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DNA Replication Kornberg and his colleagues incubated soluble extracts of \(E\). coli with a mixture of dATP, dTTP, dGTP, and dCTP, all labeled with \({ }^{32} \mathrm{P}\) in the \(a\)-phosphate group. After a time, they treated the incubation mixture with trichloroacetic acid, which precipitates the DNA but not the nucleotide precursors. They then collected the precipitate and determined the extent of precursor incorporation into DNA from the amount of radioactivity present in the precipitate. a. If any one of the four nucleotide precursors were omitted from the incubation mixture, would radioactivity be found in the precipitate? Explain. b. Would \({ }^{32} \mathrm{P}\) be incorporated into the DNA if only dTTP were labeled? Explain. c. Would radioactivity be found in the precipitate if \({ }^{32} \mathrm{P}\) labeled the \(\beta\) phosphate or \(\gamma\) phosphate rather than the \(a\) phosphate of the deoxyribonucleotides? Explain.

Short Answer

Expert verified
a. No, without one precursor, DNA can't form. b. Yes, if dTTP is labeled, it incorporates radioactivity into DNA. c. No, \(\beta\) or \(\gamma\) labeled phosphates won't be in DNA.

Step by step solution

01

Understanding DNA Precipitation Process

When Kornberg used trichloroacetic acid to treat the reaction mixture, it precipitated out DNA by separating it from free nucleotide precursors. The incorporation of radioactivity into the DNA can be measured based on the radioactivity of the precipitate.
02

Analyzing the Absence of a Nucleotide Precursor (Part a)

If any one of the four nucleotide precursors (dATP, dTTP, dGTP, dCTP) is missing, DNA polymerization cannot proceed, because DNA synthesis requires all four nucleotides to form a complete chain. Thus, no DNA would form, and the precipitate would lack radioactivity.
03

Labeling Specificity for Radioactivity Incorporation (Part b)

For radioactivity to be found in the DNA, the labeled phosphate must be incorporated into the DNA structure. If only dTTP is labeled, it will be integrated into DNA strands during polymerization, thus radioactivity would be found in DNA, as dTTP is part of DNA.
04

Phosphate Position Impact on Radioactivity (Part c)

The \ \(a\) phosphate is incorporated into the growing DNA chain, while \ the \ \(beta\) and \ \(gamma\) phosphates are released as pyrophosphate. Thus, for radioactivity to be incorporated into DNA, the \(a\) phosphate must be labeled. If only the \(beta\) or \(gamma\) phosphates are labeled, no radioactivity would be detected in DNA.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nucleotide Precursors
Simplifying the concept of nucleotide precursors helps clarify their essential role in DNA replication. Nucleotide precursors are the building blocks of DNA, much like bricks are to a house. These precursors are incredibly specific and include the four nucleotides: *dATP*, *dTTP*, *dGTP*, and *dCTP*.
Each nucleotide plays a unique role, and all are needed to construct a complete DNA strand. Imagine trying to build a wall with bricks of only three types instead of four; it simply wouldn't hold up. Likewise, in DNA replication, if any one of these nucleotide precursors is absent, DNA polymerization cannot occur because a full set is required for the synthesis phase. This means that if the replication process is missing just one nucleotide precursor, no proper DNA strand can be formed, leading to the absence of radioactivity in the precipitate.
Radioactive Labeling
To understand radioactive labeling in DNA experiments, imagine tracing a thread through an intricate web. This method is a powerful tool for detecting the incorporation of molecules like nucleotides during DNA replication.
In Kornberg’s experiment, they used nucleotides labeled with ( ^{32} P ) – a radioactive isotope of phosphorus. This labeling primarily targeted the alpha ( α ) phosphate group, assuming it's incorporated into the DNA strand.
The idea here is quite straightforward: as the labeled nucleotide becomes part of the newly synthesized DNA, the radioactivity is retained and detectable. If only specific nucleotides like dTTP are labeled, you can track its inclusion directly into the DNA. This leads to radioactive detection in the precipitate, proving successful integration into the DNA strands during replication.
DNA Polymerization
DNA polymerization is akin to assembling a chain, where nucleotide precursors act as individual links joined together to form a complete DNA molecule. This process is facilitated by enzymes known as DNA polymerases.
These enzymes are responsible for adding nucleotides to the growing DNA strand in the sequence specified by the template strand. This sequential linking follows the base-pairing rules and continues until the new DNA strand is fully formed.
Without correct and complete nucleotide precursors, DNA polymerization cannot proceed. Therefore, the absence of even one type of nucleotide prevents the complete synthesis of a DNA chain, halting the polymerization process entirely. This highlights the precision and necessity of all building blocks in successful DNA replication.
Phosphate Groups
Phosphate groups are critical to understanding how DNA builds up during replication. In nucleotide structures, phosphates occupy important positions: (α), (β), and (γ) phosphates.
The alpha ( α ) phosphate group is the only one integrated into the DNA backbone during DNA synthesis. The other two, β and γ phosphates, are released as a molecule of pyrophosphate during this process.
Imagine writing with a pencil and then sharpening it. As you add to the page (DNA), the sharpened point (α phosphate) stays, while the shavings (β and γ phosphates) are discarded.
If radioactive labels target the β or γ phosphates instead of the α phosphate, those labels won’t make their way into the DNA chain, and thus their radioactivity would not appear in DNA precipitates. Such targeting explains the need for precise labeling for accurate experimental results.

