Chapter 9: Problem 25
Write chemical reactions to justify that hydrogen peroxide can function as an oxidising as well as reducing agent.
Short Answer
Expert verified
Hydrogen peroxide can act as both an oxidizing agent (e.g., reducing \( \text{I}^- \) to \( \text{I}_2 \)) and a reducing agent (e.g., oxidizing itself to produce \( \text{O}_2 \)).
Step by step solution
01
Understanding the Role of Hydrogen Peroxide as an Oxidizing Agent
In an oxidation reaction, a substance causes another substance to lose electrons, and itself gets reduced. Hydrogen peroxide \( \text{H}_2\text{O}_2 \) acts as an oxidizing agent by gaining electrons and is reduced to water \( \text{H}_2\text{O} \). Consider the reaction with iodide ions \( \text{I}^- \): \[ \text{H}_2\text{O}_2 + 2\text{I}^- + 2\text{H}^+ \rightarrow 2\text{H}_2\text{O} + \text{I}_2 \]In this process, \( \text{H}_2\text{O}_2 \) is reduced to \( \text{H}_2\text{O} \), while \( \text{I}^- \) is oxidized to \( \text{I}_2 \).
02
Understanding the Role of Hydrogen Peroxide as a Reducing Agent
In a reduction reaction, a substance causes another substance to gain electrons, and itself gets oxidized. Hydrogen peroxide \( \text{H}_2\text{O}_2 \) acts as a reducing agent by releasing electrons and is oxidized to oxygen \( \text{O}_2 \). Consider the reaction with potassium permanganate \( \text{KMnO}_4 \) in acidic solution:\[ 2\text{MnO}_4^- + 6\text{H}^+ + 5\text{H}_2\text{O}_2 \rightarrow 2\text{Mn}^{2+} + 8\text{H}_2\text{O} + 5\text{O}_2 \]Here, \( \text{H}_2\text{O}_2 \) is oxidized to \( \text{O}_2 \), and \( \text{MnO}_4^- \) is reduced to \( \text{Mn}^{2+} \).
03
Conclusion on Amphoteric Nature of Hydrogen Peroxide
By analyzing the reactions, it's clear that hydrogen peroxide can donate electrons and be oxidized or accept electrons and be reduced. This dual behavior shows that hydrogen peroxide acts both as an oxidizing agent and a reducing agent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidizing Agent
Hydrogen peroxide is a compound often used in oxidation reactions, which are processes where an element or compound loses electrons. In this role, hydrogen peroxide, denoted as \( \text{H}_2\text{O}_2 \), functions as an oxidizing agent by accepting electrons from other substances. By doing so, it itself is reduced, meaning it receives electrons and changes to a lower oxidative state. In the example with iodide ions \( \text{I}^- \), we see this behavior clearly:
\[ \text{H}_2\text{O}_2 + 2\text{I}^- + 2\text{H}^+ \rightarrow 2\text{H}_2\text{O} + \text{I}_2 \]
In this equation, hydrogen peroxide accepts electrons to form water \( \text{H}_2\text{O} \), demonstrating its role as an oxidizing agent. Meanwhile, iodide ions lose electrons and are oxidized to iodine \( \text{I}_2 \).
When utilizing hydrogen peroxide as an oxidizing agent, it is important to remember that the substance that gives away electrons is being oxidized, while the one accepting electrons, like hydrogen peroxide, is being reduced.
\[ \text{H}_2\text{O}_2 + 2\text{I}^- + 2\text{H}^+ \rightarrow 2\text{H}_2\text{O} + \text{I}_2 \]
In this equation, hydrogen peroxide accepts electrons to form water \( \text{H}_2\text{O} \), demonstrating its role as an oxidizing agent. Meanwhile, iodide ions lose electrons and are oxidized to iodine \( \text{I}_2 \).
When utilizing hydrogen peroxide as an oxidizing agent, it is important to remember that the substance that gives away electrons is being oxidized, while the one accepting electrons, like hydrogen peroxide, is being reduced.
Reducing Agent
Apart from being an oxidizing agent, hydrogen peroxide can also serve as a reducing agent in chemical reactions. A reducing agent is a substance that donates electrons to another compound, causing that compound to be reduced, while the reducing agent itself gets oxidized.
An excellent example of hydrogen peroxide functioning as a reducing agent is its reaction with potassium permanganate \( \text{KMnO}_4 \) in acidic conditions:
\[ 2\text{MnO}_4^- + 6\text{H}^+ + 5\text{H}_2\text{O}_2 \rightarrow 2\text{Mn}^{2+} + 8\text{H}_2\text{O} + 5\text{O}_2 \]
Here, \( \text{H}_2\text{O}_2 \) donates electrons, becoming oxidized to oxygen \( \text{O}_2 \). Meanwhile, the \( \text{MnO}_4^- \) ions are reduced to \( \text{Mn}^{2+} \).
In essence, a reducing agent like hydrogen peroxide helps other substances gain electrons but ends up losing electrons itself. This dual ability in chemistry is what distinguishes compounds like hydrogen peroxide in redox reactions.
An excellent example of hydrogen peroxide functioning as a reducing agent is its reaction with potassium permanganate \( \text{KMnO}_4 \) in acidic conditions:
\[ 2\text{MnO}_4^- + 6\text{H}^+ + 5\text{H}_2\text{O}_2 \rightarrow 2\text{Mn}^{2+} + 8\text{H}_2\text{O} + 5\text{O}_2 \]
Here, \( \text{H}_2\text{O}_2 \) donates electrons, becoming oxidized to oxygen \( \text{O}_2 \). Meanwhile, the \( \text{MnO}_4^- \) ions are reduced to \( \text{Mn}^{2+} \).
In essence, a reducing agent like hydrogen peroxide helps other substances gain electrons but ends up losing electrons itself. This dual ability in chemistry is what distinguishes compounds like hydrogen peroxide in redox reactions.
Redox Reactions
Redox reactions are chemical reactions involving the transfer of electrons between two substances. The term 'redox' stands for reduction-oxidation, highlighting that a redox reaction consists of one substance being oxidized (losing electrons) and another being reduced (gaining electrons).
Hydrogen peroxide is a unique compound due to its ability to participate in redox reactions both as an oxidizing and reducing agent.
With hydrogen peroxide, observing both its reduction (acting as an oxidizing agent) and oxidation (acting as a reducing agent), tells us about its versatile skill in balancing and facilitating these reactions.
Hydrogen peroxide is a unique compound due to its ability to participate in redox reactions both as an oxidizing and reducing agent.
Key Characteristics of Redox Reactions:
- Involves electron transfer between two substances.
- Includes two half-reactions: oxidation where electrons are lost, and reduction where electrons are gained.
- Demonstrates conservation of charge, meaning total charge changes are balanced across the reaction.
With hydrogen peroxide, observing both its reduction (acting as an oxidizing agent) and oxidation (acting as a reducing agent), tells us about its versatile skill in balancing and facilitating these reactions.