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An antibody with high affinity for its antigen has a \(K_{\mathrm{d}}\) in the low nanomolar range. Assume an antibody binds an antigen with a \(K_{\mathrm{d}}\) of \(5 \times 10^{-8}\) M. Calculate the antigen concentration when \(Y\), the fraction of binding sites occupied by the ligand, is a. \(0.4\), b. \(0.5\), c. \(0.8\), d. \(0.9\).

Short Answer

Expert verified
For \(Y = 0.4\), \([L] = 3.33 \times 10^{-8}\ M\); for \(Y = 0.5\), \([L] = 5 \times 10^{-8}\ M\); for \(Y = 0.8\), \([L] = 2 \times 10^{-7}\ M\); for \(Y = 0.9\), \([L] = 4.5 \times 10^{-7}\ M\).

Step by step solution

01

Understanding the Binding Equation

To solve this problem, use the equation for the fraction of binding sites occupied (\(Y\)): \[ Y = \frac{[L]}{K_d + [L]} \] where \([L]\) is the concentration of the ligand (antigen), \(K_d\) is the dissociation constant, and \(Y\) is the fraction of occupied binding sites.
02

Rearranging the Equation

Rearrange the equation to solve for the antigen concentration \([L]\): \[ [L] = \frac{Y \times K_d}{1 - Y} \] This formula will be used to calculate \([L]\) for different values of \(Y\).
03

Step 3a: Calculate for Y = 0.4

Substitute \(Y = 0.4\) and \(K_d = 5 \times 10^{-8} \text{ M}\) into the rearranged equation: \[ [L] = \frac{0.4 \times 5 \times 10^{-8}}{1 - 0.4} = \frac{2 \times 10^{-8}}{0.6} = 3.33 \times 10^{-8} \text{ M} \].
04

Step 3b: Calculate for Y = 0.5

Substitute \(Y = 0.5\) and \(K_d = 5 \times 10^{-8} \text{ M}\) into the rearranged equation: \[ [L] = \frac{0.5 \times 5 \times 10^{-8}}{1 - 0.5} = \frac{2.5 \times 10^{-8}}{0.5} = 5 \times 10^{-8} \text{ M} \]
05

Step 3c: Calculate for Y = 0.8

Substitute \(Y = 0.8\) and \(K_d = 5 \times 10^{-8} \text{ M}\) into the rearranged equation: \[ [L] = \frac{0.8 \times 5 \times 10^{-8}}{1 - 0.8} = \frac{4 \times 10^{-8}}{0.2} = 2 \times 10^{-7} \text{ M} \].
06

Step 3d: Calculate for Y = 0.9

Substitute \(Y = 0.9\) and \(K_d = 5 \times 10^{-8} \text{ M}\) into the rearranged equation: \[ [L] = \frac{0.9 \times 5 \times 10^{-8}}{1 - 0.9} = \frac{4.5 \times 10^{-8}}{0.1} = 4.5 \times 10^{-7} \text{ M} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Antibody-Antigen Interaction
Antibodies and antigens are like partners in a dance. Their interaction is central to the immune response, which helps protect the body from pathogens. Antibodies are proteins that recognize specific molecules called antigens on the surface of foreign invaders like viruses and bacteria. This recognition is highly specific, with antibodies binding only to their target antigens much like a lock and key.

The site on the antigen where the antibody binds is called the epitope, while the part of the antibody that attaches is known as the paratope. When an antibody encounters its corresponding antigen, they form a complex. This binding can trigger a series of immune system responses aimed at neutralizing the pathogen.

Understanding this interaction is vital not only in immunology, but also in medical applications such as immunotherapy and vaccine development. By exploiting antibody-antigen interactions, scientists can develop treatments that specifically target diseased cells or pathogens without affecting healthy cells.
Dissociation Constant (K_d)
The dissociation constant, represented as \(K_d\), is a crucial parameter in understanding binding affinity in biochemistry. It essentially measures how tightly a ligand, like an antigen, binds to a protein, such as an antibody. A small \(K_d\) value indicates a strong binding affinity, meaning the ligand and protein form a stable complex that doesn't dissociate easily, whereas a larger \(K_d\) would suggest weaker binding.

In the context of antibody-antigen interactions, \(K_d\) quantifies the equilibrium between the bound and unbound states of the antibody and antigen. Specificity and high affinity are key for any diagnostic tool or therapeutic drug development involving antibodies. Simply put, the \(K_d\) value helps researchers and clinicians understand if a given antibody will effectively "stick" to its target antigen in the body.

Calculating \(K_d\) can involve methods like surface plasmon resonance or isothermal titration calorimetry. It's important for understanding the effectiveness of potential drugs and for optimizing antibody design to ensure they bind effectively to their target.
Ligand Binding
Ligand binding refers to the interaction between a ligand, typically a small molecule or ion, and a specific site on a biomolecule like a protein. This interaction is fundamental in numerous biological processes and plays a central role in molecular recognition events.

