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Regulation of Glycogen Phosphorylase In muscle tissue, the rate of conversion of glycogen to glucose 6-phosphate is determined by the ratio of phosphorylase \(a\) (active) to phosphorylase \(b\) (less active). Determine what happens to the rate of glycogen breakdown if a broken cell extract of muscle containing glycogen phosphorylase is treated with (a) phosphorylase kinase and ATP (b) PP1 (c) epinephrine.

Short Answer

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(a) Increases, (b) Decreases, (c) Increases.

Step by step solution

01

Understanding Glycogen Phosphorylase

Glycogen phosphorylase exists in two forms: phosphorylase a (active) and phosphorylase b (less active). The conversion between these forms is regulated through phosphorylation and dephosphorylation processes. Phosphorylase a is phosphorylated, whereas phosphorylase b is not.
02

Effect of Phosphorylase Kinase and ATP

Phosphorylase kinase phosphorylates phosphorylase b using ATP, converting it to phosphorylase a. This increases the active phosphorylase a level, enhancing the rate of glycogen breakdown.
03

Effect of Protein Phosphatase 1 (PP1)

PP1 dephosphorylates phosphorylase a, converting it back to phosphorylase b. This decreases the active phosphorylase a level, reducing the rate of glycogen breakdown.
04

Effect of Epinephrine

Epinephrine triggers a signal transduction cascade that activates phosphorylase kinase. This leads to the phosphorylation of phosphorylase b, converting it to phosphorylase a, thereby increasing the glycogen breakdown rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phosphorylase Kinase
Phosphorylase kinase is a crucial enzyme in regulating glycogen metabolism. It plays a vital role in the conversion of glycogen phosphorylase from its inactive form, phosphorylase b, to its active form, phosphorylase a. This enzyme is activated by phosphorylation through a chain of events triggered by hormonal signals or muscle contraction. In the presence of ATP, phosphorylase kinase specifically targets phosphorylase b, attaching a phosphate group to it. Subsequently, this modification transforms phosphorylase b into the more active phosphorylase a form.

This catalytic action of phosphorylase kinase enhances the breakdown of glycogen by increasing the abundance of active glycogen phosphorylase a in muscle tissues. By boosting this process, muscles can efficiently access glucose for energy production, especially during physical activities. Overall, phosphorylase kinase serves as an essential regulator, integrating signals to modulate energy release in response to various cellular needs.
Protein Phosphatase 1 (PP1)
Protein Phosphatase 1 (PP1) works as a counterbalance to the action of phosphorylase kinase. Its role is to revert the effects of phosphorylation on glycogen phosphorylase. This enzyme carefully removes the phosphate group from phosphorylase a, converting it back to its less active form, phosphorylase b.

By dephosphorylating phosphorylase a, PP1 effectively decreases the rate of glycogen breakdown. This process is essential in scenarios where energy conservation is necessary, such as during rest or low-intensity activities. The action of PP1 ensures that glycogen reserves in muscle tissues are preserved for future use.

Overall, PP1 maintains glycogen homeostasis by controlling the balance between the active and inactive forms of glycogen phosphorylase, aiding in the regulation of energy reserves.
Signal Transduction Cascade
The signal transduction cascade is an intricate series of biochemical reactions initiated by external signals, such as hormones. In the context of glycogen breakdown, epinephrine serves as a primary signal, targeting muscle cells to initiate energy release.

Upon binding to specific receptors on muscle cells, epinephrine activates a series of intracellular pathways. These pathways typically involve molecules like cyclic AMP (cAMP) as secondary messengers. The activation of these molecules ultimately leads to the activation of phosphorylase kinase. Through this cascade, epinephrine amplifies the signal, ensuring a swift response across numerous cells.

This entire sequence of events results in the conversion of phosphorylase b to the more active phosphorylase a form, promoting glycogenolysis and providing the necessary energy for muscle activity. The signal transduction cascade highlights how external stimuli can efficiently regulate intracellular processes essential for survival.
Muscle Glycogen Metabolism
Muscle glycogen metabolism involves the strategic breakdown and synthesis of glycogen, a polysaccharide that serves as energy storage. The regulation of this metabolic pathway is crucial for maintaining energy availability during different physiological states.

During periods of high demand, such as exercise, glycogen phosphorylase is activated to degrade glycogen into glucose 6-phosphate. This compound is then utilized in glycolysis to produce ATP, meeting the immediate energy needs of muscles. Conversely, in rest states or after meals, glycogen synthesis is prioritized to replenish energy stores for future use.

The regulation of muscle glycogen metabolism is a balanced act performed by enzymes like glycogen synthase and glycogen phosphorylase, along with their activators and inhibitors. Efficient regulation ensures muscle cells can respond promptly to energy demands while conserving resources when the demand is low.

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Most popular questions from this chapter

Enzyme Activity and Physiological Function The \(V_{\max }\) of the glycogen phosphorylase from skeletal muscle is much greater than the \(V_{\max }\) of the same enzyme from liver tissue. a. What is the physiological function of glycogen phosphorylase in skeletal muscle? In liver tissue? b. Why does the \(V_{\max }\) of the muscle enzyme need to be greater than that of the liver enzyme?

