Chapter 14: Problem 15
Free radicals can undergo (1) Disproportion to two species (2) Rearrangement to more stable free radical (3) Decomposition to give another free radical (4) Combination with other free radical (5) All are correct
Short Answer
Expert verified
All are correct.
Step by step solution
01
Understanding Disproportionation
Disproportionation involves the transformation of two free radicals into two different chemical species. This typically results in one species being oxidized and the other being reduced.
02
Understanding Rearrangement
Rearrangement refers to the reorganization of the molecular structure of a free radical to form a more stable configuration. This often involves the migration of atoms or groups within the molecule.
03
Understanding Decomposition
Decomposition of free radicals occurs when a free radical breaks down to produce another free radical and other products. This process usually involves the cleavage of chemical bonds.
04
Understanding Combination
Combination occurs when two free radicals react together to form a single, more stable molecule. This neutralizes the unpaired electrons of both radicals.
05
Conclusion
Free radicals can undergo disproportionation, rearrangement, decomposition, and combination. Therefore, all the options listed are correct mechanisms.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Disproportionation
Disproportionation is a type of redox reaction where one molecule undergoes simultaneous oxidation and reduction. In the context of free radicals, it refers to the transformation of two free radicals into two distinct chemical species. This process often yields one oxidized and one reduced product.
For example, when two molecules of phosphorous trihydride (PH3) react, we can see:
\[ 2PH_3 \rightarrow P_2H_4 + H_2 \text{ } \text{(disproportionation reaction)} \]
In this reaction, one PH3 molecule is reduced to H2, while the other is oxidized to P2H4. This shows how two radicals can stabilize by disproportionating into different products.
For example, when two molecules of phosphorous trihydride (PH3) react, we can see:
\[ 2PH_3 \rightarrow P_2H_4 + H_2 \text{ } \text{(disproportionation reaction)} \]
In this reaction, one PH3 molecule is reduced to H2, while the other is oxidized to P2H4. This shows how two radicals can stabilize by disproportionating into different products.
Rearrangement
Rearrangement in free radical chemistry refers to the process where the molecular structure of a free radical changes to a more stable form. This often involves the movement of atoms or groups within the molecule.
Consider the free radical formed during the reaction of isobutane with a halogen:
\[ (\text{CH}_3)_3 \text{C} \bullet \rightarrow (\text{CH}_3)_2 \text{C} \bullet \text{CH}_2\text{ } (\text{rearrangement}) \]
Here, the tertiary butyl radical rearranges to a more stable secondary butyl radical, making the overall system more stable. This rearrangement lowers the energy of the molecule and results in a more stable free radical.
Consider the free radical formed during the reaction of isobutane with a halogen:
\[ (\text{CH}_3)_3 \text{C} \bullet \rightarrow (\text{CH}_3)_2 \text{C} \bullet \text{CH}_2\text{ } (\text{rearrangement}) \]
Here, the tertiary butyl radical rearranges to a more stable secondary butyl radical, making the overall system more stable. This rearrangement lowers the energy of the molecule and results in a more stable free radical.
Decomposition
Decomposition in the context of free radicals refers to the process where a free radical breaks down to form another free radical and other products. This typically involves the breaking of chemical bonds.
For example, consider the decomposition of benzoyl peroxide (C6H5CO-OO-COC6H5):
\[ \text{C}_6\text{H}_5\text{CO-OO-COC}_6\text{H}_5 \rightarrow 2\text{C}_6\text{H}_5\text{CO}-\bullet + \text{O}_2 \text{ } (\text{decomposition}) \]
In this reaction, benzoyl peroxide decomposes to produce two benzoyl radicals and molecular oxygen. This illustrates how free radicals can form new radicals through decomposition.
For example, consider the decomposition of benzoyl peroxide (C6H5CO-OO-COC6H5):
\[ \text{C}_6\text{H}_5\text{CO-OO-COC}_6\text{H}_5 \rightarrow 2\text{C}_6\text{H}_5\text{CO}-\bullet + \text{O}_2 \text{ } (\text{decomposition}) \]
In this reaction, benzoyl peroxide decomposes to produce two benzoyl radicals and molecular oxygen. This illustrates how free radicals can form new radicals through decomposition.
Combination Reactions
Combination reactions involving free radicals occur when two radicals come together to form a more stable molecule, effectively neutralizing each other. This is important because it helps to terminate chain reactions in radical chemistry.
Consider the reaction between two methyl radicals:
\[ \text{2CH}_3\bullet \rightarrow \text{CH}_3\text{CH}_3 \text{ } (\text{combination reaction}) \]
Here, two methyl radicals combine to form ethane (C2H6), a more stable molecule. This reaction demonstrates how free radicals decrease their reactivity by forming a stable bond through combination.
Consider the reaction between two methyl radicals:
\[ \text{2CH}_3\bullet \rightarrow \text{CH}_3\text{CH}_3 \text{ } (\text{combination reaction}) \]
Here, two methyl radicals combine to form ethane (C2H6), a more stable molecule. This reaction demonstrates how free radicals decrease their reactivity by forming a stable bond through combination.