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Enzyme Activity and Physiological Function The \(V_{\max }\) of the glycogen phosphorylase from skeletal muscle is much greater than the \(V_{\max }\) of the same enzyme from liver tissue. a. What is the physiological function of glycogen phosphorylase in skeletal muscle? In liver tissue? b. Why does the \(V_{\max }\) of the muscle enzyme need to be greater than that of the liver enzyme?

Short Answer

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Glycogen phosphorylase in muscles meets immediate energy needs during activity, while in the liver, it maintains blood glucose levels. Higher muscle enzyme V_{max} allows for quick energy release.

Step by step solution

01

Understanding Glycogen Phosphorylase

Glycogen phosphorylase is an enzyme that catalyzes the breakdown of glycogen into glucose-1-phosphate, which is crucial for energy production in muscles and for maintaining blood glucose levels in the liver.
02

Physiological Function in Skeletal Muscle

In skeletal muscle, glycogen phosphorylase provides a rapid source of glucose for ATP production, supporting immediate energy demands during physical activity or exercise.
03

Physiological Function in Liver Tissue

In the liver, glycogen phosphorylase helps to maintain blood glucose levels by releasing glucose into the bloodstream during fasting or between meals.
04

Importance of Higher Vmax in Muscle

The higher V_{max} in skeletal muscle reflects the need for a rapid response to energy demands, allowing for quick conversion of glycogen to glucose to support intense muscular activity. In contrast, the liver's function in maintaining steady glucose levels is less immediate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Glycogen Phosphorylase
Glycogen phosphorylase is an essential enzyme involved in the breakdown of glycogen, a stored form of glucose, into glucose-1-phosphate. This process is crucial because it releases glucose units that can be further processed to create energy within the body. Glycogen phosphorylase works by cleaving glucose molecules from glycogen chains, which is vital in both skeletal muscle and liver tissues, although serving different physiological roles in each.
Understanding how this enzyme operates can provide insights into energy management and regulation within our cells. Its role is not just important for energy production, but also for ensuring that glucose levels are efficiently managed in the body.
Skeletal Muscle
Skeletal muscle relies heavily on glycogen phosphorylase during bouts of physical activity. Its primary purpose in these muscles is to provide an immediate supply of glucose, which is needed to produce ATP – the energy currency of the cell.
This instant energy generation is particularly important during high-intensity exercises when demands for energy are high.
  • Ensures quick energy conversion.
  • Supports prolonged physical activity.
  • Facilitates fast recovery between short bursts of activity.
The enzyme's activity is therefore finely tuned to meet the rapid energy needs of exercised muscles, reflecting the necessity for a high throughput of glucose production.
Liver Tissue
The liver has a distinct role compared to skeletal muscle when using glycogen phosphorylase. This enzyme in the liver is pivotal in maintaining blood glucose homeostasis. During fasting, between meals, or during sleep, the liver becomes the primary source of glucose for the body.
The controlled breakdown of liver glycogen provides a steady release of glucose into the bloodstream. This process is crucial for organs that depend on glucose as a primary energy source, such as the brain.
  • Manages blood glucose levels.
  • Ensures a continuous supply of energy.
  • Prevents hypoglycemia during prolonged fasting.
Hence, the liver's enzymatic activity is crucial for long-term energy balance rather than the immediate energy needs seen in muscle action.
Vmax
The term \( V_{\max} \) refers to the maximum rate of an enzymatic reaction when the enzyme is saturated with substrate. In the case of glycogen phosphorylase, the higher \( V_{\max} \) in skeletal muscle compared to liver tissue is indicative of the muscle's need for a quick conversion of glycogen to glucose.
This rapid conversion supports swift responses to high energy demands during activity.
  • High \( V_{\max} \) means faster glucose availability.
  • Reflects different energy needs in muscles versus the liver.
  • Indicates enzymatic prioritization of muscle energy requirements during physical exertion.
Meanwhile, the liver does not require such a high \( V_{\max} \) since its role is more about steady and sustained energy provision rather than rapid energy release.
Physiological Function
The physiological functions of glycogen phosphorylase in both skeletal muscle and liver are tailored to meet different energy needs in the body. In skeletal muscle, the enzyme ensures that there is a swift supply of glucose for immediate energy during physical exertion. This is crucial for activities such as sprinting or heavy lifting, where energy demand spikes instantly.
Meanwhile, in the liver, the enzyme's activity helps manage blood glucose levels, ensuring a consistent energy supply during periods without food intake. This balance prevents abrupt changes in blood glucose, safeguarding against conditions like hypoglycemia. By understanding these roles, we appreciate how different tissues have adapted enzymatic activities to support overall metabolic stability and energy efficiency.

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Most popular questions from this chapter

