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pH and Drug Absorption Asp?rin is a weak acid with a \(p K_{n}\) of \(3.5\) (the ionizable \(H\) is shown in red): Aspirin is absorbed into the blood through the cells lining the stomach and the small intestine. Absorption requires passage through the plasma membrane. The polarity of the molecule determines the absorption rate: charged and highly polar molecules pass slowly, whereas neutral hydrophobic molecules pass rapidly. The \(\mathrm{pH}\) of the stomach contents is about \(1.5\), and the \(\mathrm{pH}\) of the contents of the small intestine is about 6. Rased on this information, is more aspirin absorbed into the bloodstream from the stomach or from the small intestine? Clearly justify your choice

Short Answer

Expert verified
More aspirin is absorbed in the stomach due to its neutral form at pH 1.5.

Step by step solution

01

Understand the Chemistry

Aspirin, being a weak acid, will donate protons more readily in an acidic environment. The ionizable hydrogen (H) allows aspirin to exist in its protonated form (neutral) or deprotonated form (charged). The degree of ionization depends on the pH of the environment and the pKa of the acid.
02

Determine the Ionization

The Henderson-Hasselbalch equation can help us determine the ratio of ionized to non-ionized aspirin. It is expressed as: \[pH = pK_a + \log \left(\frac{[A^-]}{[HA]}\right) \]where \([A^-]\) is the deprotonated form (ionized) and \([HA]\) is the protonated form (neutral).
03

Calculate for the Stomach

Given the pH in the stomach is 1.5 and the pKa of aspirin is 3.5, we can rearrange the equation:\[1.5 = 3.5 + \log \left(\frac{[A^-]}{[HA]}\right) \]Solving, we find:\[\log \left(\frac{[A^-]}{[HA]}\right) = 1.5 - 3.5 = -2\]This implies \([A^-]/[HA] = 10^{-2} = 0.01\), indicating a ratio of 1 ionized aspirin to 100 neutral aspirins.
04

Calculate for the Small Intestine

For the small intestine, where the pH is 6:\[6 = 3.5 + \log \left(\frac{[A^-]}{[HA]}\right) \]Solving, we find:\[\log \left(\frac{[A^-]}{[HA]}\right) = 6 - 3.5 = 2.5 \]This implies \([A^-]/[HA] = 10^{2.5} \approx 316.23\), suggesting 316 ionized aspirins for every 1 neutral aspirin.
05

Compare Absorption

In the stomach (pH 1.5), the majority of aspirin is in its neutral form, facilitating rapid passage through the nonpolar plasma membrane. In the small intestine (pH 6), most aspirin is ionized, making it less permeable. Hence, more aspirin is absorbed in the stomach.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Aspirin Absorption
Aspirin is a common pain-reliever that many people use, but its absorption into the bloodstream involves some interesting chemistry. The main point to understand is that aspirin is a weak acid. This means it can exist in two forms: a protonated (neutral) form and a deprotonated (charged) form.

The form that aspirin takes depends heavily on the environment it is in. Aspirin is mainly absorbed through the cells lining the stomach and the small intestine. Each of these environments has different pH levels, which influence how aspirin will exist at any given time.

In the stomach, where the pH is quite acidic at 1.5, aspirin remains largely in its neutral form. This makes it easier for aspirin to be absorbed because neutral molecules pass through the plasma membrane more readily than charged molecules.

On the other hand, the small intestine has a higher pH of about 6. In this environment, more aspirin molecules become charged and thus, less aspirin is absorbed here compared to the stomach. Understanding these basic principles can help explain why the stomach is more effective at absorbing aspirin.
Henderson-Hasselbalch Equation
The Henderson-Hasselbalch equation is a vital tool in biochemistry for understanding the degree of ionization of compounds like aspirin. This equation is useful because it links the pH of the environment with the pKa (a measure of the strength of an acid) of the compound.

The equation is expressed as follows:
\[ pH = pK_a + \log \left(\frac{[A^-]}{[HA]}\right) \]
Here, \[ [A^-] \] represents the concentration of the ionized form, and \[ [HA] \] represents the concentration of the protonated (neutral) form.

By using this equation, we can calculate the ratio of ionized to non-ionized aspirin in different environments. For example, in the stomach with a pH of 1.5, the equation helps demonstrate that most aspirin exists in its non-ionized, neutral form. On the contrary, in the small intestine with a pH of 6, the equation shows aspirin mainly in its ionized form.