13\. Optimal Glycogen Structure Muscle cells need rapid access to large amounts of glucose during heavy exercise. This glucose is stored in liver and skeletal muscle in polymeric form as particles of glycogen. The typical glycogen \(\beta\)-particle contains about 55,000 glucose residues (see Eig_ 15-2). Meléndez-Hevia, Waddell, and Shelton (1993), explored some theoretical aspects of the structure of glycogen, as described in this problem. a. The cellular concentration of glycogen in liver is about \(0.01 \mu \mathrm{M}\). What cellular concentration of free glucose would be required to store an equivalent amount of glucose? Why would this concentration of free glucose present a problem for the cell? Glucose is released from glycogen by glycogen phosphorylase, an enzyme that can remove glucose molecules, one at a time, from one end of a glycogen chain (see Eig. 15-3). Glycogen chains are branched (see Eig.15-2), and the degree of branching - the number of branches per chain - has a powerful influence on the rate at which glycogen phosphorylase can release glucose. b. Why would a degree of branching that was too low (i.e., below an optimum level) reduce the rate of glucose release? (Hint: Consider the extreme case of no branches in a chain of 55,000 glucose residues.) c. Why would a degree of branching that was too high also reduce the rate of glucose release? (Hint: Think of the physical constraints.) Meléndez-Hevia and colleagues did a series of calculations and found that two branches per chain (see Eig_15-2) was optimal for the constraints described above. This is what is found in glycogen stored in muscle and liver. To determine the optimum number of glucose residues per chain, Meléndez-Hevia and coauthors considered two key parameters that define the structure of a glycogen particle: \(t=\) the number of tiers of glucose chains in a particle (the mole-cule in Eig.15-2 has five tiers); \(g_{c}=\) the number of glucose residues in each chain. The \(y\) set out to find the values of \(t\) and \(g_{c}\) that would maximize three quantities: (1) the amount of glucose stored in the particle \(\left(G_{\mathrm{T}}\right)\) per unit volume; (2) the number of unbranched glucose chains \(\left(C_{A}\right)\) per unit volume (i.e., number of A chains in the outermost tier, readily accessible to glycogen phosphorylase); and (3) the amount of glucose available to phosphorylase in these unbranched chains \(\left(G_{\mathrm{PT}}\right)\). d. Show that \(C_{A}=2^{t-1}\). This is the number of chains available to glycogen phosphorylase before the action of the debranching enzyme. e. Show that \(C_{\mathrm{T}}\), the total number of chains in the particle, is given by \(C_{\mathrm{T}}=2^{t}-1\). For purposes of this calculation, consider the primers to be a single chain. Thus \(G_{\mathrm{T}}=g_{\mathrm{c}}\left(C_{\mathrm{T}}\right)=g_{c}\left(2^{t}-1\right)\), the total number of glucose residues in the particle. f. Glycogen phosphorylase cannot remove glucose from glycogen chains that are shorter than five glucose residues. Show that \(G_{\mathrm{PT}}=\left(g_{e}-4\right)\left(2^{t-1}\right)\). This is the amount of glucose readily available to glycogen phosphorylase.g. Based on the size of a glucose residue and the location of branches, the thickness of one tier of glycogen is \(0.12 g_{\mathrm{c}} \mathrm{nm}+0.35 \mathrm{~nm}\). Show that the volume of a particle, \(V_{5}\), is given by the equation $$ V_{\mathrm{s}}=4 / 3 \pi t^{3}\left(0.12 g_{\mathrm{c}}+0.35\right)^{3} \mathrm{~nm}^{3} $$ Meléndez-Hevia and coauthors then determined the optimum values of \(t\) and \(g_{c}\) - those that gave the maximum value of a quality function, \(f\), that maximizes \(G_{\mathrm{T}}, C_{A}\), and \(G_{P T}\), while minimizing \(V_{8}: f=\frac{G_{\mathrm{T}} C_{\mathrm{A}} G \mathrm{PT}}{V_{8}}\). They found that the optimum value of \(g_{c}\) is independent of \(t .\) h. Choose a value of \(t\) between 5 and 15 and find the optimum value of \(g_{\mathrm{c}}\). How does this compare with the \(g_{e}\) found in liver glycogen (see Egg.15-2)? (Hint: You may find it useful to use a spreadsheet program.)

Metabolic Effects of Mutant Enzymes Predict and explain the effect on glycogen metabolism of each of the listed defects caused by mutation: (a) Loss of the cAMPbinding site on the regulatory subunit of protein kinase A (PKA) (b) Loss of the protein phosphatase inhibitor (inhibitor 1 in Fig. 15-16) (c) Overexpression of phosphorylase \(b\) kinase in liver (d) Defective glucagon receptors in liver.

Hormonal Control of Metabolic Fuel Between your evening meal and breakfast, your blood glucose drops and your liver becomes a net producer rather than consumer of glucose. Describe the hormonal basis for this switch, and explain how the hormonal change triggers glucose production by the liver.

Glycogen Breakdown in Migrating Birds Unlike a rabbit, running all-out for a few moments to escape a predator, migratory birds require energy for extended periods of time. For example, ducks generally fly several thousand miles during their annual migration. The flight muscles of migratory birds have a high oxidative capacity and obtain the necessary ATP through the oxidation of acetyl-CoA (obtained from fats) via the citric acid cycle. Compare the regulation of muscle glycolysis during short-term intense activity, as in a fleeing rabbit, and during extended activity, as in a migrating duck. Why must the regulation in these two settings be different?

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