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Sodium peroxide is uscd to purify the air in submarimes and confirmed spaces because (1) it decomposcs to form \(\mathrm{Na}_{2} \mathrm{O}\) and \(\mathrm{O}_{2}\) (2) it removes \(\mathrm{CO}_{2}\) and produce \(\mathrm{O}_{2}\) (3) it reacts with oxygen to form sodium superoxide (4) it kills the bacteria in air

Short Answer

Expert verified
Option (2): It removes CO2 and produces O2.

Step by step solution

01

Identify the Given Options

Review the given options to understand their significance: (1) It decomposes to form \(\text{Na}_2\text{O}\) and \(\text{O}_2\), (2) It removes \(\text{CO}_2\) and produces \(\text{O}_2\), (3) It reacts with oxygen to form sodium superoxide, (4) It kills bacteria in the air.
02

Analyze Each Option

Determine the validity of each statement based on chemical reactions and properties of sodium peroxide: \(\text{Na}_2\text{O}_2\).
03

Check the Decomposition Reaction

Analyze option (1): \(\text{Na}_2\text{O}_2 \rightarrow \text{Na}_2\text{O} + \text{O}_2\). This statement is correct but it does not describe why it purifies air.
04

Evaluate the CO2 Removal and O2 Production

Analyze option (2): \(\text{Na}_2\text{O}_2 + \text{CO}_2 \rightarrow \text{Na}_2\text{CO}_3 + \text{O}_2\). This reaction explains how sodium peroxide purifies air by removing \(\text{CO}_2\) and generating \(\text{O}_2\).
05

Consider the Reaction with Oxygen

Analyze option (3): This involves forming sodium superoxide when reacting with oxygen, which is not related to air purification directly.
06

Verify the Bacteria Killing Hypothesis

Analyze option (4): While it might have some antibacterial properties, this is not the primary reason it purifies air.
07

Conclusion

Combine all the information from previous steps: Option (2) is the most relevant, as it directly explains how sodium peroxide purifies air by removing \(\text{CO}_2\) and producing \(\text{O}_2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sodium peroxide reactions
Sodium peroxide (\text{Na}_2\text{O}_2) is involved in several chemical reactions important for air purification. One of the key reactions is the decomposition of sodium peroxide into sodium oxide (\text{Na}_2\text{O}) and oxygen (\text{O}_2):
\[\text{Na}_2\text{O}_2 \rightarrow \text{Na}_2\text{O} + \text{O}_2 \]
This reaction, while producing oxygen, does not directly contribute to air purification. However, it is noteworthy because the oxygen generated here can be utilized to sustain life in enclosed spaces like submarines.
removal of carbon dioxide
A critical aspect of air purification in confined environments is dealing with carbon dioxide (\text{CO}_2) buildup. Sodium peroxide excels at removing \text{CO}_2} through a significant chemical reaction:
\[\text{Na}_2\text{O}_2 + \text{CO}_2 \rightarrow \text{Na}_2\text{CO}_3 + \text{O}_2 \]
In this reaction, sodium peroxide reacts with carbon dioxide to form sodium carbonate (\text{Na}_2\text{CO}_3}) and oxygen (\text{O}_2). By transforming \text{CO}_2} into \text{Na}_2\text{CO}_3, it effectively reduces the concentration of this gas in the air, which is otherwise harmful in high amounts.
production of oxygen
The production of oxygen is another vital function that sodium peroxide serves in air purification. The decomposition of sodium peroxide not only clears carbon dioxide but also generates oxygen:
\[\text{Na}_2\text{O}_2 \rightarrow \text{Na}_2\text{O} + \text{O}_2 \]
Beyond this, the reaction with carbon dioxide also releases oxygen:
\[\text{Na}_2\text{O}_2 + \text{CO}_2 \rightarrow \text{Na}_2\text{CO}_3 + \text{O}_2 \]
Both reactions ensure a consistent supply of oxygen, which is crucial for breathing in submarine and other confined spaces.
chemical air purification
Chemical air purification involves using chemical reactions to remove impurities and produce clean air. In submarines, sodium peroxide plays a pivotal role in this process.
The primary mechanism is its reaction with carbon dioxide to form an innocuous compound and release oxygen:
\[\text{Na}_2\text{O}_2 + \text{CO}_2 \rightarrow \text{Na}_2\text{CO}_3 + \text{O}_2 \]
This dual-action response, both removing \text{CO}_2} and generating \text{O}_2}, makes sodium peroxide an effective substance for maintaining a breathable atmosphere in confined environments. This process is fundamental to ensuring the health and safety of people in spaces like submarines.

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Most popular questions from this chapter

There is loss of weight when a mixture of \(\mathrm{Li}_{2} \mathrm{CO}_{3}\) and \(\mathrm{Na}_{2} \mathrm{CO}_{3} .10 \mathrm{H}_{2} \mathrm{O}\) is heated strongly. This loss is due to (1) \(\mathrm{Li}_{2} \mathrm{CO}_{3}\) due to decomposition into \(\mathrm{Li}_{2} \mathrm{O}\) and gascous \(\mathrm{CO}_{2}\). (2) Both \(\mathrm{Li}_{2} \mathrm{CO}_{3}\) and \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) decompose to \(\mathrm{Li}_{2} \mathrm{O}\) and \(\mathrm{Na}_{2} \mathrm{O}\) losing gascous \(\mathrm{CO}_{2}\). (3) Due to loss of \(\mathrm{CO}_{2}\) from \(\mathrm{Li}_{2} \mathrm{CO}_{3}\) and water from \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}\) (4) Due to sublimation of \(\mathrm{Li}_{2} \mathrm{CO}_{3}\)

Which of the following fluorides are sparingly soluble in water? (1) LiF (2) \(\mathrm{NaF}\) (3) CsF (4) KF

Identify the false statement regarding the solutions of alkali metals in ammonia. (1) The blue colour, paramagnetic character and reduction properties of the solution are due to ammoniated electrons. (2) The conduetivity is due to both ammoniated electrons and ammoniated metal ions. (3) Evaporation of the solution in the absence of catalyst or impurities gives metal amides. (4) The conductivity of saturated solutions is normally equal to the metal dissolved in ammonia.

Which of the following is correct regarding solutions of sodium metal in liquid ammonia? (1) The solutions are generally blue coloured, good conductors of electricity and conductivity decreases as temperature rises. (2) The solutions are paramagnetic but paramagnetic character decreases as concentration of solution is increased. (3) When \(\mathrm{NH}_{4} \mathrm{Cl}\) solid is added to such a solution, \(\mathrm{NaCl}\) is precipitated. (4) All the above are correct.

An inorganic compound first melts, then resolidifies and then liberates a gas. It may be (1) \(\mathrm{KClO}_{3}\) (2) \(\mathrm{KMnO}_{4}\) (3) \(\mathrm{Al}_{2} \mathrm{O}_{3}\) (4) \(\mathrm{MnO}_{2}\)

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