Understanding how to apply the Henderson-Hasselbalch equation allows us to predict how well aspirin will be absorbed in varying pH conditions.
Ionization and pH
Ionization and pH are key concepts that influence drug absorption. When a weak acid like aspirin enters an acidic environment (such as the stomach), it tends to stay in its protonated (neutral) state. This is due to the low pH promoting the non-ionized form.

In contrast, a basic or higher pH environment (like the small intestine) leads to more ionization of aspirin, causing it to lose hydrogen ions and become charged.

Why is this important? Well, the form of the aspirin affects how easily it can pass through the plasma membrane. Neutral forms are usually more hydrophobic and can cross the lipid-rich plasma membrane with ease.

Charged forms are more polar and typically don't penetrate cell membranes as readily. This is why aspirin is absorbed more efficiently in the stomach, where it remains mostly neutral.

By grasping the relationship between ionization and pH, one can better understand the processes of drug absorption and efficacy.
Plasma Membrane Permeability
The plasma membrane plays a crucial role in drug absorption as it dictates which substances can enter the cell.

For substances like aspirin, understanding membrane permeability is essential. The plasma membrane consists of a lipid bilayer, which is selectively permeable. This means it favors the passage of small, nonpolar, or neutral molecules.

Given this, neutral aspirin molecules can cross the plasma membrane easily. In contrast, ionized molecules are more highly charged and polar, making it difficult for them to move through the nonpolar interior of the lipid bilayer.

In environments such as the acidic stomach, where aspirin is largely in its neutral form, the plasma membrane is more permeable to aspirin. On the other hand, in the basic environment of the small intestine, where aspirin is more ionized, membrane permeability is reduced, leading to less absorption.

It's essential to grasp that the permeability of the plasma membrane is central to understanding why aspirin is absorbed more efficiently in certain parts of the digestive tract.

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Most popular questions from this chapter

a. In what pH range can glycine be used as an effective buffer due to its amino group? b. In a \(0.1 \mathrm{~m}\) solution of glycine at pH \(9.0\), what fraction of glycine has its amino group in the \(-\mathrm{NH}_{3}^{4}\) form? c. How much \(5 \mathrm{M}\) KOH must be added to \(1.0 \mathrm{~L}\) of \(0.1 \mathrm{M}\) glycine at pH \(9.0\) to bring its pII to exactly \(10.0 ?\) d. When 9996 of the glycine is in ?ts \(-\mathrm{NH}_{3}^{+}\)form, what is the numerical relation between the pH of the solution and the p \(K_{\mathrm{n}}\) of the amino group? Properties of a Buffer The amino acid glycine is often used as the main ingredient of a buffer in biochemical experiments. The amino group of glycine, which has a \(\mathrm{p} K_{\mathrm{n}}\) of \(9.6\), can exist either in the protonated form \(\left(-\mathrm{NH}_{3}^{+}\right)\)or as the free base \(\left(-\mathrm{NH}_{2}\right)\), because of the reversible equilibrium $$ \mathrm{F}-\mathrm{NH}_{3}^{+} \rightleftharpoons \mathrm{H}-\mathrm{NH}_{2}+\mathrm{H}^{+} $$

Biological Advantage of Weak Interactions The associations between biomolecules are often stabilized by hydrogen bonds, electrostatic interactions, the hydrophobic effect, and van der Waals interactions. How are weak interactions such as these advantageous to an organism?

Relationship Between \(\mathrm{p} K_{\text {a }}\) and pH Which aqueous solution has the lowest pH: \(0.1 \mathrm{~m}\) hydrofluoric acid \(\left(\mathrm{p} K_{\mathrm{a}}=3.20\right) ; 0.1 \mathrm{M}\) acetic acid \(\left(\mathrm{p} K_{\mathrm{s}}=4.86\right) ; 0.1 \mathrm{~m}\) formic acid \(\left(\mathrm{p} K_{\mathrm{a}}=3.75\right) ;\) or \(0.1 \mathrm{~m}\) lactic acid \(\left(\mathrm{p} K_{\mathrm{a}}=7.86\right) ?\)

Calculation of the \(\mathrm{pH}\) of a Mixture of a Weak Acid and Its Conjugate Base Calculate the \(\mathrm{pH}\) of a dilute solution that contains a molar ratio of potassium acetate to acetic acid \(\left(\mathrm{p} K_{\mathrm{a}}=4.76\right)\) of a. \(2: 1\) b. \(1: 3 ;\) c. \(5: 1\) d. \(1: 1 ;\) e. \(1: 10\).

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