Chapter 13: Problem 20
Two elements \(\Lambda\) and \(\mathrm{B}\) of carbon family have very close atomic radii. The clements \(\Lambda\) and \(B\) arc (1) \(\mathrm{Pb}\) and \(\mathrm{Sn}\) (2) \(\mathrm{C}\) and \(\mathrm{Si}\) (3) Ge and Sn (4) \(\mathrm{Si}\) and \(\mathrm{Gc}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Carbon family elements
For instance, carbon is a nonmetal, silicon and germanium are metalloids, while tin and lead are metals. This variation results in a wide range of bonding types and chemical behaviors. Understanding the atomic radii of these elements helps us comprehend how these properties change, aiding in predicting their reactivity and compatibility in different reactions.
Group 14 elements
Silicon (Si), Germanium (Ge), Tin (Sn), and Lead (Pb) display an trend towards metallic properties, with Lead being the most metallic. Germanium and Silicon, however, are known for their semiconductor properties, making them invaluable in electronics. The ability to compare their atomic radii gives insight into their bonding capabilities and placements in various chemical environments.
Periodic table trends
This trend helps us predict not only the size of atoms but also their reactivity and other chemical properties. Elements like Si and Ge, being adjacent to each other, have very similar atomic radii, making them closely comparable. This similarity often means they can substitute for one another in various chemical compounds, which is vital in fields like material science and chemistry.