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Function of DNA Ligase Some \(E\). coli mutants contain defective DNA ligase. When researchers expose these mutants to \({ }^{3} \mathrm{H}\)-labeled thymine and then sediment the DNA produced on an alkaline sucrose density gradient, two radioactive bands appear. One corresponds to a high molecular weight fraction, the other to a low molecular weight fraction. Explain.

Short Answer

Expert verified
Defective DNA ligase in mutants leads to incomplete ligation, resulting in both high and low molecular weight DNA fragments in the density gradient.

Step by step solution

01

Understanding DNA Ligase Function

DNA ligase is an enzyme that facilitates the joining of DNA strands together by catalyzing the formation of a phosphodiester bond. It is crucial for completing the process of DNA replication by joining Okazaki fragments on the lagging strand and sealing nicks in DNA. In mutants with defective DNA ligase, these joining processes are impaired.
02

Sedimentation in Alkaline Sucrose Density Gradient

When DNA is exposed to an alkaline sucrose density gradient, it is separated based on molecular weight and sedimentation velocity. High molecular weight DNA strands sediment faster and form a distinct band, while lower molecular weight DNA forms a lighter band that sediments more slowly.
03

Analyzing the Appearance of Radioactive Bands

In the case of the described E. coli mutants, the two radioactive bands observed represent different fractions of DNA. The high molecular weight band correlates with complete DNA strands that include joined Okazaki fragments, despite some defects. The low molecular weight band corresponds to single, unjoined Okazaki fragments due to the mutants' inability to effectively ligate DNA strands together.
04

Interpretation of Results

The presence of a low molecular weight radioactive band indicates that, in the absence of functional DNA ligase, DNA replication is incomplete, resulting in the accumulation of unligated Okazaki fragments. This is why there are two distinct bands: one from the fragmented and another from the joined DNA pieces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

DNA replication
DNA replication is the fundamental process of copying a cell's DNA to ensure that each new cell has a complete set of genetic information. This is essential for cell division and growth. DNA replication takes place in several steps:
  • Initiation: Starts at specific sequences called origins of replication.
  • Elongation: New strands of DNA are synthesized by DNA polymerases.
  • Termination: Process ends when the entire DNA molecule has been replicated.
Special enzyme activities ensure that replication is both accurate and efficient. DNA polymerases are essential as they add nucleotides to form new DNA strands. However, they can only add bases in one direction, which leads to the formation of Okazaki fragments on the lagging strand.
Okazaki fragments
Okazaki fragments are short sequences of DNA nucleotides synthesized discontinuously and later linked together during DNA replication. These fragments form on the lagging strand, which is synthesized in the opposite direction of the replication fork's movement. This backward directionality necessitates periodic priming and synthesis of new fragments:
  • Each Okazaki fragment begins with an RNA primer synthesized by primase.
  • DNA polymerase extends the fragment until it reaches the previous primer.
  • After which, RNA primers are removed and replaced with DNA.
Finally, DNA ligase seals the gaps between adjacent fragments, forming a continuous DNA strand. Mutations affecting ligase can lead to incomplete or abnormal DNA replication.
Escherichia coli mutants
Escherichia coli, commonly known as E. coli, is a bacterium often used in scientific research due to its relative simplicity and prevalence. In experiments with E. coli mutants, especially those with defective enzymes such as DNA ligase, researchers can observe how important these proteins are for cellular processes. If the mutants contain defective DNA ligase, crucial steps in DNA replication can be disrupted.
  • Inability to effectively join Okazaki fragments.
  • Accumulation of gaps within the DNA sequence.
  • Potential errors in DNA synthesis and repair processes.
These mutants can thus provide insight into both the normal function of DNA replication enzymes and the effects of their failure.
Phosphodiester bond formation
Phosphodiester bonds are the chemical linkages between the sugar-phosphate backbone of DNA and RNA strands. They are essential for maintaining the structural integrity of nucleic acid molecules. During DNA replication, DNA ligase catalyzes the formation of these bonds to link the 3' hydroxyl end of one nucleotide with the 5' phosphate end of another. This process is crucial for sealing nicks left after Okazaki fragments are synthesized.
  • Without these bonds, DNA strands would not remain intact.
  • They ensure continuity and stability of the DNA molecule.
  • Defective phosphodiester bond formation can lead to unstable genetic material.
Thus, mutations that impair ligase function can result in incomplete DNA replication and a buildup of fragmented DNA, as observed in certain E. coli mutants.

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Most popular questions from this chapter

DNA Replication Kornberg and his colleagues incubated soluble extracts of \(E\). coli with a mixture of dATP, dTTP, dGTP, and dCTP, all labeled with \({ }^{32} \mathrm{P}\) in the \(a\)-phosphate group. After a time, they treated the incubation mixture with trichloroacetic acid, which precipitates the DNA but not the nucleotide precursors. They then collected the precipitate and determined the extent of precursor incorporation into DNA from the amount of radioactivity present in the precipitate. a. If any one of the four nucleotide precursors were omitted from the incubation mixture, would radioactivity be found in the precipitate? Explain. b. Would \({ }^{32} \mathrm{P}\) be incorporated into the DNA if only dTTP were labeled? Explain. c. Would radioactivity be found in the precipitate if \({ }^{32} \mathrm{P}\) labeled the \(\beta\) phosphate or \(\gamma\) phosphate rather than the \(a\) phosphate of the deoxyribonucleotides? Explain.

Activities of DNA Polymerases You are characterizing a new DNA polymerase. When you incubate the enzyme with \({ }^{32} \mathrm{P}\)-labeled DNA and no dNTPs, you observe the release of \(\left[{ }^{32} \mathrm{P}\right] \mathrm{dNMPs}\). The addition of unlabeled dNTPs prevents this release. Explain the reactions that most likely underlie these observations. What would you expect to observe if you added pyrophosphate instead of dNTPs?

Heavy Isotope Analysis of DNA Replication A researcher switches a culture of \(E\). coli growing in a medium containing \({ }^{15} \mathrm{NH}_{4} \mathrm{Cl}\) to a medium containing \({ }^{14} \mathrm{NH}_{4} \mathrm{Cl}\) for three generations (an eightfold increase in population). What is the molar ratio of hybrid DNA \(\left({ }^{15} \mathrm{~N}^{-14} \mathrm{~N}\right)\) to light DNA \(\left({ }^{14} \mathrm{~N}^{-14} \mathrm{~N}\right)\) at this point?

Fidelity of Replication of DNA What factors promote the fidelity of replication during synthesis of the leading strand of DNA? Would you expect the lagging strand to be made with the same fidelity? Give reasons for your answers.

The Chemistry of DNA Replication All DNA polymerases synthesize new DNA strands in the \(5^{\prime} \rightarrow 3^{\prime}\) direction. In some respects, replication of the antiparallel strands of duplex DNA would be simpler if there were also a second type of polymerase, one that synthesized DNA in the \(3^{\prime} \rightarrow 5^{\prime}\) direction. The two types of polymerase could, in principle, coordinate DNA synthesis without the complicated mechanics required for lagging strand replication. However, no such \(3^{\prime} \rightarrow 5^{\prime}\)-synthesizing enzyme has been found. Suggest two possible mechanisms for \(3^{\prime} \rightarrow 5^{\prime}\) DNA synthesis. Pyrophosphate should be one product of both proposed reactions. Could one or both mechanisms be supported in a cell? Why or why not? (Hint: You may suggest the use of DNA precursors not actually present in extant cells.)

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