text{in terms of halogen addition reactivity.}\]
This trend highlights that alkenes will react faster with halogens compared to alkynes, making alkenes the more reactive species in halogen addition reactions.