Chapter 8: Problem 34
Complete and balance each of the following combination reactions: (a) \(\mathrm{Sr}+\mathrm{O}_{2} \rightarrow\) (b) \(\mathrm{Al}+\mathrm{O}_{2} \rightarrow\)
Short Answer
Expert verified
(a) \(2\mathrm{Sr} + \mathrm{O}_2 \rightarrow 2\mathrm{SrO}\); (b) \(4\mathrm{Al} + 3\mathrm{O}_2 \rightarrow 2\mathrm{Al}_2\mathrm{O}_3\).
Step by step solution
01
Understand the Problem
In combination reactions, two or more reactants combine to form a compound. Here, both reactions involve a metal reacting with oxygen.
02
Determine Reactants and Products for (a)
Strontium (Sr) reacts with oxygen (\(\mathrm{O}_2\)) to form strontium oxide (\(\mathrm{SrO}\)). The reaction starts as: \(\mathrm{Sr} + \mathrm{O}_2 \rightarrow \mathrm{SrO}\).
03
Balance the Reaction for (a)
The unbalanced reaction is \(\mathrm{Sr} + \mathrm{O}_2 \rightarrow \mathrm{SrO}\). To balance it, note that each \(\mathrm{SrO}\) uses one Sr and one O, but \(\mathrm{O}_2\) provides two oxygen atoms. The balanced equation is \(2\mathrm{Sr} + \mathrm{O}_2 \rightarrow 2\mathrm{SrO}\).
04
Determine Reactants and Products for (b)
Aluminum (Al) reacts with oxygen (\(\mathrm{O}_2\)) to form aluminum oxide (\(\mathrm{Al}_2\mathrm{O}_3)\). The reaction starts as: \(\mathrm{Al} + \mathrm{O}_2 \rightarrow \mathrm{Al}_2\mathrm{O}_3)\).
05
Balance the Reaction for (b)
The unbalanced reaction is \(\mathrm{Al} + \mathrm{O}_2 \rightarrow \mathrm{Al}_2\mathrm{O}_3)\). Balancing involves ensuring equal numbers of each type of atom on both sides. The balanced equation is \(4\mathrm{Al} + 3\mathrm{O}_2 \rightarrow 2\mathrm{Al}_2\mathrm{O}_3)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Combination Reactions
Combination reactions are a type of chemical reaction where two or more substances merge to form one single product. In simpler terms, these reactions bring together elements or compounds into a bigger, often more complex compound. This is why they're sometimes referred to as synthesis reactions.
In our exercise, metals are reacting with oxygen to form metal oxides. Specifically:
In our exercise, metals are reacting with oxygen to form metal oxides. Specifically:
- Strontium (Sr) and oxygen (\(\mathrm{O}_2\)) form strontium oxide (\(\mathrm{SrO}\)).
- Aluminum (Al) and oxygen (\(\mathrm{O}_2\)) form aluminum oxide (\(\mathrm{Al}_2\mathrm{O}_3\)).
Chemical Reactions
Chemical reactions transform substances into different substances, involving rearrangements of atoms and the breaking and forming of chemical bonds. They're fundamental processes in chemistry that can be grouped into types like combination, decomposition, single displacement, and double displacement reactions.
In the context of the exercise:
In the context of the exercise:
- The reaction involves metals, strontium and aluminum, reacting with oxygen.
- These are oxidation reactions, forming metal oxides as the products.
Stoichiometry
Stoichiometry is a critical concept for understanding chemical reactions. It involves calculating the proportions of elements and compounds involved in a chemical reaction. It's about keeping balance much like you would with a budget; you must have the same amount coming in as you have going out.
For example, in balancing the reaction of strontium and oxygen to form strontium oxide, we needed to match the number of atoms on both sides:
For example, in balancing the reaction of strontium and oxygen to form strontium oxide, we needed to match the number of atoms on both sides:
- The reaction starts unbalanced as \(\mathrm{Sr} + \mathrm{O}_2 \rightarrow \mathrm{SrO}\)
- By balancing, we ensure two Sr atoms combine with one \(\mathrm{O}_2\) molecule, forming two \(\mathrm{SrO}\) units as \(2 \mathrm{Sr} + \mathrm{O}_2 \rightarrow 2 \mathrm{SrO}\)