In the case of antibodies, ligands are usually antigens. The principles of ligand binding can be nicely described using the equation \( Y = \frac{[L]}{K_d + [L]} \), where \(Y\) is the fraction of occupied binding sites, \([L]\) is the ligand concentration, and \(K_d\) is the dissociation constant. This equation helps predict how much of the antibody will bind to the antigen under different concentrations.

A good grasp of ligand binding is crucial for pharmacology and drug design. The aim is to develop compounds that have high affinities for their targets, thereby ensuring they are effective even at low doses. By adjusting ligands to be more specific and have stronger binding interactions, scientists can develop more effective treatments with fewer side effects.

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Most popular questions from this chapter

Studies of oxygen transport in pregnant mammals show that the \(\mathrm{O}_{2}\) saturation curves of fetal and maternal blood are markedly different when measured under the same conditions. Fetal erythrocytes contain a structural variant of hemoglobin, HbF, consisting of two \(a\) and two \(\gamma\) subunits \(\left(\alpha_{2} \gamma_{2}\right)\), whereas maternal erythrocytes contain \(\mathrm{HbA}\left(\alpha_{2} \beta_{2}\right)\). a. Which hemoglobin has a higher affinity for oxygen under physiologic conditions? b. What is the physiological significance of the different \(\mathrm{O}_{2}\) affinities? When all the BPG is carefully removed from samples of \(\mathrm{HbA}\) and \(\mathrm{HbF}\), the measured \(\mathrm{O}_{2}\)-saturation curves (and consequently the \(\mathrm{O}_{2}\) affinities) are displaced to the left. However, HbA now has a greater affinity for oxygen than does HbF. When BPG is reintroduced, the \(\mathrm{O}_{2}\)-saturation curves return to normal, as shown in the graph. c. What is the effect of BPG on the \(\mathrm{O}_{2}\) affinity of hemoglobin? How can this information be used to explain the different \(\mathrm{O}_{2}\) affinities of fetal and maternal hemoglobin?

The \(E\). coli nickel-binding protein binds to its ligand, \(\mathrm{Ni}^{2+}\), with a \(K_{\mathrm{d}}\) of \(100 \mathrm{~nm}\). Calculate the \(\mathrm{Ni}^{2+}\) concentration when the fraction of binding sites occupied by the ligand \((Y)\) is (a) \(0.25\), (b) \(0.6\), (c) \(0.95 .\)

Protein A has a binding site for ligand \(\mathrm{X}\) with a \(K_{\mathrm{d}}\) of \(3.0 \times 10^{-7}\) ?. Protein \(\mathrm{B}\) has a binding site for ligand \(\mathrm{X}\) with a \(K_{\mathrm{d}}\) of \(4.0 \times 10^{-8} \mathrm{M}\). Calculate the \(K_{\mathrm{a}}\) for each protein. Which protein has a higher affinity for ligand X? Explain your reasoning.

Which of these situations would produce a Hill plot with \(n_{\mathrm{H}}<1.0\) ? Explain your reasoning in each case. a. The protein has multiple subunits, each with a single ligand-binding site. Ligand binding to one site decreases the binding affinity of other sites for the ligand. b. The protein is a single polypeptide with two ligandbinding sites, each having a different affinity for the ligand. c. The protein is a single polypeptide with a single ligand-binding site. As purified, the protein preparation is heterogeneous, containing some protein molecules that are partially denatured and thus have a lower binding affinity for the ligand. d. The protein has multiple subunits, each with a single ligand-binding site. Ligands bind independently to each site, do not affect the binding affinity of other sites, and bind with identical affinities.

To fully appreciate how proteins function in a cell, it is helpful to have a threedimensional view of how proteins interact with other cellular components. Fortunately, this is possible using online protein databases and three- dimensional molecular viewing utilities such as JSmol, a free and user- friendly molecular viewer that is compatible with most browsers and operating systems. In this exercise, examine the interactions between the enzyme lysozyme and the Fab portion of the antilysozyme antibody. Use the PDB identifier 1FDL to explore the structure of the IgG1 Fab fragment-lysozyme complex (antibody- antigen complex). To answer the questions, use the information on the Structure Summary page at the Protein Data Bank (www.rcsb.org), and view the structure using JSmol or a similar viewer. a. Which chains in the three-dimensional model correspond to the antibody fragment, and which correspond to the antigen, lysozyme? b. What type of secondary structure predominates in this Fab fragment? c. How many amino acid residues are in the heavy and light chains of the Fab fragment? In lysozyme? Estimate the percentage of the lysozyme that interacts with the antigen- binding site of the antibody fragment. d. Identify the specific amino acid residues in lysozyme and in the variable regions of the Fab heavy and light chains that are situated at the antigen- antibody interface. Are the residues contiguous in the primary sequence of the polypeptide chains?

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