Chapter 1: Problem 94
Chlorophyll contains \(2.68 \%\) of magnesium. The number of magnesium atoms present in 2 g of chlorophyll is (1) \(1.34 \times 10^{21}\) (2) \(6 \times 10^{20}\) (3) \(5.34 \times 10^{22}\) (4) \(5.34 \times 10^{23}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Percentage Composition
In the context of chlorophyll, we're concerned with magnesium's percentage composition.
When we say that chlorophyll contains 2.68% magnesium, it means that in every 100 grams of chlorophyll, there are 2.68 grams of magnesium.
This percentage allows us to calculate the mass of magnesium when we know the total mass of chlorophyll.
Let's walk through the calculation from the exercise:
- First, we knew the mass of chlorophyll (2 grams). Using the percentage (2.68%), we calculated the mass of magnesium: \(\text{Mass of Mg} = 2 \text{g} \times \frac{2.68}{100} = 0.0536 \text{g}\)
Mole Concept
A mole (abbreviated as mol) is a quantity that contains exactly \(6.022 \times 10^{23}\) entities (Avogadro's number).
When we have the mass of a substance and its molar mass (mass of one mole), we can find the number of moles.
For magnesium, with a molar mass of 24.305 g/mol, we can determine the number of moles in 0.0536 grams: \(\text{Moles of Mg} = \frac{0.0536 \text{g}}{24.305 \text{g/mol}} \approx 0.002205 \text{moles}\).
Avogadro's Number
Once we know the number of moles of a substance, Avogadro's number allows us to find the exact number of atoms or molecules.
- For example, in the exercise, we calculated the moles of magnesium to be 0.002205. Multiplying by Avogadro's number gives us the number of atoms: \(0.002205 \text{moles} \times 6.022 \times 10^{23} \text{ atoms/mole} \approx 1.33 \times 10^{21} \text{ atoms}\).