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Which is not correct? (1) \(\mathrm{Ge}(\mathrm{OH})_{2}\) is amphoteric. (2) \(\mathrm{GeCl}_{2}\) is more stable than \(\mathrm{GeCl}_{4}\). (3) \(\mathrm{GeO}_{2}\) is less acidic than \(\mathrm{SiO}_{2}\). (4) \(\mathrm{GeCl}_{4}\) in \(\mathrm{HCl}\) forms \(\left[\mathrm{GeCl}_{6}\right]^{2-}\).

Short Answer

Expert verified
Option 2 is incorrect.

Step by step solution

01

Analyze Option 1

Check if \(\text{Ge(OH)}_{2}\) is amphoteric. An amphoteric substance can act both as an acid and as a base. Since \( \text{Ge(OH)}_{2} \) can exhibit this behavior, it can be classified as amphoteric. Therefore, this option is correct.
02

Analyze Option 2

Verify the stability of \( \text{GeCl}_{2} \) compared to \( \text{GeCl}_{4} \). Generally, \( \text{GeCl}_{4} \) is more stable due to its complete octet configuration around germanium. Hence, this option is incorrect.
03

Analyze Option 3

Evaluate the acidity of \( \text{GeO}_{2} \) compared to \( \text{SiO}_{2} \). \( \text{GeO}_{2} \) is indeed less acidic than \( \text{SiO}_{2} \), confirming this option as correct.
04

Analyze Option 4

Check the formation of \( \text{[GeCl}_{6}]^{2-} \) in presence of \( \text{HCl} \). \( \text{GeCl}_{4} \) does form the anionic complex \( \text{[GeCl}_{6}]^{2-} \), making this option correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amphoteric substances
Understanding amphoteric substances is key in inorganic chemistry. Amphoteric substances can act both as acids and bases. This dual behavior allows them to neutralize both acids and bases, making them unique.
For example, \(\text{Ge(OH)}_{2}\) is amphoteric, meaning it can donate protons (acting as an acid) or accept protons (acting as a base) depending on the reacting substance.
Another common amphoteric substance is aluminum hydroxide \(\text{Al(OH)}_{3}\).
Recognizing amphoteric substances helps in predicting reactions and understanding compound behavior in different environments.
Stability of compounds
The stability of compounds is vital in determining how they react and persist under different conditions. For instance, \(\text{GeCl}_{4}\) is more stable than \(\text{GeCl}_{2}\).
This is because \(\text{GeCl}_{4}\) achieves a full octet, satisfying the octet rule, which makes it less reactive and more stable.
On the other hand, \(\text{GeCl}_{2}\) does not have a complete octet, making it more reactive and less stable. This stability impacts how these compounds are used and handled in practical applications.
Acidity comparison
Comparing the acidity of compounds like \(\text{GeO}_{2}\) and \(\text{SiO}_{2}\) can be quite insightful.
Acidity is the ability of a substance to donate protons. \(\text{SiO}_{2}\) (Silicon dioxide) is more acidic than \(\text{GeO}_{2}\) (Germanium dioxide).
This happens because Silicon (Si) is smaller and more electronegative than Germanium (Ge), leading to a stronger attraction of electrons towards the oxygen in \(\text{SiO}_{2}\).
This makes \(\text{SiO}_{2}\) more likely to donate protons compared to \(\text{GeO}_{2}\). Understanding these acidity trends aids in predicting reactions and compatibility between compounds.
Anionic complexes
Anionic complexes are negatively charged groups consisting of a central metal atom bonded to surrounding ligands.
For example, \(\text{GeCl}_{4}\) in \(\text{HCl}\) forms the anionic complex \(\text{[GeCl}_{6}]^{2-}\).
This occurs because \(\text{GeCl}_{4}\) reacts with additional chlorine ions (\text{Cl}^{-}) from hydrochloric acid (HCl), resulting in \(\text{[GeCl}_{6}]^{2-}\).
Anionic complexes are crucial in various chemical processes and applications, including catalysis and the formation of more complex structures.

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Most popular questions from this chapter

Carbon and silicon belong to IVA group. The maximum coordination number of carbon in commonly occurring compounds is 4, whercas that of silicon is 6 . This is duc to (1) Large size of silicon (2) Availability of vacant d-orbitals in silicon (3) Morc clectropositive nature of silicon (4) Silicon being vulnerable to attack by nucleo philic reagents

\(\mathrm{SiCl}_{4}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{X}+\mathrm{HCl}\) \(\mathrm{X} \stackrel{1000 \mathrm{C}}{\longrightarrow} \mathrm{Y}\) \(\mathrm{X}\) and \(\mathrm{Y}\) in the above reactions are (1) \(\mathrm{SiO}_{2}\) and \(\mathrm{Si}\) (2) \(\mathrm{H}_{4} \mathrm{SiO}_{4}+\mathrm{SiO}_{2}\) (3) \(\mathrm{Si}\) and \(\mathrm{SiO}_{2}\) (4) \(\mathrm{H}_{4} \mathrm{SiO}_{4}+\mathrm{Si}\)

Which of the following statements is not correct? (1) The dihalides of 14 th group elements are more ionic as compared to their tetrahalides. (2) \(\mathrm{GeX}_{2}\) is less stable than \(\mathrm{Ge} \mathrm{X}_{4}\). (3) \(\mathrm{Pb} \mathrm{X}_{2}\) is less stable than \(\mathrm{Pb} \mathrm{X}_{4}\). (4) Silicon cannot form monoxide.

Regarding the elements of Group IVA, which of the following statement is false? (1) Lead do not cxhibit allotropy. (2) Element with lowest melting point is tin. (3) Carbon in the form of diamond has maximum density. (4) Catenation power of lcad is zero.

Dry ice is effective in seeding clouds because (1) \(\mathrm{CO}_{2}\) and \(\mathrm{II}_{2} \mathrm{O}\) have similar crystal structure (2) it increases water content of the cloud (3) \(\mathrm{CO}_{2}\) molecules offer nucleus for condensation (4) upon sublimation, it lowcrs the temperature of water

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