Chapter 19: Problem 42
Passing two moles of acetylene and one mole of hydrogen cyanide through a red hot tube yields (1) pyrole (2) pyridine (3) ethyl amine (4) diethyl amine
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
headline of the respective core concept
When acetylene is exposed to high temperatures, such as in a red-hot tube, its high reactivity can lead to significant molecular transformations.
Some crucial reactions of acetylene include:
- Substitution reactions, where the triple bond interacts with other molecules to form new products
- Polymerization, where multiple acetylene molecules combine to form larger compounds
- Coupling reactions, where acetylene bonds with different chemical species, such as cyanides, to form more complex organic structures
headline of the respective core concept
Pyridine formation involves a series of steps and careful control of reaction conditions. When acetylene \(C_2H_2\) and hydrogen cyanide \(HCN\) are passed through a red-hot tube, the thermal energy facilitates the molecular rearrangement necessary to form pyridine. The high temperatures enable:
- Dehydrogenation, which helps in the removal of hydrogen atoms from the reactants
- Coupling, allowing acetylene to bond with hydrogen cyanide
- Ring formation, where the rearranged molecules form a stable aromatic structure with a nitrogen atom
headline of the respective core concept
In the context of the given exercise, the high-temperature reaction is essential for converting acetylene and hydrogen cyanide into pyridine.
Some key aspects of high-temperature reactions include:
- Increased kinetic energy of molecules, facilitating the breaking and formation of bonds
- Enhanced reaction rates, making it possible for new products to form quickly
- Thermal energy acting as a driving force for molecular rearrangements and synthesis