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The activation of free palmitate to its coenzyme A derivative (palmitoyl-CoA) in the cytosol occurs before it can be oxidized in the mitochondrion. After adding palmitate and \(\left[{ }^{14} \mathrm{C}\right]\) coenzyme A to a liver homogenate, you find palmitoyl-CoA isolated from the cytosolic fraction is radioactive, but that isolated from the mitochondrial fraction is not. Explain.

Short Answer

Expert verified
Palmitoyl-CoA is radioactive in the cytosol due to the labeled CoA but loses the label in mitochondrial isolation due to CoA recycling.

Step by step solution

01

Understand the Problem Context

Palmitate is a fatty acid that needs to be converted into its CoA derivative (palmitoyl-CoA) before it can be transported into the mitochondria for oxidation. The experiment involves using a radioactive form of coenzyme A, \([^{14}C]\) coenzyme A, to track the conversion process.
02

Analyze the Cytosolic Reaction

In the cytosol, palmitate is activated to palmitoyl-CoA, and because the coenzyme A used is radioactive, the resulting palmitoyl-CoA is also radioactive. This is why the palmitoyl-CoA isolated from the cytosolic fraction is found to be radioactive.
03

Evaluate the Mitochondrial Fraction

In the mitochondria, palmitoyl-CoA is involved in the beta-oxidation process to generate acetyl-CoA. As a result, the palmitoyl-CoA specifically formed in the mitochondria does not retain the radioactive label because the coenzyme units are recycled, and these processes typically use endogenous CoA which is not radioactive.
04

Conclude Why Mitochondrial Fraction is Non-radioactive

Since the radioactive label was only on the coenzyme A added initially and not on palmitate, and due to the recycling and use of endogenous CoA in the mitochondria, the palmitoyl-CoA isolated from the mitochondrial fraction lacks the radioactive label. The label only tracks the initial formation in the cytosol, not after subsequent changes or oxidation in the mitochondria.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Palmitoyl-CoA Activation
Fatty acids like palmitate must undergo an important transformation before they are ready for mitochondrial oxidation. This step is known as the activation of the fatty acid. In simple terms, palmitate is converted into palmitoyl-CoA in the cytosol—this process involves the attachment of coenzyme A (CoA) to the fatty acid. But why is this conversion necessary? Well, the CoA serves as a sort of "energy booster" for palmitate, making it chemically active and therefore ready to enter further metabolic processes. Initially, radioactively labeled \([^{14}C]\) coenzyme A is used in the process to monitor this reaction. As a result, the formed palmitoyl-CoA in the cytosol is also radioactive, providing us with a nifty way to track it as it progresses through fatty acid metabolism.
Beta-Oxidation
Once the fatty acid is in the form of palmitoyl-CoA, it can finally enter the mitochondria—a critical powerhouse in cells. This is where an important process called beta-oxidation takes place. Beta-oxidation is essentially a molecular "chopping room" where palmitoyl-CoA is broken down into smaller units. This process sequentially strips away acetyl-CoA units from the fatty acyl-CoA chain. These acetyl-CoA molecules are vital since they enter the citric acid cycle to produce ATP, the main energy currency of the cell. However, in our experiment, the key takeaway is to understand why the mitochondrial fraction lacks a radioactive label. This is because once inside the mitochondria, the CoA used in palmitoyl-CoA formation is often replaced by non-radioactive endogenous CoA for beta-oxidation, preventing the radioactive label from sticking around.
Coenzyme A Labeling
The incorporation of \([^{14}C]\) labeled coenzyme A serves a significant purpose in metabolic studies. By tagging coenzyme A with a radioactive isotope like \([^{14}C]\), researchers can trace the path of molecules through cellular processes with much greater clarity. But why don't the radioactive labels show up in the mitochondria? The simple answer lies in coenzyme A turnover. As palmitoyl-CoA enters the beta-oxidation pathway, the labeled CoA is detached and replaced by non-radioactive CoA produced within the mitochondria.Thus, even though the initially formed cytosolic palmitoyl-CoA was radioactive, the recycling of CoA during mitochondrial metabolism leads to a non-radioactive end product. This detail helps differentiate between where the labeling was applied and where it has been lost, turning our focus on the cytosolic processes and subsequent mitochondrial events.
Mitochondrial Transport
Before fatty acids can benefit from mitochondrial machinery, they require efficient transport into the mitochondria. However, direct transport of palmitoyl-CoA into mitochondria isn't feasible. Instead, cells employ a clever transporter molecule called carnitine. This enzyme helps convert palmitoyl-CoA into palmitoylcarnitine, allowing it easier access through the mitochondrial inner membrane. Once inside, palmitoylcarnitine is converted back into palmitoyl-CoA for more efficient beta-oxidation. This toggle between CoA and carnitine isn't just an exercise in molecular acrobatics—it’s essential for crossing the mitochondrial barrier. The lack of radioactivity inside the mitochondria from our experiment primarily results from the endogenous replacement of CoA units, within the last steps of this transport. Understanding this process clarifies why the mitochondrial fraction appears non-radioactive, and further illustrates how cells uniquely manage nutrient transport and processing.

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Most popular questions from this chapter

An individual developed a condition characterized by progressive muscular weakness and aching muscle cramps. The symptoms were aggravated by fasting, exercise, and a high-fat diet. An homogenate of a skeletal muscle specimen from the patient oxidized added oleate more slowly than did control homogenates consisting of muscle specimens from healthy individuals. When the pathologist added carnitine to the patient's muscle homogenate, the rate of oleate oxidation equaled that in the control homogenates. Based on these results, the attending physician diagnosed the patient as having a carnitine deficiency. a. Why did added carnitine increase the rate of oleate oxidation in the patient's muscle homogenate? b. Why did fasting, exercise, and a high-fat diet aggravate the patient's symptoms? c. Suggest two possible reasons for the deficiency of muscle carnitine in this individual.

Suppose you had to subsist on a diet of whale blubber and seal blubber, with little or no carbohydrate. a. What would be the effect of carbohydrate deprivation on the utilization of fats for energy? b. If your diet were totally devoid of carbohydrate, would it be better to consume odd- or even-number fatty acids? Explain.

The complete oxidation of palmitoylCoA to carbon dioxide and water is represented by the overall equation $$ \begin{gathered} \text { Palmitoyl-CoA }+23 \mathrm{O}_{2}+108 \mathrm{P}_{\mathrm{i}}+108 \mathrm{ADP} \rightarrow \\ \text { CoA }+16 \mathrm{CO}_{2}+108 \mathrm{ATP}+23 \mathrm{H}_{2} \mathrm{O} \end{gathered} $$ Water also forms in the reaction $$ \mathrm{ADP}+\mathrm{P}_{\mathrm{i}} \rightarrow \mathrm{ATP}+\mathrm{H}_{2} \mathrm{O} $$ but is not included as a product in the overall equation. Why?

What changes in metabolic pattern would result from a mutation in the muscle carnitine acyltransferase 1 in which the mutant protein has lost its affinity for malonyl-CoA but not its catalytic activity?

Effect of PDE Inhibitor on Adipocytes How would the addition of a cAMP phosphodiesterase (PDE) inhibitor affect the response of an adipocyte to epinephrine?

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