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Irreversible Inhibition of an Enzyme Many enzymes are inhibited irreversibly by heavy metal ions such as \(\mathrm{Hg}^{2+}, \mathrm{Cu}^{2+}\), or \(\mathrm{Ag}^{+}\), which can react with essential sulfhydryl groups to form mercaptides: $$ \text { Enz-SH }+\mathrm{Ag}^{+} \rightarrow \text { Enz-S-Ag }+\mathrm{H}^{+} $$ The affinity of \(\mathrm{Ag}^{+}\)for sulfhydryl groups is so great that \(\mathrm{Ag}^{+}\) can be used to titrate - SH groups quantitatively. An investigator added just enough \(\mathrm{AgNO}_{3}\) to completely inactivate a \(10.0 \mathrm{~mL}\) solution containing \(1.0 \mathrm{mg} / \mathrm{mL}\) enzyme. A total of \(0.342 \mu \mathrm{mol}\) of \(\mathrm{AgNO}_{3}\) was required. Calculate the minimum molecular weight of the enzyme. Why does the value obtained in this way give only the minimum molecular weight?

Short Answer

Expert verified
The enzyme's minimum molecular weight is approximately 29,240 g/mol. This is the minimum value because the calculation assumes all sulfhydryl groups belong to one enzyme molecule.

Step by step solution

01

Understanding the Reaction

In the given reaction, each mole of enzyme's sulfhydryl group (Enz-SH) reacts with one mole of silver ion (\(\mathrm{Ag}^{+}\)) to form a product and release a hydrogen ion (\(\mathrm{H}^{+}\)). The chemical equation is \[\text { Enz-SH }+\mathrm{Ag}^{+} \rightarrow \text { Enz-S-Ag }+\mathrm{H}^{+}\] This one-to-one reaction ratio is critical for calculating the enzyme's minimum molecular weight.
02

Calculate Total Enzyme Mass

The enzyme solution has a concentration of 1.0 mg/mL. For a total volume of 10.0 mL, the total mass of the enzyme becomes:\[\text{Total enzyme mass} = \text{concentration} \times \text{volume} = 1.0 \text{ mg/mL} \times 10.0 \text{ mL} = 10 \text{ mg}\].
03

Convert Enzyme Mass to Moles of Sulfhydryl Group

We are given that 0.342 \(\mu\text{mol}\) of \(\mathrm{AgNO}_{3}\) was used to inactivate the enzyme completely, which means 0.342 \(\mu\text{mol}\) of enzyme's sulfhydryl groups were titrated. This represents the moles of the enzyme because each active sulfhydryl group reacts with one silver ion according to the balanced equation.
04

Find Minimum Molecular Weight

Using the mass of the enzyme (10 \(\text{mg}\) or 0.010 \(\text{g}\)) and the moles of enzyme (0.342 \(\mu\text{mol}\) or 0.342\(\times10^{-6}\) \text{mol}), calculate the minimum molecular weight as:\[\text{Molecular weight} = \frac{\text{mass in grams}}{\text{moles}} = \frac{0.010 \text{ g}}{0.342 \times 10^{-6} \text{ mol}} \approx 29,240 \text{ g/mol}\].
05

Explanation of Minimum Molecular Weight

The value gives the minimum molecular weight because each \(\mathrm{Ag}^{+}\) ion can react with only one sulfhydryl group on the enzyme. If an enzyme contains multiple sulfhydryl groups, it will react with multiple \(\mathrm{Ag}^{+}\) ions, implying each count of \(\mathrm{Ag}^{+}\) titrates only the number of active sulfhydryl sites but not the entire enzyme, thus providing the minimum molecular weight estimation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Irreversible Inhibition
Irreversible inhibition is a process where an enzyme's activity is permanently reduced or stopped. This occurs when a molecule binds covalently with the active site on the enzyme. One common example of irreversible inhibition involves heavy metal ions. These ions, such as mercury
  • Act by binding strongly to the active site.
  • Alter the enzyme structure, preventing it from functioning.
In the case of our exercise, heavy metal ions irreversibly bind to sulfhydryl groups, a vital component of many enzymes, through the formation of stable complexes. This binding is strong and cannot be undone by removing the heavy metal ion. As a result, the enzyme is permanently inactivated, which is why the inhibition is termed 'irreversible.' Understanding this principle is crucial for determining how heavy metal ions affect enzyme functions in biological systems.
Heavy Metal Ions
Heavy metal ions are atoms of metals with a relatively high atomic mass and density. Known for their reactive nature, some common examples include mercury
  • Mercury ( Hg^{2+} )
  • Copper ( Cu^{2+} )
  • Silver ( Ag^{+} )
These ions are renowned inhibitors of enzymes due to their propensity to react with sulfhydryl groups. Heavy metals possess a high affinity for these groups, resulting in the formation of stable complexes called mercaptides, effectively blocking the enzyme's active sites. Such interactions render the enzymes inactive, contributing to the irreversible inhibition seen in many biochemical reactions. Additionally, the unique reactivity of heavy metals with sulfhydryl groups allows for their use in titration experiments, helping scientists determine structural features of certain proteins.
Sulfhydryl Groups
Sulfhydryl groups are functional components in many proteins and enzymes and are represented by the -SH chemical group. These groups are highly reactive due to the presence of sulfur and are crucial for maintaining the structural integrity and function of proteins. When a heavy metal ion, such as Ag^{+} , interacts with an enzyme, it targets these sulfhydryl groups. The reaction forms a stable compound, often leading to the enzyme's inactivation. Sulfhydryl groups can be found in the side chain of amino acids like cysteine. A key function of these groups is forming disulfide links that help stabilize protein structure. Their reactivity also makes them instrumental in titration experiments that estimate enzymes' active sites and, consequently, their minimum molecular weight.
Molecular Weight Calculation
Molecular weight calculation is an essential part of understanding enzyme and protein behavior. By determining the molecular weight of an enzyme, researchers can infer properties such as the number of active sites. In the provided exercise,
  • The enzyme mass is 10 mg (or 0.010 g).
  • The amount of AgNO_{3} used gives moles of enzyme's sulfhydryl groups (0.342 \mumol).
To find the minimum molecular weight, divide the enzyme mass by the moles of sulfhydryl groups: \[\text{Molecular weight} = \frac{0.010 \text{ g}}{0.342 \times 10^{-6} \text{ mol}} \approx 29,240 \text{ g/mol}\]This estimate gives the minimum molecular weight because it assumes each enzyme molecule has at most one sulfhydryl group. If the enzyme has multiple sulfhydryl groups, the actual molecular weight would be higher, as each sulfhydryl group can independently bind to a heavy metal ion.

