Chapter 18: Problem 4
Which of the following is an unsymmetrical alkene? (1) 1 -Butene (2) 2-Hexene (3) 1-pentene (4) All of these
Short Answer
Expert verified
All of these (Option 4)
Step by step solution
01
Understand the Meaning of Unsymmetrical Alkene
An unsymmetrical alkene is an alkene in which the two groups on either side of the double bond are different. This means the two carbons involved in the double bond are connected to different substituents.
02
Analyze the Structure of 1-Butene
The structure of 1-Butene is CH2=CH-CH2-CH3. On one end of the double bond, there is a hydrogen, and on the other end, there is a methyl group (CH3). This makes 1-butene unsymmetrical.
03
Analyze the Structure of 2-Hexene
The structure of 2-Hexene is CH3-CH=CH-CH2-CH2-CH3. On one end of the double bond, there is an ethyl group (CH2-CH3), and on the other end, there is a propyl group (CH2-CH2-CH3). This makes 2-hexene unsymmetrical.
04
Analyze the Structure of 1-Pentene
The structure of 1-Pentene is CH2=CH-CH2-CH2-CH3. On one end of the double bond, there is a hydrogen, and on the other end, there is a butyl group (CH2-CH2-CH3). This makes 1-pentene unsymmetrical.
05
Compare All Options
Since all 1-Butene, 2-Hexene, and 1-Pentene have different groups attached to the double-bonded carbons, all options represent unsymmetrical alkenes.
06
Conclusion
Conclude that all the provided alkenes are unsymmetrical, so the correct answer is option 4.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
alkene structure
Alkenes are a class of hydrocarbons that contain at least one carbon-carbon double bond (C=C). This double bond significantly alters the chemical properties of the molecule.
The double bond in alkenes is what makes them unique. It consists of one sigma bond and one pi bond. The pi bond is less stable and more reactive, making alkenes more chemically active than alkanes.
When analyzing alkene structures, you'll often look at the position of the double bond and the groups attached to the double-bonded carbons.
The double bond in alkenes is what makes them unique. It consists of one sigma bond and one pi bond. The pi bond is less stable and more reactive, making alkenes more chemically active than alkanes.
When analyzing alkene structures, you'll often look at the position of the double bond and the groups attached to the double-bonded carbons.
- 1-Butene: CH2=CH-CH2-CH3
- 2-Hexene: CH3-CH=CH-CH2-CH2-CH3
- 1-Pentene: CH2=CH-CH2-CH2-CH3
organic chemistry
Organic chemistry is the study of carbon-containing compounds and their properties. Alkenes are a fundamental part of this branch of chemistry because of their double bonds.
Understanding alkenes in organic chemistry involves recognizing the types of reactions they undergo, such as addition reactions. These reactions are possible due to the reactivity of the carbon-carbon double bonds, making alkenes versatile in forming complex molecules.
In organic chemistry, these structures also help in understanding the concepts of isomerism, which includes structural isomers and geometric isomers. For instance:
Understanding alkenes in organic chemistry involves recognizing the types of reactions they undergo, such as addition reactions. These reactions are possible due to the reactivity of the carbon-carbon double bonds, making alkenes versatile in forming complex molecules.
In organic chemistry, these structures also help in understanding the concepts of isomerism, which includes structural isomers and geometric isomers. For instance:
- 1-Butene and 2-Butene: Both have the formula C4H8 but different configurations due to the position of the double bond.
- cis-2-butene and trans-2-butene: Different spatial arrangements around the double bond.
molecular asymmetry
Molecular asymmetry in alkenes refers to the different groups attached to the carbon atoms involved in the double bond, resulting in unsymmetrical alkenes.
An unsymmetrical alkene has different substituents on each of the double-bonded carbons. For example:
Understanding molecular asymmetry is essential for predicting reaction mechanisms and outcomes.
An unsymmetrical alkene has different substituents on each of the double-bonded carbons. For example:
- 1-Butene: CH2=CH-CH2-CH3 (hydrogen on one end, and a methyl group on the other)
- 2-Hexene: CH3-CH=CH-CH2-CH2-CH3 (ethyl on one end and propyl on the other)
- 1-Pentene: CH2=CH-CH2-CH2-CH3 (hydrogen on one end and a butyl group on the other)
Understanding molecular asymmetry is essential for predicting reaction mechanisms and outcomes.