Chapter 18: Problem 33
The product of acid-catalysed hydration of 2 -phenyl propene is (1) 3-phenyl-2-propanol (2) I-phenyl-2-propanol (3) 2-phenyl-2-propanol (4) 2-phenyl-1-propanol
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Markovnikov's Rule
This rule helps us understand why certain products form during acid-catalyzed hydration. By following Markovnikov's Rule, you can predict the major product of these reactions accurately. Remember, this rule applies due to the stability of intermediates formed during the reaction.
Alkene
When looking at alkenes, the double bond represents a region of high electron density, making it an attractive target for electrophilic addition reactions. For example, in the presence of an acid, a water molecule can add across the double bond, leading to hydration. Understanding the nature of alkenes is key to predicting how they will react and what products they will form.
2-phenylpropene
Given its structure, the double bond is between the second and third carbon atoms. During acid-catalyzed hydration of 2-phenylpropene, water adds across this double bond. According to Markovnikov's Rule, the hydrogen (H) from water attaches to the third carbon, while the hydroxyl group (OH) attaches to the second carbon. This leads to the formation of 2-phenyl-2-propanol as the main product.
Organic Reaction Mechanism
- Protonation of the alkene to form a more stable carbocation intermediate.
- Water (acting as a nucleophile) adding to the carbocation intermediate.
- Deprotonation of the added water molecule, resulting in the formation of an alcohol.
In our example with 2-phenylpropene, the acid first protonates the double bond, forming a carbocation at the second carbon. Water then adds to this carbocation, and after losing a proton, forms 2-phenyl-2-propanol. Each step follows a logical sequence, ensuring the most stable intermediate is formed, which determines the final product.