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Thermal stability of \(\mathrm{BaCO}_{3}, \mathrm{CaCO}_{3}\) and \(\mathrm{MgCO}_{3}\) is (1) \(\mathrm{CaCO}_{3}>\mathrm{MgCO}_{3}>\mathrm{BaCO}_{3}\) (2) \(\mathrm{MgCO}_{3}>\mathrm{CaCO}_{3}>\mathrm{BaCO}_{3}\) (3) \(\mathrm{BaCO}_{3}>\mathrm{MgCO}_{3}>\mathrm{CaCO}_{3}\) (4) \(\mathrm{BaCO}_{3}>\mathrm{CaCO}_{3}>\mathrm{MgCO}_{3}\)

Short Answer

Expert verified
Option (2): MgCO₃ > CaCO₃ > BaCO₃.

Step by step solution

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01

- Understanding Thermal Stability

Thermal stability refers to the ability of a compound to resist decomposition when heated. In carbonates, this is influenced by the cation present (Ba, Ca, or Mg), which affects the lattice energy and the ease with which the compound decomposes.
02

- Analyzing Cations

Consider the position of Ba, Ca, and Mg in the periodic table. As we move down the group from Mg to Ba, the size of the cation increases. Larger cations result in weaker lattice energies, making it easier for the compound to decompose.
03

- Trend in Thermal Stability

Smaller cations like Mg will have stronger lattice energies and thus higher thermal stability compared to larger cations like Ca and Ba. Therefore, thermal stability generally decreases going from MgCO₃ to CaCO₃ to BaCO₃.
04

- Determining the Correct Order

Based on the analysis, the correct order of increasing thermal stability is: BaCO₃ < CaCO₃ < MgCO₃.
05

- Matching with Given Options

Compare the correct order with the provided options: (1) CaCO₃ > MgCO₃ > BaCO₃, (2) MgCO₃ > CaCO₃ > BaCO₃, (3) BaCO₃ > MgCO₃ > CaCO₃, and (4) BaCO₃ > CaCO₃ > MgCO₃. The correct match is option (2): MgCO₃ > CaCO₃ > BaCO₃.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Stability
Thermal stability is a key concept when discussing the decomposition of substances under heat. It specifically refers to the resistance of a compound against breaking down when exposed to high temperatures.

For metal carbonates like \(\text{BaCO}_3\), \(\text{CaCO}_3\), and \(\text{MgCO}_3\), thermal stability is largely influenced by the nature of the cation present.

The underlying principle here is the lattice energy— the energy required to break the ionic bonds in a solid. When the lattice energy is high, more energy is needed to decompose the compound, thus making it thermally stable.

In summary, compounds with higher lattice energies exhibit greater thermal stability, meaning they decompose at higher temperatures.
Carbonates Decomposition
When we talk about carbonates decomposition, we mean the process where carbonates (\text{CO}_3^{2-}) break down into their constituent elements when heated. This reaction generally produces metal oxides and carbon dioxide.

For example:
  • \(\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2\)
  • \(\text{MgCO}_3 \rightarrow \text{MgO} + \text{CO}_2\)
  • \(\text{BaCO}_3 \rightarrow \text{BaO} + \text{CO}_2\)


The ease of this decomposition depends on the strength of the bonds within the crystal lattice of the carbonate. Stronger bonds equate to higher thermal stability.

In our case, \text{MgCO}_3 decomposes at a higher temperature than \text{CaCO}_3 and \text{BaCO}_3, due to stronger ionic bonds resulting from the smaller size and higher charge density of the \(\text{Mg}^{2+}\) ion.
Cation Effect
The cation effect is crucial in determining the thermal stability of metal carbonates. The cation's size and charge density play significant roles in this context.

Here's what happens:
  • As you go down Group 2 in the periodic table, the cation size increases (from \(\text{Mg}^{2+}\) to \(\text{Ba}^{2+}\)).
  • Larger cations, such as \(\text{Ba}^{2+}\), have lower charge density and result in weaker electrostatic attractions in the crystal lattice.
  • This leads to lower lattice energy and, hence, lower thermal stability.

So, the trend in thermal stability for carbonates of Mg, Ca, and Ba is: \(\text{MgCO}_3 > \text{CaCO}_3 > \text{BaCO}_3\). Smaller cations like \(\text{Mg}^{2+}\) lead to higher lattice energies and greater stability against heat-induced decomposition.

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Most popular questions from this chapter

The group IIA elements of the periodic table (I) are called alkaline earth metals (II) are capable of forming coloured ions \(\mathrm{M}^{21}\) (III) are capable of forming colourless ions \(\mathrm{M}^{2}\) (IV) form volatile compounds of these (1) I, II and III are correct (2) I and IV are correct (3) I, II and IV arc correct (4) I and III are correct

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When bright shining magncsium is cxposed to wet air it becomes dull because (1) of the formation of \(\mathrm{MgO}\) or basic carbonate of magnesium (2) of the formation of \(\mathrm{Mg}_{3} \mathrm{~N}_{2}\) (3) of the formation of \(\mathrm{Mg}\left(\mathrm{NO}_{3}\right)\) (4) the moisture forms as a layer

The first ionization energies of alkaline earth metals are higher than those of alkali metals. This is because (1) there is increase in the nuclear charge of the alkaline earth metals (2) there is decrease in the nuclear charge of alkaline earth metals (3) there is no change in the nuclear charge (4) none of the above

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