Question

How many moles of atoms are present in onc mole of \(\mathrm{CII}_{3} \mathrm{COOII}\) molecule? (1) 2 moles of \(\mathrm{C}\) atoms, 4 moles of \(\mathrm{H}\) atoms, 2 moles of \(\mathrm{O}\) atoms (2) 1 mole of \(C\) atoms, 2 moles of \(\mathrm{H}\) atoms, 1 mole of \(\mathrm{O}\) atoms (3) 2 moles of \(\mathrm{C}\) atoms, 3 moles of \(\mathrm{H}\) atoms, 2 moles of \(O\) atoms (4) None

Short answer

None

Step-by-step solution

Analyze the given molecule

The given molecule is \( \text{CII}_{3} \text{COOII} \). It's necessary to determine the types and numbers of different atoms in the molecule.

Identify the number of atoms of each element in the molecule

Break down the molecular formula into its individual components: \( \text{CII}_{3} \text{COOII} \). Here: \(\text{CII}_{3} \) indicates 3 Carbon atoms and \( \text{COOII} \) indicates 2 Carbon atoms, 2 Oxygen atoms, and (presumably) 4 Hydrogen atoms, although check if there's a typo in the molecule formula given.

Sum the number of atoms for each element

Since there are 3 Carbon atoms in \( \text{CII}_{3} \) and 1 more in \(\text{COOII} \), the total is 3 + 1 = 4 Carbon atoms. There are 4 Hydrogens in \( \text{COOII} \). And 2 Oxygens in the whole formula.

Determine moles per mole of compound

Since we are considering 1 mole of \( \text{CII}_{3} \text{COOII} \), each atom quantity we have is already in moles. Thus, for one mole of the compound, we have 4 moles of Carbon, 4 moles of Hydrogen, and 2 moles of Oxygen.

Compare to given choices

Refer to the given options: (1) 2 moles of \(\text{C} \) atoms, 4 moles of \(\text{H} \) atoms, 2 moles of \(\text{O} \) atoms; (2) 1 mole of \(\text{C} \) atoms, 2 moles of \(\text{H} \) atoms, 1 mole of \(\text{O} \) atoms; (3) 2 moles of \(\text{C} \) atoms, 3 moles of \(\text{H} \) atoms, 2 moles of \(\text{O} \) atoms. None of these match our result.

Key concepts

molecular formula

A molecular formula tells us the exact number of different atoms in a molecule. It is essential to understand this before counting atoms and moles.

In our example, the molecular formula is \(\text{CII}_{3}\text{COOII}\). This needs to be carefully read to identify how many of each type of atom it contains.

Such formulas indicate the exact number of atoms in the smallest unit of the compound. Thus, knowing how to interpret them is the key to solving the question correctly.

chemical elements

Chemical elements are substances consisting of one type of atom. They are listed in the periodic table, and each element has a unique symbol, like C for carbon, H for hydrogen, and O for oxygen.

Understanding these symbols helps in recognizing how many atoms of each type are present in a molecule.

When breaking down the given formula \(\text{CII}_{3} \text{COOII}\), we see the components are carbon (C), hydrogen (H), and oxygen (O).

Recognizing these elements helps streamline the counting process and makes the problem manageable.

mole concept

The mole concept is a fundamental unit in chemistry for measuring the amount of substance. One mole equals Avogadro's number, which is approximately \(6.022 \times 10^{23}\) entities (atoms, molecules, etc.).

The beauty here is that if you have a molecular formula, like \(\text{CII}_{3} \text{COOII} \), understanding and using the mole concept allows you to calculate the number of atoms in a given mole of a substance easily.

In one mole of our molecule, we simply count the number of each type of atom specified. Thus, 4 moles of Carbon, 4 moles of Hydrogen, and 2 moles of Oxygen in this case.

atom counting

Atom counting involves breaking down the molecular formula to determine the number of each atom present.

For the exercise, you first recognize \(\text{CII}_{3}\) gives us 3 Carbon atoms, and \(\text{COOII}\) should mean 1 more Carbon, 2 Oxygen, and potentially a typo for Hydrogen, but we'll treat it carefully by hypothesizing 4 Hydrogens.

Summing these gives us the counts for each element. If counting seems confusing, practice with simpler molecules like \(H_2O\) to build confidence.

Always recheck your work to avoid mistakes, which is critical in this type of exercise.