Chapter 12: Problem 40
Fluorine is more electronegative than either boron or phosphorous. What conclusion can be drawn from the fact that \(\mathrm{BF}_{3}\) has no dipole moment but \(\mathrm{PF}_{3}\) does? (1) \(\mathrm{BF}_{3}\) is not spherically symmetrical but \(\mathrm{PF}_{3}\) is. (2) \(\mathrm{BF}_{3}\) moleculc must be linear. (3) The atomic radius of \(P\) is larger than that of \(B\). (4) The \(\mathrm{B} \mathrm{F}_{3}\) molccule must be planar triangular.
Short Answer
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Key Concepts
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