Chapter 12: Problem 86
Which of the following is called alum? (1) \(\left(\mathrm{NII}_{4}\right) \mathrm{SO}_{4} \cdot \mathrm{FeSO}_{4} \cdot 6 \mathrm{II}_{2} \mathrm{O}\) (2) \(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot \Lambda \mathrm{l}_{2}\left(\mathrm{SO}_{4}\right)_{3} \cdot 24 \mathrm{II}_{2} \mathrm{O}\) (3) \(\mathrm{KCl} \cdot \mathrm{MgCl}_{2} \cdot 6 \mathrm{II}_{2} \mathrm{O}\) (4) \(\mathrm{Na} \mathrm{AlO}_{2}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
hydrated double sulfate salts
A typical formula for these salts is \text{M}_2\text{SO}_\({4}\) \text{M}_{\(III\)}_2(\text{SO}_4)_3 \textto 24\text{H}_2\text{O}, where 'M' is a monovalent cation, and '\(M_{III}\)' is a trivalent cation.
- Monovalent cations: Potassium (K\text{⁺}), Sodium (Na\text{⁺})
- Trivalent cations: Aluminum (Al\text{³⁺}), Iron (Fe\text{³⁺})
chemical compound definitions
There are several types of compounds, including:
- Ionic compounds: Formed from the electrostatic attraction between positive and negative ions (e.g., NaCl)
- Covalent compounds: Formed by the sharing of electrons between atoms (e.g., H₂O)
- Metallic compounds: Formed by the pooling of electrons shared among metal atoms (e.g., Fe, Cu)
alum formula analysis
Steps for formula analysis:
1. Check for monovalent cation (\text{M}): Common examples are potassium (K\text{⁺}) and sodium (Na\text{⁺}).
2. Check for trivalent cation (\text{M}_{\(III\)}): Common examples are aluminum (Al\text{³⁺}) and iron (Fe\text{³⁺}).
3. Verify the sulfate components (\text{SO}₄) are present in specific ratios.
4. Ensure the compound includes 24 water molecules as water of hydration.
The exercise options were analyzed using this framework. For example:
- Option 1: Missing the proper amount of water of hydration.
- Option 3: Incorrect ions and lacks water of hydration.
- Option 4: Not related to the alum structure at all.