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Pure sodium oxide can be prepared by heating (1) \(\mathrm{NaNO}_{3}\) with \(\mathrm{Na}\) (2) \(\mathrm{NaNO}_{2}\) with \(\mathrm{Na}\) (3) \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) with \(\mathrm{Na}\) (4) Both 1 and 2

Short Answer

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Both reactions (1) and (2) are valid for preparing pure sodium oxide.

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01

- Analyzing Sodium Nitrate Reaction

Consider the reaction of \( \mathrm{NaNO}_{3} \) with \( \mathrm{Na} \). \( \mathrm{NaNO}_{3} + 3 \mathrm{Na} \rightarrow \mathrm{Na}_2\mathrm{O} + N_2 \) and byproducts.
02

- Analyzing Sodium Nitrite Reaction

Consider the reaction of \( \mathrm{NaNO}_{2} \) with \( \mathrm{Na} \). \( \mathrm{NaNO}_{2} + 3 \mathrm{Na} \rightarrow \mathrm{Na}_2\mathrm{O} + N_2 \) and byproducts.
03

- Analyzing Sodium Carbonate Reaction

Consider the reaction of \( \mathrm{Na}_{2} \mathrm{CO}_{3} \) with \( \mathrm{Na} \). This reaction doesn't produce pure sodium oxide reliably.
04

- Conclusion

Both reactions (1) and (2) are valid methods for preparing pure sodium oxide by heating with sodium metal.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sodium nitrate reaction
Sodium nitrate (\text{NaNO}_3\text{) is a chemical compound that reacts with sodium (\text{Na}\text{) to form sodium oxide (\text{Na}_2\text{O}\text{) and nitrogen gas (\text{N}_2\text{) as the primary products. The reaction is as follows: \[\text{NaNO}_3 + 3\text{Na} \rightarrow \text{Na}_2\text{O} + \text{N}_2\text{\]. This process occurs when heated, and it's a reliable method to obtain pure sodium oxide. Sodium nitrate acts as an oxidizing agent, meaning it helps in the oxidation of sodium. Sodium in turn reduces the nitrate ion. The byproducts are typically trace amounts of other nitrogen oxides, but primarily, nitrogen gas is released. Given the efficiency and purity of the product, this chemical reaction is a practical way to synthesize sodium oxide in laboratory settings.
sodium nitrite reaction
Sodium nitrite (\text{NaNO}_2\text{) also reacts with sodium (\text{Na}\text{) to yield sodium oxide (\text{Na}_2\text{O}\text{) and nitrogen gas (\text{N}_2\text{). The reaction is represented by: \[\text{NaNO}_2 + 3\text{Na} \rightarrow \text{Na}_2\text{O} + \text{N}_2\text{\]. Similar to the sodium nitrate reaction, this reaction is completed upon heating. In this case, sodium nitrite serves as an oxidizing agent, facilitating the reduction of sodium while itself being reduced to form nitrogen gas. The purity of sodium oxide obtained through this method is comparable to that from the sodium nitrate reaction. However, the choice between using \text{NaNO}_3\text{ or \text{NaNO}_2\text{ often depends on other practical considerations such as availability, cost, and the specific requirements of the synthesis process.
sodium carbonate reaction
Sodium carbonate (\text{Na}_2\text{CO}_3\text{) reacts with sodium (\text{Na}\text{) but does not reliably produce pure sodium oxide (\text{Na}_2\text{O}\text{). The attempted reaction is: \[\text{Na}_2\text{CO}_3 + 2\text{Na} \rightarrow 3\text{Na}_2\text{O} + \text{CO}_2\text{\]. However, this reaction is often complicated by the formation of carbon dioxide (\text{CO}_2) and potential side reactions that can lead to impurities. Thus, it is not considered effective for preparing pure sodium oxide. The presence of carbonates and incomplete reaction can result in a mixture rather than the desired pure product. Therefore, for synthesizing pure sodium oxide, other methods such as the reactions using \text{NaNO}_3\text{ or \text{NaNO}_2\text{ are preferred.

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Most popular questions from this chapter

A standard solution of sodium hydroxide cannot be prepared by direct wcighing of cold sodium hydroxide because (1) NaOII is a solid (2) NaOII is a liquid (3) NaOII is casily dissolved (4) NaOII is a deliquescent substance

The compounds \(\mathrm{X}\) and \(\mathrm{Y}\) are obtained by the reaction \(\mathrm{of} \mathrm{C} \mathrm{l}_{2}\) with cold and dilute solution of \(\mathrm{NaOH}\) and \(\mathrm{X}\) and \(\mathrm{Z}\) are formed with hot and concentrated solution of \(\mathrm{NaOH}\). The \(\mathrm{Y}\) and \(\mathrm{Z}\) respectively are (1) \(\mathrm{NaCl}, \mathrm{NaClO}_{3}\) (2) \(\mathrm{NaClO}, \mathrm{NaClO}_{3}\) (3) \(\mathrm{NaCl}, \mathrm{NaClO}\) (4) \(\mathrm{NaC} 1 \mathrm{O}, \mathrm{HCl}\)

\(0.242 \mathrm{~g}\) sample of potassium is heated in oxygen. The result is \(0.44\) of a crystalline compound. What is the formula of this compound? (1) \(\mathrm{KO}\) (2) \(\mathrm{K}_{2} \mathrm{O}\) (3) \(\mathrm{KO}_{2}\) (4) \(\mathrm{KO}_{3}\)

Which of the following about compounds of lithium is false? (1) The hydroxide, carbonatc and nitrate decompose to give the oxide on heating. (2) It is the most clectroncgative clement of group I \(\Lambda\). (3) The hydrogen carbonate can be isolated in stable state. (4) It forms an oxidc but not a supcroxide.

Which of the following statements is wrong? (1) In Nelson's cell asbestos diaphragm is used because it is permeable to ions and prevents the reaction between \(\mathrm{NaOH}\) and \(\mathrm{Cl}_{2}\). (2) In Castner-Kellner cell, the anode in the middle compartment is mercury. (3) The products of the electrolysis of concentrated aqueous solution of common salt are \(\mathrm{NaOH}, \mathrm{H}_{2}\) and \(\mathrm{Cl}_{2}\). (4) The products formed during the electrolysis of brine at cathode, anode and in the solution are in the mole ratio \(1: 1: 1\).

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