After initiation, the reaction moves into the propagation step.
This is where the actual substitution happens, involving a series of two key reactions.
First, one of the halogen radicals produced in the initiation step reacts with an alkane molecule.
- This generates a new radical from the alkane (the \text{alkyl} radical) and a stable hydrogen halide molecule.
For example: \[ \text{\textsuperscript{·}} Cl + CH_4 \rightarrow \text{\textsuperscript{·}} CH_3 + HCl \] The second part involves the newly formed alkyl radical reacting with another halogen molecule to regenerate the halogen radical and form the halogenated alkane.
- This ensures the chain reaction continues as long as there are reactants available.
Example: \[ \text{\textsuperscript{·}} CH_3 + Cl_2 \rightarrow CH_3Cl + \text{\textsuperscript{·}} Cl \] These steps repeat and can rapidly produce a large number of halogenated alkanes.
The propagation steps are crucial for the chain reaction nature of the halogenation process.