Chapter 18: Problem 68
Cyclopentene on treatment with alkaline \(\mathrm{KMnO}_{4}\) gives (1) cyclopentanol (2) trans-1,2-cyclopentane diol (3) cis 1,2 -cyclopentane diol (4) mixture of \((2)\) and \((3)\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
alkene hydroxylation
The reaction is typically achieved using strong oxidizing agents such as potassium permanganate (KMnO4).
This process turns the alkene into a diol, which is a compound with two hydroxyl groups.
Hydroxylation can happen in either a syn or anti fashion. Syn addition leads to both hydroxyl groups being added to the same side of the double bond.
In the case of cyclopentene reacting with alkaline KMnO4, the hydroxylation occurs in a syn manner, resulting in a cis-diol.
cis-diol formation
In our case, cyclopentene reacts with alkaline KMnO4 (potassium permanganate). This reaction is known as syn-hydroxylation.
The syn-hydroxylation means that the OH groups attach to the same face of the double bond.
The product of this hydroxylation reaction with cyclopentene is cis-1,2-cyclopentane diol.
Because the hydroxyl groups are on the same side, it has the 'cis' configuration, where both hydroxyl groups are added to adjacent carbons.
oxidizing agents in organic chemistry
Alkaline KMnO4 is one such strong oxidizing agent. It is highly effective in converting alkenes into diols.
In oxidation reactions, KMnO4 typically adds hydroxyl groups across a double bond, breaking it and forming a diol.
The agents help to increase the oxygen content of the organic molecules by breaking the double bonds.
For cyclopentene, KMnO4's action forms cis-1,2-cyclopentane diol as it hydroxylates the double bond. This specificity shows how oxidizing agents can control the product configuration in organic reactions.