13\. Optimal Glycogen Structure Muscle cells need rapid access to large amounts of glucose during heavy exercise. This glucose is stored in liver and skeletal muscle in polymeric form as particles of glycogen. The typical glycogen \(\beta\)-particle contains about 55,000 glucose residues (see Eig_ 15-2). Meléndez-Hevia, Waddell, and Shelton (1993), explored some theoretical aspects of the structure of glycogen, as described in this problem. a. The cellular concentration of glycogen in liver is about \(0.01 \mu \mathrm{M}\). What cellular concentration of free glucose would be required to store an equivalent amount of glucose? Why would this concentration of free glucose present a problem for the cell? Glucose is released from glycogen by glycogen phosphorylase, an enzyme that can remove glucose molecules, one at a time, from one end of a glycogen chain (see Eig. 15-3). Glycogen chains are branched (see Eig.15-2), and the degree of branching - the number of branches per chain - has a powerful influence on the rate at which glycogen phosphorylase can release glucose. b. Why would a degree of branching that was too low (i.e., below an optimum level) reduce the rate of glucose release? (Hint: Consider the extreme case of no branches in a chain of 55,000 glucose residues.) c. Why would a degree of branching that was too high also reduce the rate of glucose release? (Hint: Think of the physical constraints.) Meléndez-Hevia and colleagues did a series of calculations and found that two branches per chain (see Eig_15-2) was optimal for the constraints described above. This is what is found in glycogen stored in muscle and liver. To determine the optimum number of glucose residues per chain, Meléndez-Hevia and coauthors considered two key parameters that define the structure of a glycogen particle: \(t=\) the number of tiers of glucose chains in a particle (the mole-cule in Eig.15-2 has five tiers); \(g_{c}=\) the number of glucose residues in each chain. The \(y\) set out to find the values of \(t\) and \(g_{c}\) that would maximize three quantities: (1) the amount of glucose stored in the particle \(\left(G_{\mathrm{T}}\right)\) per unit volume; (2) the number of unbranched glucose chains \(\left(C_{A}\right)\) per unit volume (i.e., number of A chains in the outermost tier, readily accessible to glycogen phosphorylase); and (3) the amount of glucose available to phosphorylase in these unbranched chains \(\left(G_{\mathrm{PT}}\right)\). d. Show that \(C_{A}=2^{t-1}\). This is the number of chains available to glycogen phosphorylase before the action of the debranching enzyme. e. Show that \(C_{\mathrm{T}}\), the total number of chains in the particle, is given by \(C_{\mathrm{T}}=2^{t}-1\). For purposes of this calculation, consider the primers to be a single chain. Thus \(G_{\mathrm{T}}=g_{\mathrm{c}}\left(C_{\mathrm{T}}\right)=g_{c}\left(2^{t}-1\right)\), the total number of glucose residues in the particle. f. Glycogen phosphorylase cannot remove glucose from glycogen chains that are shorter than five glucose residues. Show that \(G_{\mathrm{PT}}=\left(g_{e}-4\right)\left(2^{t-1}\right)\). This is the amount of glucose readily available to glycogen phosphorylase.g. Based on the size of a glucose residue and the location of branches, the thickness of one tier of glycogen is \(0.12 g_{\mathrm{c}} \mathrm{nm}+0.35 \mathrm{~nm}\). Show that the volume of a particle, \(V_{5}\), is given by the equation $$ V_{\mathrm{s}}=4 / 3 \pi t^{3}\left(0.12 g_{\mathrm{c}}+0.35\right)^{3} \mathrm{~nm}^{3} $$ Meléndez-Hevia and coauthors then determined the optimum values of \(t\) and \(g_{c}\) - those that gave the maximum value of a quality function, \(f\), that maximizes \(G_{\mathrm{T}}, C_{A}\), and \(G_{P T}\), while minimizing \(V_{8}: f=\frac{G_{\mathrm{T}} C_{\mathrm{A}} G \mathrm{PT}}{V_{8}}\). They found that the optimum value of \(g_{c}\) is independent of \(t .\) h. Choose a value of \(t\) between 5 and 15 and find the optimum value of \(g_{\mathrm{c}}\). How does this compare with the \(g_{e}\) found in liver glycogen (see Egg.15-2)? (Hint: You may find it useful to use a spreadsheet program.)

Hormonal Control of Metabolic Fuel Between your evening meal and breakfast, your blood glucose drops and your liver becomes a net producer rather than consumer of glucose. Describe the hormonal basis for this switch, and explain how the hormonal change triggers glucose production by the liver.

Glycogen as Energy Storage: How Long Can a Game Bird Fly? Since ancient times, people have observed that certain game birds, such as grouse, quail, and pheasants, fatigue easily. The Greek historian Xenophon wrote: "The bustards ... can be caught if one is quick in starting them up, for they will fly only a short distance, like partridges, and soon tire; and their flesh is delicious." The flight muscles of game birds rely almost entirely on the use of glucose 1-phosphate to drive ATP synthesis (Chapter 14). The glucose 1-phosphate derives from the breakdown of stored muscle glycogen, catalyzed by the enzyme glycogen phosphorylase. The rate of ATP production is limited by the rate at which glycogen can be broken down. During a "panic flight," the game bird's rate of glycogen breakdown is quite high, approximately \(120 \mu \mathrm{mol} / \mathrm{min}\) of glucose 1-phosphate produced per gram of fresh tissue. Given that the flight muscles usually contain about \(0.35 \%\) glycogen by weight, calculate how long a game bird can fly. (Assume the average molecular weight of a glucose residue in glycogen is \(162 \mathrm{~g} / \mathrm{mol}\). )

Glycogen Breakdown in Migrating Birds Unlike a rabbit, running all-out for a few moments to escape a predator, migratory birds require energy for extended periods of time. For example, ducks generally fly several thousand miles during their annual migration. The flight muscles of migratory birds have a high oxidative capacity and obtain the necessary ATP through the oxidation of acetyl-CoA (obtained from fats) via the citric acid cycle. Compare the regulation of muscle glycolysis during short-term intense activity, as in a fleeing rabbit, and during extended activity, as in a migrating duck. Why must the regulation in these two settings be different?

Regulation of Glycogen Phosphorylase In muscle tissue, the rate of conversion of glycogen to glucose 6-phosphate is determined by the ratio of phosphorylase \(a\) (active) to phosphorylase \(b\) (less active). Determine what happens to the rate of glycogen breakdown if a broken cell extract of muscle containing glycogen phosphorylase is treated with (a) phosphorylase kinase and ATP (b) PP1 (c) epinephrine.

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