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Most popular questions from this chapter

The Chemistry of DNA Replication All DNA polymerases synthesize new DNA strands in the \(5^{\prime} \rightarrow 3^{\prime}\) direction. In some respects, replication of the antiparallel strands of duplex DNA would be simpler if there were also a second type of polymerase, one that synthesized DNA in the \(3^{\prime} \rightarrow 5^{\prime}\) direction. The two types of polymerase could, in principle, coordinate DNA synthesis without the complicated mechanics required for lagging strand replication. However, no such \(3^{\prime} \rightarrow 5^{\prime}\)-synthesizing enzyme has been found. Suggest two possible mechanisms for \(3^{\prime} \rightarrow 5^{\prime}\) DNA synthesis. Pyrophosphate should be one product of both proposed reactions. Could one or both mechanisms be supported in a cell? Why or why not? (Hint: You may suggest the use of DNA precursors not actually present in extant cells.)

DNA Repair Mechanisms Vertebrate and plant cells often methylate cytosine in DNA to form 5-methylcytosine (see \(\underline{\text { Fig. }}\) 8-5a). In these same cells, a specialized repair system recognizes \(\mathrm{G}-\mathrm{T}\) mismatches and repairs them to \(\mathrm{G} \equiv \mathrm{C}\) base pairs. How might this repair system be advantageous to the cell? (Explain in terms of the presence of 5-methylcytosine in the DNA.)

Leading and Lagging Strands Prepare a table that lists the names and compares the functions of the precursors, enzymes, and other proteins needed to make the leading strand versus the lagging strand during DNA replication in \(E\). coli.

Activities of DNA Polymerases You are characterizing a new DNA polymerase. When you incubate the enzyme with \({ }^{32} \mathrm{P}\)-labeled DNA and no dNTPs, you observe the release of \(\left[{ }^{32} \mathrm{P}\right] \mathrm{dNMPs}\). The addition of unlabeled dNTPs prevents this release. Explain the reactions that most likely underlie these observations. What would you expect to observe if you added pyrophosphate instead of dNTPs?

The Ames Test In a nutrient medium that lacks histidine, a thin layer of agar containing \(\sim 10^{9}\) Salmonella typhimurium histidine auxotrophs (mutant cells that require histidine to survive) produces \(\sim 13\) colonies over a two-day incubation period at \(37^{\circ} \mathrm{C}\) (see Eig \(25-19\) ). How do these colonies arise in the absence of histidine? When investigators repeat the experiment in the presence of \(0.4 \mu \mathrm{g}\) of 2 -aminoanthracene, the number of colonies produced over two days exceeds 10,000 . What does this indicate about 2-aminoanthracene? What can you surmise about its carcinogenicity?

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