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Most popular questions from this chapter

Estimation of \(V_{\max }\) and \(\boldsymbol{K}_{\mathrm{m}}\) by Inspection Graphical methods are available for accurate determination of the \(V_{\max }\) and \(K_{\mathrm{m}}\) of an enzyme-catalyzed reaction. However, these quantities can sometimes be estimated by inspecting values of \(V_{0}\) at increasing [S]. Estimate the \(V_{\max }\) and \(K_{m}\) of the enzyme-catalyzed reaction for which the data in the table were obtained. \begin{tabular}{cc} {\([\mathbf{S}](\mathrm{M})\)} & \(V_{0}(\mu \mathrm{M} / \mathrm{min})\) \\ \hline \(2.5 \times 10^{-6}\) & 28 \\ \(4.0 \times 10^{-6}\) & 40 \end{tabular} \begin{tabular}{ll} \(1 \times 10^{-5}\) & 70 \\ \(2 \times 10^{-5}\) & 95 \\ \(4 \times 10^{-5}\) & 112 \\ \(1 \times 10^{-4}\) & 128 \\ \(2 \times 10^{-3}\) & 140 \\ \(1 \times 10^{-2}\) & 139 \\ \hline \end{tabular}

Intracellular Concentration of Enzymes To approximate the concentration of enzymes in a bacterial cell, assume that the cell contains equal concentrations of 1,000 different enzymes in solution in the cytosol and that each protein has a molecular weight of 100,000 . Assume also that the bacterial cell is a cylinder (diameter \(1.0 \mu \mathrm{m}\), height \(2.0 \mu \mathrm{m}\) ), that the cytosol (specific gravity \(1.20\) ) is \(20 \%\) soluble protein by weight, and that the soluble protein consists entirely of enzymes. Calculate the average molar concentration of each enzyme in this hypothetical cell.

The Effects of Reversible Inhibitors The MichaelisMenten rate equation for reversible mixed inhibition is written as $$ V_{0}=\frac{V_{\max }[\mathrm{S}]}{\alpha K_{\mathrm{m}}+\alpha^{\prime}[\mathrm{S}]} $$ Apparent, or observed, \(K_{\mathrm{m}}\) is equivalent to the [S] at which $$ V_{0}=\frac{V_{\max }}{2 \alpha^{\prime}} $$ Derive an expression for the effect of a reversible inhibitor on apparent \(K_{\mathrm{m}}\) from the previous equation.

Kinetic Inhibition Patterns Indicate how the observed \(K_{\mathrm{m}}\) of an enzyme would change in the presence of inhibitors having the given effect on \(a\) and \(\alpha^{\prime}\) : a. \(\alpha>\alpha^{\prime} ; \alpha^{\prime}=1.0\) b. \(\alpha^{\prime}>\alpha\) c. \(\alpha=\alpha^{\prime} ; \alpha^{\prime}>1.0\) d. \(\alpha=\alpha^{\prime} ; \alpha^{\prime}=1.0\)

Rate Enhancement by Urease The enzyme urease enhances the rate of urea hydrolysis at \(\mathrm{pH} 8.0\) and \(20{ }^{\circ} \mathrm{C}\) by a factor of \(10^{14}\). Suppose that a given quantity of urease can completely hydrolyze a given quantity of urea in \(5.0 \mathrm{~min}\) at \(20^{\circ} \mathrm{C}\) and \(\mathrm{pH} 8.0\). How long would it take for this amount of urea to be hydrolyzed under the same conditions in the absence of urease? Assume that both reactions take place in sterile systems so that bacteria cannot attack the urea.

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