Chapter 10: Problem 56
Excess of dilute sodium hydroxide solution is gradually added with shaking to an aqueous solution of zinc sulphate or aluminium sulphatc. What would you obscrve? (1) A permanent white precipitate is formed immediately. (2) A white precipitate appears which dissolves to give a colourless solution. (3) No change in the beginning but later a white precipitate is formed on standing. (4) No change takes place and the solution remains clear.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
formation of precipitates
Initially, the hydroxide ions (OH⁻) from the sodium hydroxide react with the metal ions (Zn²⁺ or Al³⁺). This reaction produces insoluble hydroxides, Zn(OH)₂ and Al(OH)₃. These hydroxides cannot dissolve in water and, therefore, form a white precipitate.
In practical terms, this means if you observe the solution, you will see a cloudy mixture or sediment due to the formation of these solid hydroxides. This is the visual cue for precipitation.
solubility of hydroxides
When the sodium hydroxide is added in excess, these metal hydroxides interact further. For zinc hydroxide, the reaction can be:
Zn(OH)₂ + 2NaOH → Na₂[Zn(OH)₄]
For aluminium hydroxide, it can be:
Al(OH)₃ + NaOH → Na[Al(OH)₄]
Both reactions lead to the formation of complex anions that are soluble in water. The initial white precipitate dissolves, producing a clear and colorless solution. This increased solubility upon adding excess NaOH is a key observation in these chemical reactions.
chemical reactions
These reactions follow these steps:
- Sodium hydroxide provides hydroxide ions (OH⁻).
- These ions react with metal ions (Zn²⁺ or Al³⁺) to form insoluble hydroxides (Zn(OH)₂ or Al(OH)₃).
- Initially, a white precipitate forms as these hydroxides separate out from the solution.
- Upon adding excess sodium hydroxide, these hydroxides dissolve forming soluble complex ions.
The chemical equations representing these reactions are:
- For zinc: ZnSO₄ + 2NaOH → Zn(OH)₂ + Na₂SO₄ followed by Zn(OH)₂ + 2NaOH → Na₂[Zn(OH)₄]
- For aluminium: Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄ followed by Al(OH)₃ + NaOH → Na[Al(OH)₄]
Understanding these chemical reactions helps predict the sequence of visual changes in the mixtures and the reasoning behind the solution becoming clear again after initially becoming cloudy.