Chapter 12: Problem 40
Fluorine is more electronegative than either boron or phosphorous. What conclusion can be drawn from the fact that \(\mathrm{BF}_{3}\) has no dipole moment but \(\mathrm{PF}_{3}\) does? (1) \(\mathrm{BF}_{3}\) is not spherically symmetrical but \(\mathrm{PF}_{3}\) is. (2) \(\mathrm{BF}_{3}\) moleculc must be linear. (3) The atomic radius of \(P\) is larger than that of \(B\). (4) The \(\mathrm{B} \mathrm{F}_{3}\) molccule must be planar triangular.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electronegativity
In the context of \(\text{BF}_3\) and \(\text{PF}_3\), the high electronegativity of fluorine causes a significant electron pull towards itself from both boron and phosphorus. However, the resulting molecular behavior differs due to their respective geometries.
Dipole Moment
For example, in \(\text{BF}\_3\), even though each \(\text{B-F}\) bond has a dipole, the molecular symmetry results in these dipoles canceling out. Therefore, \(\text{BF}\_3\) shows no overall dipole moment.
Conversely, \(\text{PF}\_3\) has a trigonal pyramidal geometry, which is asymmetrical due to a lone pair on phosphorus. This asymmetry means the dipoles do not cancel out, and \(\text{PF}\_3\) has a net dipole moment.
Trigonal Planar Structure
Boron trifluoride \(\text{BF}\_3\) is an example of a molecule with a trigonal planar structure. In \(\text{BF}_3\), boron is at the center, with the three fluorine atoms evenly spaced around it. Due to this symmetry, any dipole moments from the \(\text{B-F}\) bonds cancel out, resulting in no net dipole moment.
Trigonal Pyramidal Structure
Phosphorus trifluoride \(\text{PF}\_3\) exhibits a trigonal pyramidal structure. Due to the lone pair on phosphorus, the molecule is not symmetrically arranged. This asymmetry causes the dipole moments of the \(\text{P-F}\) bonds to not cancel out, resulting in a net dipole moment for the entire molecule.