Chapter 8: Problem 42
Complete and balance each of the following decomposition reactions: (a) \(\mathrm{Li}_{2} \mathrm{CO}_{3}(s) \rightarrow\) (b) \(\mathrm{CdCO}_{3}(s) \rightarrow\)
Short Answer
Expert verified
(a) \( ext{Li}_2 ext{CO}_3(s) \to ext{Li}_2 ext{O}(s) + ext{CO}_2(g)\)
(b) \( ext{CdCO}_3(s) \to ext{CdO}(s) + ext{CO}_2(g)\)
Step by step solution
01
Understand Decomposition Reactions
Decomposition reactions involve a single compound breaking down into two or more simpler substances. Typically, carbonates decompose to form metal oxides and carbon dioxide gas when heated.
02
Decompose Li₂CO₃
Lithium carbonate, \( ext{Li}_2 ext{CO}_3\), decomposes when heated to form lithium oxide and carbon dioxide. The reaction is: \( ext{Li}_2 ext{CO}_3(s)
ightarrow ext{Li}_2 ext{O}(s) + ext{CO}_2(g)\).
03
Balance the Equation for Li₂CO₃
Each element must have the same number of atoms on both sides of the equation. In \( ext{Li}_2 ext{CO}_3(s)
ightarrow ext{Li}_2 ext{O}(s) + ext{CO}_2(g)\), lithium, carbon, and oxygen atoms are already balanced.
04
Decompose CdCO₃
Cadmium carbonate, \( ext{CdCO}_3\), decomposes to form cadmium oxide and carbon dioxide. The reaction is: \( ext{CdCO}_3(s)
ightarrow ext{CdO}(s) + ext{CO}_2(g)\).
05
Balance the Equation for CdCO₃
Ensure that all elements have the same number of atoms on both sides. The equation \( ext{CdCO}_3(s)
ightarrow ext{CdO}(s) + ext{CO}_2(g)\) is already balanced.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Equations
When we talk about chemical equations, we are looking at a way to express a chemical reaction using symbols and formulas. Imagine a recipe that tells you what ingredients are needed and what will be produced. A chemical equation does the same but for chemical reactions. Each part of the equation has a meaning: the left side lists the starting materials, known as reactants, and the right side lists the products, which are the new substances formed during the reaction. So, with the decomposition reactions such as those you're learning about with carbonates, you'll see the carbonate on the left and its decomposed products, typically a metal oxide and carbon dioxide, on the right.
When you read a chemical equation, take note of:
When you read a chemical equation, take note of:
- The reactants and products and how they show what happens during the reaction.
- The physical states (solid, liquid, gas) which may be included in the equation for further clarity.
- Directional arrows, like \( \rightarrow \), indicating the direction of the reaction.
Balancing Equations
Balancing chemical equations is a critical step in understanding reactions and ensuring they follow the law of conservation of mass. This law states that matter cannot be created or destroyed in a chemical reaction. Thus, each atom you start with as a reactant must appear in the same number in the products. Think of it as balancing a seesaw with children of the same weight on each side. It must be equal.
To balance equations:
To balance equations:
- Write down the number of atoms for each element in both the reactants and the products.
- Adjust the coefficients (the numbers in front of compounds) until the number of atoms of each element is equal on both sides of the equation.
- Double-check your work to ensure you haven’t changed a subscript or formula, which can alter the compound itself.
Carbonates Decomposition
Carbonates are compounds that contain carbonate ions \((\mathrm{CO}_3^{2-})\), and they tend to decompose when exposed to heat. This is a classic type of decomposition reaction where you generally end up with a metal oxide and carbon dioxide gas. For example, when lithium carbonate \( (\mathrm{Li}_2 \mathrm{CO}_3) \) decomposes, it splits into lithium oxide \( (\mathrm{Li}_2 \mathrm{O}) \) and carbon dioxide \( (\mathrm{CO}_2) \) gas.
This reaction can be visualized as:
This reaction can be visualized as:
- \[ \mathrm{Li}_2 \mathrm{CO}_3(s) \rightarrow \mathrm{Li}_2 \mathrm{O}(s) + \mathrm{CO}_2(g) \]
- \[ \mathrm{CdCO}_3(s) \rightarrow \mathrm{CdO}(s) + \mathrm{CO}_2(g) \]