Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The co-ordination mumber of aluminiun in meta aluminate and aluminates, respectively, is (1) 4,4 (2) 4,6 (3) 6,4 (4) 6,6

Short Answer

Expert verified
Option (2) 4,6

Step by step solution

01

Understand the Coordination Number

The coordination number of an atom in a molecule or crystal is the number of atoms it is directly bonded to.
02

Examine Meta Aluminate

In meta aluminate, aluminum typically has a coordination number of 4, meaning it is bonded to four oxygen atoms.
03

Examine Aluminates

In aluminates, aluminum typically has a coordination number of 6, meaning it is bonded to six oxygen atoms.
04

Compare with Given Options

By analyzing the coordination numbers, we can see that option (2) 4,6 correctly describes aluminum's coordination numbers in meta aluminate and aluminates, respectively.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

meta aluminate
Meta aluminate is an important compound in coordination chemistry. In this type of compound, an aluminum atom is bonded directly to four oxygen atoms.
This specific arrangement gives aluminum a coordination number of 4.
The term 'meta' indicates a particular structure where oxygen atoms surround and connect to the central aluminum atom.
Understanding this coordination helps us in predicting the properties and behavior of meta aluminates in different chemical reactions.
When learning about meta aluminate, it's essential to recognize how these bonds contribute to its stability and reactivity.
aluminates
Aluminates are another class of compounds involving aluminum.
In these compounds, aluminum typically has a coordination number of 6, meaning it is bonded to six oxygen atoms.
This higher coordination number results from the arrangement of these atoms around the aluminum ion, forming a more complex structure compared to meta aluminates.
Aluminates are found in various chemical and industrial processes.
They are used in making ceramics, cement, and other materials.
By understanding the coordination number, we learn about the bonding, which aids in predicting the compound's physical and chemical properties.
coordination chemistry
Coordination chemistry focuses on the structure and properties of complex compounds formed by metals bonded to ligands.
A key concept in this field is the coordination number, which tells us how many atoms or molecules directly bond to a central atom.
For aluminum, commonly found coordination numbers are 4 and 6.
By knowing the coordination number, we can determine how a central atom interacts with its surrounding atoms.
This helps us predict the geometry, stability, and reactivity of the compound.
When studying coordination chemistry, it is crucial to understand these fundamental concepts to grasp how different compounds are formed and behave in various chemical reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Boron nitridc obtained by heating borazolc is (1) white solid with a diamond-like structure. (2) slippery white solid with layered structure similar to that of graphite. (3) covalent liquid and is structurally similar to \(\mathrm{CO}\). (4) soft low-melting solid with rock salt-like structure.

\(\mathrm{AlCl}_{3}\) is (1) anhydrous and covalent. (2) anhydrous and ionic. (3) covalent and basic. (4) co-ordinate and acidic.

\(\Lambda\) boron carbide rod is used in a nuclear reactor because \(\left({ }^{10} \mathrm{~B}\right)\) has very (1) low cross-scctional area for capturing neutrons. (2) high cross-sectional arca for capturing neutrons. (3) low cross-scctional area for removing positrons. (4) high cross-sectional area for capturing neutrions.

Pure boron is best prepared by (1) heating \(\mathrm{B}_{2} \mathrm{O}_{3}\) with \(\mathrm{II}_{2}\). (2) heating \(\mathrm{B}_{2} \mathrm{O}_{3}\) with Na or \(\mathrm{K}\). (3) heating \(\mathrm{KBF}_{4}\) with Na or \(\mathrm{K}\). (4) heating \(\mathrm{BBr}_{3}\) with \(\mathrm{II}_{2}\) in the presence of catalyst.

Which of the following statements is falsc? (1) \(\mathrm{B}(\mathrm{OII})_{3}\) partially reacts with water to form \(\mathrm{II}_{3} \mathrm{O}^{+}\) and \(\left[\mathrm{B}(\mathrm{OII})_{4}\right]^{-}\) and behaves like a weak acid. (2) \(\mathrm{B}(\mathrm{OII})_{3}\) behaves like a strong monobasic acid in the presence of sugars and this acid can be titrated against on NaOII solution using phenolphthalein. (3) \(\mathrm{B}(\mathrm{OII})_{3}\) does not donate a proton and hencc does not form any salt of NaOII. (4) \(\mathrm{B}(\mathrm{OII})_{3}\) reacts with \(\mathrm{NaO}\) II forming \(\mathrm{Na}\left[\mathrm{B}(\mathrm{OII})_{4}\right]^{-}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free