Chapter 5: Problem 10
Treating 2-methyl-1-propanol with methylsulfonyl chloride in base, followed by reaction with pyridinium chlorochromate, and a final step in strong acid, will give an end product of: (A) 2-methyl-1-propanol. (B) 2-methylpropanal. (C) 2-methylpropanoic acid. (D) 2-methyl-1-propane.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.