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What is the minimum number of transesterification reactions needed to splice an intron from a pre-mRNA transcript? Explain.

Short Answer

Expert verified
Two transesterification reactions are needed to splice an intron from pre-mRNA.

Step by step solution

01

Understanding Transesterification

Transesterification is a reaction where a hydroxyl group attacks a phosphodiester bond, causing cleavage and reformation of the bond. In splicing, these reactions rearrange the RNA to remove introns.
02

Identifying Splicing Process

In the process of splicing, introns are removed from an RNA sequence, and exons are joined together. This typically involves two main transesterification reactions.
03

First Transesterification Reaction

The first transesterification occurs when the 2'-hydroxyl group of the adenosine within the branch site attacks the 5' splice site at the exon-intron junction, creating a lariat structure with the intron.
04

Second Transesterification Reaction

The second transesterification involves the 3'-hydroxyl of the upstream exon attacking the 3' splice site, which leads to the excision of the intron in a lariat form and joining of the exons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transesterification
Transesterification is a fascinating chemical reaction pivotal to RNA splicing. It involves a hydroxyl group performing a nucleophilic attack on a phosphodiester bond. This attack is all about rearranging chemical bonds, which is crucial for RNA modification.
In simpler terms, it helps to stitch together the exons, the coding sections of RNA, by cleaving and forming new bonds.

In RNA splicing, there are two key transesterification reactions:
  • The first one sets the stage by forming a loop-like structure called a lariat with the intron.
  • The second reaction ultimately cuts out the intron and stitches the exons back together.
These steps are essential for creating a functional messenger RNA (mRNA) ready to be translated into proteins.
pre-mRNA processing
The journey of pre-mRNA to becoming mature mRNA is a crucial part of gene expression. Pre-mRNA is the raw transcript directly synthesized from DNA. It includes both introns and exons.
This transcript initially contains sequences that need to be removed and processed; thus, it undergoes significant modifications, known as pre-mRNA processing.

This processing involves:
  • Capping: Adding a 7-methylguanylate cap at the 5’ end to stabilize the mRNA.
  • Polyadenylation: Adding a poly-A tail at the 3’ end, which protects the mRNA from degradation.
  • Splicing: Removing introns and joining exons to produce a continuous coding sequence.
This meticulous processing ensures that only the necessary coding portions are translated into proteins.
Intron Removal
The removal of introns from RNA is a critical step in creating a functional mRNA molecule. Introns are non-coding regions in the RNA transcript that need to be excised before the RNA can be translated into a protein.

During splicing, introns are removed in a two-step process involving transesterification reactions:
  • Lariat Formation: The first transesterification reaction forms a lariat structure, effectively looping out the intron.
  • Exon Joining: The second reaction cuts out the intron and joins the exons, leaving a linear RNA ready for translation.
These precise reactions ensure the RNA is error-free and retains only the necessary coding sequences for protein synthesis.

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Most popular questions from this chapter

The gene encoding the \(E\). coli enzyme enolase begins with the sequence ATGTCCAAAATCGTA. What is the sequence of the RNA transcript specified by this part of the gene?

In eukaryotes, premRNA splicing by the spliceosome occurs only in the nucleus and translation of mRNAs occurs only in the cytosol. Why might the separation of these two activities into different cellular compartments be important?

DNA polymerases are capable of editing and error correction, whereas the capacity for error correction in RNA polymerases seems to be limited. Given that a single base error in either replication or transcription can lead to an error in protein synthesis, suggest a possible biological explanation for this difference.

While studying human transcription in the 1960s, James Darnell carried out an experiment that has become a classic in biochemistry, but at the time, it was incredibly perplexing. Darnell and coworkers used radioactive isotopes, such as \({ }^{32} \mathrm{P}\) ]-labeled phosphate, to isolate and quantify RNAs from a cultured line of human cancer cells (HeLa). With this approach, they were able to identify those RNAs present in the nucleus and those present in the cytoplasm. The results were puzzling, because it was obvious that a large amount of transcription was occurring in the nucleus, but comparatively little radioactive mRNA was isolated from the cytoplasm. Moreover, the nuclear- isolated RNAs were much longer than those isolated from the cytoplasm. What can account for these observations?

The RNA genome of phage \(Q \beta\) is the nontemplate strand, or coding strand, and when introduced into the cell, it functions as an mRNA. Suppose the RNA replicase of phage \(\mathrm{Q} \beta\) synthesized primarily template-strand RNA and uniquely incorporated this, rather than nontemplate strands, into the viral particles. What would be the fate of the template strands when they entered a new cell? What enzyme would have to be included in the viral particles for successful invasion of a host cell?

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